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Abstract
Let be a graph. For two disjoint sets of vertices
and
, set
dominates set
if every vertex in
is adjacent to at least one vertex in
. In this paper we introduce the upper domatic number
, which equals the maximum order
of a vertex partition
such that for every
,
, either
dominates
or
dominates
, or both. We study properties of the upper domatic number of a graph, determine bounds on
, and compare
to a related parameter, the transitivity
of
.
1 Introduction
Partitioning the vertex set of a graph into subsets with a specified property is a popular subject in graph theory. Arguably the most famous problem of graph partitioning is graph coloring, where the vertex set is partitioned into independent sets. The minimum order of such a partition is the well-studied chromatic number of a graph. Considering subsets that are dominating sets, Cockayne and Hedetniemi [Citation1] in 1977 defined the domatic number to be the maximum order of a partition of the vertices of a graph into dominating sets.
More formally, a set is a dominating set of a graph
if every vertex in
is adjacent to a vertex in
. The domination number of
, denoted
, is the minimum cardinality of a dominating set of
. A dominating set with cardinality
is a called a
-set of
. Given two disjoint sets of vertices
, we say that
dominates
, denoted
, if every vertex in
is adjacent to, or dominated by, at least one vertex in
. As previously mentioned, the domatic number of a graph
, denoted
, is the maximum order
of a vertex partition
such that for every
,
,
is a dominating set of
. We call a partition
into dominating sets a domatic partition and a domatic partition of order
is called a
-partition of
. Well over 100 papers have been published on this concept and its variations. The bibliography contains a sampling of these papers. For examples, cf. [Citation2–9].
An equivalent definition of the domatic number is that it equals the maximum order of a vertex partition
such that for all
,
,
and
. This definition of the domatic number suggests the following straightforward generalization. The upper domatic number, denoted
, equals the maximum order
of a vertex partition
such that for all
,
, either
or
, or both. A vertex partition
meeting this condition is called an upper domatic partition and an upper domatic partition of order
is called a
-partition of
.
In 2017, J. T. Hedetniemi and S. T. Hedetniemi [Citation10] gave a different generalization of the domatic number as follows. The transitivity of a graph is the maximum order
of a vertex partition
such that for all
,
,
. A vertex partition of
meeting this condition is called a transitive partition and a transitive partition of
having order
is called a
-partition of
.
By definition, therefore, every domatic partition is both a transitive partition and an upper domatic partition, while every transitive partition is an upper domatic partition. Thus, we have the following basic inequalities for any graph .
Proposition 1
For any graph of order
,
.
Our aim in this paper is to introduce and study the upper domatic number of a graph. We present properties and bounds on , and compare the upper domatic number and transitivity of graphs
.
1.1 Notation and terminology
In general, we follow the notation and terminology in [Citation11]. Let be a graph. The open neighborhood of a vertex
is the set
. Each vertex
is called a neighbor of
, and
is called the degree of
, denoted
. The minimum and maximum degrees of vertices in a graph
are denoted
and
, respectively. The closed neighborhood of a vertex
is the set
. The open neighborhood of a set
of vertices is
, while the closed neighborhood of a set
is the set
. Let
denote the subgraph induced by
in
.
A cycle and path on vertices are denoted by
and
, respectively. The complete graph on
vertices is denoted by
, and its complement, the empty graph on
vertices, is denoted
. A clique is a maximal complete subgraph of
, and the clique number
is the maximum cardinality of a clique of
.
Let be a vertex partition of a graph
. A subset
with
is called a singleton, and a subset
is called a non-singleton.
1.2 Domination digraphs
An equivalent definition of domatic partitions can be given using domination digraphs. Let be a vertex partition of a graph
. From this partition one can construct a directed graph, or digraph,
, the vertices of which correspond one-to-one with the sets
of
, with a directed arc
in
if
dominates
in
, that is,
. We call
the domination digraph of
. Domination digraphs were introduced in 2012 by Goddard et al. [Citation12]. A digraph
is called complete if for any two vertices
, either
or
, or both. A complete digraph is called bi-directed if for any two vertices
and
, both
and
. A complete digraph
is called a tournament if for any two vertices
and
, either
or
, but not both. A tournament
is called transitive if the vertices can be ordered
in such a way that for every
,
if and only if
. A (complete) digraph
of order
is said to be transitive if it contains a transitive tournament of order
as a sub-digraph, that is,
contains a spanning transitive tournament.
