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Psychology

The role of self-regulatory efficacy, moral disengagement and guilt on doping likelihood: A social cognitive theory perspective

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Pages 578-584 | Accepted 20 Apr 2017, Published online: 08 May 2017
 

ABSTRACT

Given the concern over doping in sport, researchers have begun to explore the role played by self-regulatory processes in the decision whether to use banned performance-enhancing substances. Grounded on Bandura’s (1991) theory of moral thought and action, this study examined the role of self-regulatory efficacy, moral disengagement and anticipated guilt on the likelihood to use a banned substance among college athletes. Doping self-regulatory efficacy was associated with doping likelihood both directly (b = −.16, P < .001) and indirectly (b = −.29, P < .001) through doping moral disengagement. Moral disengagement also contributed directly to higher doping likelihood and lower anticipated guilt about doping, which was associated with higher doping likelihood. Overall, the present findings provide evidence to support a model of doping based on Bandura’s social cognitive theory of moral thought and action, in which self-regulatory efficacy influences the likelihood to use banned performance-enhancing substances both directly and indirectly via moral disengagement.

Disclosure statement

No potential conflict of interest was reported by the authors.

Notes

1 We used PROCESS to examine the direct effects of moral disengagement on doping likelihood, moral disengagement on guilt, and guilt on doping likelihood, as well as the indirect effect of moral disengagement on doping likelihood via guilt. These regressions indicated significant direct effects of moral disengagement on doping likelihood, b = 0.45, 95% CI = 0.30, 0.59; moral disengagement on guilt, b = −0.68, 95% CI = −0.83, −0.53; and guilt on doping likelihood, b = −0.16, 95% CI = −0.27, −0.05. Further, moral disengagement had a significant indirect effect on doping likelihood mediated via guilt, b = 0.11, 95% CI = 0.01, 0.22; CSIE = .10, 95% CI = .01, .20.

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