320
Views
21
CrossRef citations to date
0
Altmetric
Original Articles

Second Modules Over Noncommutative Rings

, &
Pages 83-98 | Received 09 Feb 2011, Published online: 04 Jan 2013
 

Abstract

Let R be an arbitrary ring. A nonzero unital right R-module M is called a second module if M and all its nonzero homomorphic images have the same annihilator in R. It is proved that if R is a ring such that R/P is a left bounded left Goldie ring for every prime ideal P of R, then a right R-module M is a second module if and only if Q = ann R (M) is a prime ideal of R and M is a divisible right (R/Q)-module. If a ring R satisfies the ascending chain condition on two-sided ideals, then every nonzero R-module has a nonzero homomorphic image which is a second module. Every nonzero Artinian module contains second submodules and there are only a finite number of maximal members in the collection of second submodules. If R is a ring and M is a nonzero right R-module such that M contains a proper submodule N with M/N a second module and M has finite hollow dimension n, for some positive integer n, then there exist a positive integer k ≤ n and prime ideals P i  (1 ≤ i ≤ k) such that if L is a proper submodule of M with M/L a second module, then M/L has annihilator P i for some 1 ≤ i ≤ k. Every second submodule of an Artinian module is a finite sum of hollow second submodules.

2000 Mathematics Subject Classification:

ACKNOWLEDGMENT

The first and second authors were supported by the Scientific Research Project Administration of Akdeniz University. We thank the referee for careful reading of the manuscript.

Notes

Communicated by T. Albu.

Reprints and Corporate Permissions

Please note: Selecting permissions does not provide access to the full text of the article, please see our help page How do I view content?

To request a reprint or corporate permissions for this article, please click on the relevant link below:

Academic Permissions

Please note: Selecting permissions does not provide access to the full text of the article, please see our help page How do I view content?

Obtain permissions instantly via Rightslink by clicking on the button below:

If you are unable to obtain permissions via Rightslink, please complete and submit this Permissions form. For more information, please visit our Permissions help page.