A set in a partition
is called a source set if the out-degree of vertex
in its domination digraph
is
. And the set
is a sink set if the in-degree of vertex
in
is
. Note that if
is a transitive partition, then
is a source set and
is a sink set.
Using domination digraphs, we can give equivalent definitions of transitive, domatic, and upper domatic partitions. A vertex partition is transitive if its domination digraph is transitive, and is an upper domatic partition if its domination digraph is complete. The domatic number of a graph is the maximum integer
such that
has a vertex partition
whose domination digraph is a bi-directed complete graph.
2 The upper domatic number
2.1 Basic properties
We begin with some basic properties that will prove useful in the results that follow.
Proposition 2
If is an upper domatic partition of a graph
, then the partition
obtained from
by deleting
and
and adding to
the union
, for any
, is also an upper domatic partition.
Proof
In the vertex partition , we only need to show that for any
,
, either
or
. There are essentially two cases: (i)
and
, or (ii) either
or
or both. For (i),
, and for any of the three possibilities of (ii),
.
Corollary 3
If a graph has an upper domatic partition of order
, then it has an upper domatic partition of order
, for any
.
The following observations are straightforward.
Observation 4
Let be an upper domatic partition of a graph
.
1. | For each | ||||
2. | For each | ||||
3. | If vertices | ||||
4. | If a vertex | ||||
5. | If |
It was shown in [Citation10] that the transitivity of any graph is at least as large as the transitivity of any subgraph of
.
Proposition 5
[Citation10] If is any subgraph of a graph
, then
.
This is not necessarily true for the upper domatic number. To see this, consider the bipartite graph in . Let
be the induced subgraph
, and note that
is an upper domatic partition of
in which
and
is a sink set. Thus,
, and it is straightforward to show that
.
The graph , on the other hand, satisfies
. This follows by observing that since
has an isolated vertex
, any upper domatic partition of
of order
,
, must have a source set
containing vertex
. This means that the set
is a dominating set of
. However, it can be seen that the domination number of
is
, and that the vertices of any dominating set are incident to at least 8 of the 12 edges. Thus, one can check that there is no upper domatic partition of
of order 4 containing such a source set.
The following relaxed form of Proposition 5, however, does hold for the upper domatic number.
Proposition 6
If is any subgraph of a graph
and
has a
-partition with a source set, then
.
Proof
To get an upper domatic partition for , use the
-partition for
and add the vertices in
to the source set in the
-partition for
.
Corollary 7
For any graph ,
.
We note that the bound of Corollary 7 is sharp for complete graphs , for which
. On the other hand, the difference
can be arbitrarily large; for complete bipartite graphs
,
. Note that an upper domatic partition of order
can be formed by placing one vertex from each partite set into singleton sets and adding
dominating sets containing one vertex from each partite set.
2.2 Small values of the upper domatic number
In this section we characterize the families of graphs having upper domatic number equal to
,
, or at least
. A star is a tree having at most one vertex of degree greater than one. A galaxy is a disjoint union of stars.
Theorem 8
For any graph ,
(1) if and only if
contains either a
or a
,
(2) if and only if
is a galaxy with at least one edge, and
(3) if and only if
.
Proof
(1) Assume that contains a triangle or a
subgraph. Each of these subgraphs has upper domatic number 3 and a
-partition with a source set. Thus, Proposition 6 implies that
.
Conversely, assume that . Let
be an upper domatic partition of
. Consider only
,
, and
. Since
is an upper domatic partition, it follows that either
or
, or both, for every
. From this we can assume either (i) the existence of a cyclic triple, where, without loss of generality,
,
and
, or (ii) the existence of a transitive triple, where
,
, and
.
