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Articles

Broadcast domination of lexicographic and modular products of graphs

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Pages 177-181 | Received 28 Mar 2022, Accepted 18 Jun 2022, Published online: 04 Jul 2022

Abstract

A dominating broadcast labeling of a graph G is a function f:V(G){0,1,2,,diam(G)} such that f(v)e(v) for all vV(G), where e(v) is the eccentricity of v, and for every vertex uV(G), there exists a vertex v with f(v)1 and d(u,v)f(v). The cost of f is vV(G)f(v). The minimum of costs over all the dominating broadcast labelings of G is called the broadcast domination number γb(G) of G. In this paper, we give bounds to the broadcast domination number of lexicographic product GH of a connected graph G and a graph H, and we show that the bounds are tight by determining the exact values for lexicographic products of some classes of graphs. Also, we give an algorithm which produces a dominating broadcast labeling of GH. We use the algorithm to find γb(PmH) and γb(CmH). Further, we give an upper bound for the broadcast domination number of the modular product of two connected graphs and exact values are determined for the modular product of two graphs involving path, cycle and complete graphs.

2010 MATHEMATICS SUBJECT CLASSIFICATION::

1. Introduction

A radio station wishes to install broadcasting towers of varying capacities in different sections/locations of a region so that the whole region can hear their broadcast. A broadcasting tower of larger capacity broadcasts further but attracts more cost. So, it is an obvious target to install towers, tactically, of appropriate capacities in order to minimize the total cost. This lead to the concept of broadcast domination in a graph. The situation was modeled as a graph whose vertices are different sections/locations of the region and two vertices are adjacent if those two corresponding sections/locations are close enough. Erwin [Citation4] has introduced the concept of broadcast domination.

A broadcast labeling of a graph G is a function f:V(G){0,1,2,,diam(G)} such that f(v)e(v) for all v V(G), where e(v) is the eccentricity of v. The cost of f is vV(G)f(v) and is denoted by σ(f). A vertex v is a broadcast vertex if f(v)1 and the set of all broadcast vertices is denoted by Vf+(G) or simply Vf+. A vertex uV(G) is said to be f-dominated if there exists a vertex vVf+ such that d(u,v)f(v). It is clear that a broadcast vertex f-dominates itself. For each vertex vVf+, the closed f-neighborhood Nf[v] of v is the set {uV(G):d(u,v)f(v)}. A broadcast labeling f is said to be a dominating broadcast labeling if vVf+Nf[v]=V(G) and the broadcast domination number γb(G) of G is defined as min{σ(f):f is a dominatingbroadcast labeling of G}. A dominating broadcast labeling f is said to be an optimal dominating broadcast labeling if σ(f)=γb(G). A dominating broadcast labeling f is said to be an efficient dominating broadcast labeling if every vertex is f-dominated by exactly one broadcast vertex. From now onwards, we use DBL and ODBL in place of dominating broadcast labeling and optimal dominating broadcast labeling, respectively.

For any two graphs G and H, there are four standard graph products, namely, Cartesian product GH, direct product G × H, strong product GH and lexicographic product GH. The vertex set of each of the products is V(G)×V(H) and the edge sets are defined as follows.

  1. (u,v)(u,v)E(GH) if uuE(G) and v=v, or u=u and vvE(H).

  2. (u,v)(u,v)E(G×H) if uuE(G) and vvE(H).

  3. E(GH)=E(GH)E(G×H).

  4. (u,v)(u,v)E(GH) if uuE(G), or u=u and vvE(H).

The broadcast domination for the first three products is studied in [Citation1, Citation3, Citation7, Citation10, Citation11]. In this paper, we explore the broadcast domination of the lexicographic product and the modular product, where the latter one is closely related to the standard products. For the modular product GH of G and H, the vertex set is V(G)×V(H) and the edge set E(GH)=E(GH)E(G×H)E(G¯×H¯). The lexicographic product and the modular product of P3 and P4 are given in and , respectively. It is evident that, among all the mentioned products, only the lexicographic product is non-commutative.

Figure 1. Lexicographic product of P3 and P4.

Figure 1. Lexicographic product of P3 and P4.

Figure 2. Modular product of P3 and P4.

Figure 2. Modular product of P3 and P4.

1.1. Literature survey

Erwin [Citation4] has given tight bounds for the broadcast domination number of any graph.

Theorem 1.1

([Citation4]). For a non-trivial connected graph G, diam(G)+13γb(G)min{rad(G),γ(G)}.

Dunbar et al. [Citation3] have proved that every graph has an efficient ODBL. So, whenever required, we consider an efficient ODBL without citing the theorem below.

Theorem 1.2

([Citation3]). Every graph G has an efficient optimal dominating broadcast labeling.

In light of the upper bound given in Theorem 1.1, Dunbar et al. [Citation3] have proposed the following classification of graphs and the relevant studies can be found in [Citation2, Citation4–6, Citation8, Citation9]. A graph G is said to be Type I or radial graph (Type II or 1-cap graph) if γb(G)=rad(G) (γb(G)=γ(G)). If γb(G)<min {rad(G),γ(G)}, then G is a Type III graph.

