An error was detected in “Generalized Group Algebras of Locally Compact Groups,” Communications in Algebra 36(9):3559–3563 (2008).
It has been brought to our attention that Lemma 9 of [Citation1] is incorrect. Lemma 9 is used only in the proof of Proposition 10, but Proposition 10 is used in some of the results that follow it. We withdraw Lemma 9 and give here a new proof of Proposition 10, which is independent of the incorrect Lemma 9 and thus reinforce the correctness of all other results in [Citation1].
Proposition 10 ([Citation1])
If RG is right continuous, then R is right continuous.
Proof
By Lemma 8 [Citation1], R is right quasi-continuous. To prove that R is right continuous, we only need to show that every right ideal of R isomorphic to a direct summand of R is itself a direct summand of R. Let I be a right ideal isomorphic to eR for some e = e
2 ∈ R. Let σ: I → eR be a right R-module isomorphism. Then ϕ: IG → eRG given by for a
g
∈ I and g ∈ G, is a right RG-module isomorphism. But since RG is right continuous, we have IG = fRG for some f = f
2 ∈ RG. Suppose
. Put
. Define ψ: RG → R by
. Then ψ(f) = m and m
2 = ψ(f)ψ(f) = ψ(f
2) = ψ(f) = m. Thus m is an idempotent in R. Now, I = ψ(IG) = ψ(fRG) = ψ(f)ψ(RG) = mR. This shows that I is a direct summand of R. Therefore, R is right continuous.
In view of the above, the main theorem of [Citation1] for generalized group algebras still holds true.
Theorem 11 ([Citation1])
If L 1(G, A) is right continuous then G is finite and A is right continuous.
ACKNOWLEDGMENT
We would like to thank Evrim Akalan for pointing out the error.
REFERENCES
- Jain , S. K. , Singh , A. I. , Srivastava , A. K. ( 2008 ). Generalized group algebras of locally compact groups . Comm. Algebra 36 : 3559 – 3563 .