If (i) holds, let be an arbitrary vertex in
. Since
, there must be a vertex
, which is adjacent to
. Similarly, since
, there must be a vertex
which is adjacent to vertex
. Finally, since
, there must be a vertex
which is adjacent to
. If
, then
has a triangle
, but if
, then
has a
subgraph
.
If (ii) holds, let . Since
, there must exist a vertex
which is adjacent to
. Since
, there is a vertex
which is adjacent to
. Finally, since
, there is a vertex
, which is adjacent to
. If
, then
forms a triangle in
, but if
, then
is a
subgraph of
.
(2) Let be a galaxy with at least one edge, say
. Then the partition defined by
is an upper domatic partition, and so
. But since
is a galaxy, it does not contain a
or a
. Hence, from (1) we know that
. Thus,
.
Conversely, assume that . Then by definition,
has at least one edge. By (1) we know that
has no triangle and no
subgraph. Any trivial component of
is the star
. Since
has at least one edge,
has at least one nontrivial component. Consider any nontrivial component
of
(if
is connected
), and let
be a vertex of
having maximum degree
. Since
has no triangles,
is an independent set. If
has degree 1, then since
has maximum degree,
is the star
. Assume that
has degree 2 or more. If a neighbor of
, say
, has a neighbor
, then
, where
and
is a
subgraph of
, a contradiction. Hence, every neighbor of
has degree 1, so
is a star, implying that
is a galaxy.
(3) Trivially, . Assume that
. If
, then
has at least one edge, say
. Thus, the partition defined by
is an upper domatic partition, and so,
, a contradiction. Thus,
.
3 Bounds on the upper domatic number
For a set of vertices , let
be the graph formed from
by removing the set
from
.
Proposition 9
If is a graph with order
and
is a
-set of
, then
Proof
Since along with the sets of a
-partition of
is an upper domatic partition of
,
.
By Proposition 1, we have that . Proposition 9 suggests a way of improving this bound for graphs with a
-partition containing a set that is not independent.
Proposition 10
If is a
-partition of
, with
for
, then
.
Proof
Let be a
-partition of
, and let
. Let
and let
be a
-partition of
. We note that
is an upper domatic partition of
. Thus,
.
Corollary 11
If is a graph with
, then every
-partition of
is a partition of the vertices of
into independent dominating sets.
Proof
Let be a
-partition of
, and let
be a set in
that is not independent. Using the notation of Proposition 10,
. Since
is not an independent set, Theorem 8 implies that
. Thus,
.
The following upper bound on the domatic number is well known.
Proposition 12
[Citation1] For any graph ,
.
This bound does not hold for . It is immediately obvious that for any complete graph
, the domatic number
. Consider, however, the graph
formed by adding a new vertex
adjacent to exactly one vertex, say
, of a complete graph
. It is easy to see that
, while
, since a set containing
along with
singleton sets, each containing a vertex of
, is a
-partition of
. Thus, for
,
, and we see that a significant difference can exist between the domatic number and the upper domatic number. With this example, we have proved the following.
Proposition 13
For any positive integer , there is a graph
such that
, and such that
Although the bound involving minimum degree in Proposition 12 does not hold for the upper domatic number, we show that replacing minimum degree with maximum degree is an upper bound for .
Theorem 14
For any graph ,
.
Proof
Let be a
-partition of
ordered in such a way, that
for
. We claim there is at least one vertex
with
. By Observation 4, it follows there must be at least
edges between each of the sets
and
, for
. Hence, the sum of the degrees of the vertices in
is at least
, and therefore, the average degree of the vertices in this set is at least
. Hence,
.
It is shown in [Citation1] that . Our Nordhaus–Gaddum type bounds for the upper domatic number follow from Theorem 14.
Corollary 15
Let be a graph of order
. Then
Proof
Theorem 14 implies that . The result follows since
.
We note that the bound of Corollary 15 is obtained by the self-complementary graph for which
. It is also obtained the complete graph.
Corollary 16
If is a regular graph, then
.
An upper bound on the sum of the upper domatic number and the domination number of a graph also follows from Theorem 14. It is a well-known result (see Citation11]) that for graphs with order ,
.