Erwin [Citation4] has shown that γb(Pn)=n3=γb(Cn). Brešar and Špacapan [Citation1] have given sharp upper bounds for the broadcast domination numbers of GH,GH and G × H, for any two connected graphs G and H, in terms of γb(G) and γb(H). The broadcast domination numbers of some products of graphs involving Pn,Cn,Kn and K1,n are given in [Citation3, Citation7, Citation10, Citation11].

Theorem 1.3

([Citation1]). For any two connected graphs G and H, γb(GH)32(γb(G)+γb(H)).γb(GH)32max{γb(G),γb(H)}.γb(G×H){3max{γb(G),γb(H)}if rad(G)rad(H),3max{γb(G),γb(H)}+1if rad(G)=rad(H).

Theorem 1.4

([Citation3]). For any pair of integers m2 and n2,γb(PmPn)=rad(PmPn)=m2+n2.

Theorem 1.5

([Citation11]). For paths Pm and Pn, γb(PmPn)=12(mmmax{p,3}), where p=2n12+1.γb(Pm×Pn)={mif n=1,n(m+1n+1)if n2, m,n both odd with m+1n+1 integer,2mmn+12otherwise. γb(Pm Pn)={max{m3,n3}if m=1 or n{1,2,3}, max{2m5,2}if m2 and n4.

Theorem 1.6

([Citation7]). For any two positive integers m3 and n3, γb(PmK1,n)=γb(CmK1,n)=γb(PmKn)=γb(CmKn)=m+12andγb(CmPn)={m2if n=2 and m is even,m2+n2otherwise.

Theorem 1.7

([Citation10]). For any two positive integers m3 and n3,γb(CmCn)=m+n21.

In this paper, first, we give upper and lower bounds to the broadcast domination number of lexicographic product GH of a connected graph G and a graph H, in terms of γb(G). We find γb(CmKn),γb(PmKn),γb(KnCm),γb(KnPm) and γb(GH), where G is either a hypercube graph or radial graph and H is any graph with γb(H)2. We show that these graphs attain either the lower or the upper bound. Further, we give an algorithm which produces a DBL of GH. We give a lower bound for γb(PmH) and γb(CmH), and prove that the DBL produced by the algorithm achieves the lower bound. Later, we show that γb(GH) is at most 3 for any two connected non-complete graphs G and H, and prove that γb(KmH)=γb(H). Also, we determine the exact values of the broadcast domination numbers of the modular products of graphs involving Pn, Cn and Kn. All the graphs considered in this article are simple and non-trivial.

2. Lexicographic product

We denote the vertex (ui,vj) of the product as xi,j. There are |V(G)| number of copies of H, the copy corresponding to the vertex ui is Hi, and the vertex xi,j belongs to Hi.

Theorem 2.1.

For any connected graph G and a graph H, γb(G)γb(G H)γb(G)+min{|{uVf+(G):f(u)=1}|: f is an optimal dominating broadcast labeling of G}.

Proof.

Let f be an ODBL of GH. Now, we define a broadcast labeling g of G as g(ui)=maxj f(xi,j).

Then, g is a DBL of G with σ(g)γb(GH) and we get the first inequality.

Let f be an ODBL of G. Then, the broadcast labeling g of GH defined as g(xi,j)={f(ui)+1if f(ui)=1 and j=1,f(ui)if f(ui)2 and j=1,0otherwise, is a DBL of GH with σ(g)=γb(G)+|{uVf+(G):f(u)=1}|. Hence, we have the second inequality.□

Corollary 2.2.

Let G be a connected graph and H be any graph. If G has an optimal dominating broadcast labeling in which each broadcast vertex receives cost more than 1, then γb(G H)=γb(G).

Proposition 2.3.

Let G be a connected graph and H be any graph with γb(H)=1. Then γb(G H)=γb(G).

Proof.

Let f be an ODBL of G and vt be a central vertex of H. Then, the broadcast g defined as g(xi,j)={f(ui)if j=t,0otherwise, is a DBL of GH of cost γb(G). Hence, the result follows from Theorem 2.1.□

Remark 2.4.

Corollary 2.2 and Proposition 2.3 allow us to construct a bigger Type I graph (i.e. GH) from a given Type I graph (i.e. G). Also using Proposition 2.3, one can construct a bigger Type II/Type III graph (i.e. GH) from a given Type II/Type III graph (i.e. G), respectively.

The lemma below shows that the cost of every broadcast vertex corresponding to an efficient ODBL of GH with γb(H)2 is at least 2.

Lemma 2.5.

Let f be an efficient optimal dominating broadcast labeling of G • H, where G is a connected graph and H is any graph with γb(H)2. Then f(xi,j)2 for every xi,jVf+.

Proof.