Corollary 17
If is a graph with order
, then
The following proposition was given in [Citation10].
Proposition 18
[Citation10] For any connected graph with
,
.
Since , we have the following corollary.
Corollary 19
For any connected graph with
,
.
Based on Corollary 19, one might think that for any graph ,
. However, this is not the case. The following examples show that
is possible. Indeed, the difference
can be arbitrarily large.
For integers and
, let
be the complete multipartite graph with
partite sets each having cardinality
. That is,
with
partite sets.
Proposition 20
For the graph with
even,
.
Proof
Let the partite sets be and let
for
. Note that for any
,
and conversely,
. Moreover, every two-element subset containing elements from different partite sets is a dominating set of
. That is, the partition
is an upper domatic partition. Thus, it follows that for this graph,
.
To see that , observe that any upper domatic partition of order larger than
has at least
singleton sets. But then at least two of these singleton sets are vertices in the same partite set and are not adjacent, contradicting Observation 4.
It follows from Proposition 20 that there exists a graph for which
, and there is a graph
for which
. For examples, the graph
has
, and the graph
has
.
4 Upper domatic number versus transitivity
In this section, we first consider graphs having equal transitivity and upper domatic number. We then turn our attention to the differences in these two parameters.
By considering Theorem 8 together with the following two results proven in [Citation10], we see that graphs satisfying
have equal upper domatic and transitivity numbers.
Theorem 21
[Citation10] Let be a graph.
1. |
| ||||
2. |
|
Proposition 22
[Citation10] For any graph ,
if and only if
contains either a triangle or a
subgraph (not necessarily induced).
We now consider other examples of graph families having this property. Recall that and
denote the path and cycle, of order
, respectively. The Cartesian product
of two graphs
and
is the graph with vertex set
and edges such that two vertices
and
are adjacent in
if and only if either
and
is adjacent to
in
, or
is adjacent to
in
and
. The class of graphs called
-cubes is defined recursively as follows. The
-cube, denoted
, is the graph
. The
-cube
is the graph
.
Using the fact that (Theorem 14) and proofs similar to those in [13,10], we can easily prove the following.
Theorem 23
1. | For the path | ||||
2. | For the cycle | ||||
3. | For any cubic graph | ||||
4. | For | ||||
5. | For | ||||
6. | For any positive integer |
Theorem 23 gives several families of graphs having equal transitivity and upper domatic numbers. Acyclic graphs are another family with this property.
Theorem 24
If is acyclic, then
.
Proof
Let be any acyclic graph, and let
be an upper domatic partition of cardinality
for
. We show that the sets in
can be reordered
, so that for
,
dominates
. We first show that
contains a source set. Let
be a tree in
rooted at
. We consider two cases:
Case (i). Let . For Case (i), if
is a child of
, then either
or
dominates the set of
containing
. Thus,
dominates all the sets of
containing vertices in
. Suppose there is some set
that is not dominated by
. Then no child of
is in
, implying that
does not dominate
, contradicting that
is an upper domatic partition of
. Hence,
is a source set in
, and we can let
.
Case (ii). If Case (i) does not hold, let be a vertex of maximum depth in
, such that parent(
)’s set, say
, is different from the set
containing
and
does not dominate
. Since Case (i) does not hold, at least one child of
has this property, so the vertex
exists. Moreover, since
is an upper domatic partition,
. Also note by the choice of
, if
has a child, it is either in
or
dominates the child’s set. Again, if there is a set say
such that
does not dominate
, then
has no vertex in
. But then
does not dominate
and
does not dominate
, contradicting that
is an upper domatic partition. Thus,
is a source set in
.
Therefore, there exists a source set in . We let this set be the first set
in a reordered
. We can create a new acyclic graph
. The partition
will be an upper domatic partition for
. By repeating the above process, we can find the next set in the ordering of
, and after
iterations the entire ordering.
We have seen several examples where the inequality is tight. On the other hand, strict inequality is possible. For example, the graph
in has
. To see that
, we note that
is an upper domatic partition, so
, and Theorem 14 implies that
. It can be verified by a straightforward, but detailed proof or by a computer search that
is a graph with the fewest vertices having transitivity strictly less than its upper domatic number. Similarly, it can be proved that the bipartite graph
in , for which
, is a graph with the fewest edges having this property. We note that Propositions 22 and 25 imply that
. From Theorem 14,
. The partition
is an upper domatic partition, and so,
.
We next show that the difference between and
can be made arbitrarily large. We will need the following result from [Citation10].
Proposition 25
[Citation10] If is a graph with
, then there exist two adjacent vertices in
, each having degree
or more.
Theorem 26
There exists a graph for which
differ by at least
, for any positive integer
.
Proof
Let for some positive integer
. We construct a bipartite graph
with
vertices and
edges as follows.
Let . For
, let
and
.
For , add edges such that
is adjacent to every vertex in
where
is the sum
modulo
for
. Finally, add the edges
such that
. Now
is a bipartite graph with partite sets
and
for
, where each vertex in
has degree
and each vertex in
has degree
.
We note that the partition is an upper domatic partition, so
. On the other hand, since every edge of
is incident to a vertex in
with degree
, Proposition 25 implies that
, and so,
.
5 Concluding remarks
We conclude by noting another difference in the transitivity number and the upper domatic number of a graph that leads us to making a conjecture. As we saw in Section 1.2, every transitive partition has at least one source set and at least one sink set. In fact, it was observed in [Citation10] that a graph
will always have a
-partition with at least two sink sets. Upper domatic partitions, on the other hand, do not necessarily behave similarly.
For example, consider the graph from . This graph has no
-partition with a source set. If
had a
-partition with a source set
, then as in the proof of Proposition 29 , in the graph
,
would be an upper domatic partition. But if
, then
as well. This would imply that a transitive partition of
of order four could be constructed, a contradiction. Additionally, the graph
in has no
-partition with two sink sets. To see this, note that the graph
has
. Thus, if
had a
-partition with two sink sets, then the partition would also be transitive, again a contradiction.
The question arises whether there are graphs with no -partitions with a sink set. Unfortunately, we have neither found such a graph nor proven that one does not exist.
Conjecture 1
There exists a graph such that no
-partition of
contains a sink set.
Our next results show that if Conjecture 1 is true for a graph , then
.
Proposition 27
If has a
-partition
of order
that contains a set that is dominated by
sets, then
has a
-partition
containing a sink set.
Proof
Let be an upper domatic partition that contains a set
that is dominated by
sets. If
does not have a sink set, consider the set
that is dominated by
. Let
be a vertex in
that dominates a vertex in
. Let
. Then
is a
-partition of
with the sink set
(cf. Proposition 2).
Corollary 28
If , then there exists a
-partition that contains a sink set.
Proof
It follows from previous results that if , then
, and there is a Tr-partition
that is a
-partition. Thus,
has a sink set. Hence, assume that
. Let
be a
-partition for
, and consider the domination digraph for
. There are four vertices and at least six arcs in this digraph, so some vertex must have in-degree at least
. By Proposition 27, the result holds.
We also note that if Conjecture 1 holds, the following is true.
Proposition 29
If there exist graphs that have no D-partitions containing a sink set, then there exist graphs that have no D-partitions containing either a sink set or a source set.
Proof
Let be a graph for which
, and
has no
-partition containing a sink set. Assume that
is the minimum integer for which a graph
exists for which
and
has no
-partitions containing a sink set. Let
be a
-partition of
, where, by assumption,
is not a sink set, and assume that
is a source set. This means that
is a dominating set of
. Then
is an upper domatic partition of order
of the graph
.
First, we claim that . From the upper domatic partition
, we know that
. Suppose
. Let
be a
-partition of
, where
. Then it follows that
is an upper domatic partition of
of order greater than
; a contradiction. Thus,
.
Now suppose that has a
-partition
in which
is a sink. Then
is a
-partition of
containing a sink; a contradiction.
Thus, has no
-partition containing a sink, but
, which contradicts our assumption that
is the minimum integer for which a graph
exists having
and no
-partitions containing a sink set.
Thus, it follows that has no
-partitions containing either a sink set or a source set.
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