Let f be an efficient ODBL of GH and xi,j be a broadcast vertex with f(xi,j)=1. Since γb(H)2,xi,j does not f-dominate whole of Hi. Therefore, there exists a broadcast vertex xi,j which f-dominates other vertices of Hi. Now, Nf[xi,j]Nf[xi,j], which is a contradiction.□

Proposition 2.6.

Let G be a connected graph and H be any graph. If every optimal dominating broadcast labeling of G has exactly one broadcast vertex of cost 1 and γb(H)2, then γb(G H)=γb(G)+1.

Proof.

Let f be an efficient ODBL of GH. By Lemma 2.5, f(xi,j)2 for every xi,jVf+(GH). If γb(GH)=γb(G), then the broadcast g, as defined in Theorem 2.1, gives an ODBL of G in which cost of every broadcast vertex is more than 1, which is a contradiction. Therefore, by Theorem 2.1, γb(GH)=γb(G)+1.

It is evident that the lexicographic product of two complete graphs is again a complete graph and therefore γb(KmKn)=1. In the theorems below, we determine the exact values of γb(CmKn),γb(PmKn),γb(KnCm) and γb(KnPm). Further, we give the broadcast domination numbers of lexicographic product of two connected graphs G and H, where G is either a hypercube graph or a Type I graph, and H is an arbitrary graph with γb(H)2. All of these values justify the tightness of the bounds given in Theorem 2.1.

Theorem 2.7.

For any integer m4,

  1. γb(Cm Kn)=m3.

  2. γb(Pm Kn)=m3.

  3. γb(Kn Cm)=2.

  4. γb(Kn Pm)=2.

Proof.

The proofs of (a) and (b) are obvious by Proposition 2.3. The proofs of (c) and (d) are evident from Proposition 2.6.□

For hypercube Qn, Brešar and Špacapan [Citation1] have determined that γb(Qn)={nfor n=1 and 2,n1for n3, by defining an ODBL of Qn, n3, which assigns value nk1 and k, for 1kn2, to two of its antipodal vertices u and v, and zero to all the other vertices. Then the following theorem is obvious from Corollary 2.2.

Theorem 2.8.

If G is either a hypercube graph Qn(n5) or a Type I graph, and H be any arbitrary graph with γb(H)2, then γb(G H)=γb(G).

Theorem 2.1 gives an upper bound of γb(GH) in terms of γb(G). In the proof of Theorem 2.1, starting from an ODBL of G, we get a DBL of GH. Now, we provide an algorithm which gives a DBL of GH, without any help of a DBL of G. The algorithm chooses vertices from the vertex set of G and gives cost to a vertex on each corresponding copy of H in GH. Later, we determine γb(PmH) and γb(CmH) in the process of which we use the algorithm to obtain the upper bounds.

Algorithm 2.9.

  1. Starting from any arbitrary vertex u of G, consider the set D=(iLi){u}, where Li={xV(G):dG(u,x)=5i,i=1,2,3,}.

  2. Define a broadcast f of G • H which assigns 2 to every vertex (x,v)D×{v}, where v is an arbitrarily fixed vertex of H, and zero to all the other vertices of G • H.

  3. If (x,v)D×{v}(Nf[(x,v)])V(G H), consider the set X={yV(G):(y,z)V(G H)(x,v)D×{v}Nf[(x,v)]}.

  4. Consider D=iLi, where Li={xX:dG(u,x)=5i2,i=1,2,3,}.

  5. Modify the broadcast f for the vertices of D×{v} by replacing the cost 0 by 2.

Theorem 2.10.

Algorithm Citation2.Citation9 produces a DBL of G • H.

Now, we find γb(PmH) and γb(CmH) where H is any graph with γb(H)2. We consider the following observation due to Soh and Koh [Citation11] which we use in Lemma 2.12.

Observation 2.11

([Citation11]). Let f be a broadcast labeling of Pm • Pn, where m3 and n4. Let B={xi,1:1im} and T={xi,n:1im}. Then, for any UVf+, the number of f-dominated vertices in BT is at most 5uUf(u).

Lemma 2.12.

Let f be a broadcast labeling of G • H where G is either a path graph or a cycle graph, of order m3, and H be any graph with γb(H)2. Let vr and vs be two vertices in H such that d(vr,vs)>2, and B1={xi,r:1im} and B2={xi,s:1im}. Then, for any UVf+, the number of f-dominated vertices in B1B2 is at most 5uUf(u).

Proof.

Let xi,j be a broadcast vertex. If f(xi,j)=1, then the broadcast f-dominates at most 5 vertices of B1B2. If f(xi,j)2, then |Nf[xi,j](B1B2)|2(2f(xi,j)+1)5f(xi,j).

Theorem 2.13.

If G is either a path graph or a cycle graph, of order m3, and H is an arbitrary graph with γb(H)2, then γb(G H)=2m5.

Proof.

Let G be a path Pm: u1u2u3um and f be an ODBL of PmH. Then, by Lemma 2.12, we have γb(PmH)2m5. Now, applying Algorithm Citation2.Citation9 starting from u3, we get γb(PmH)2m5. Hence, γb(PmH)=2m5. The proof is similar when G is a cycle graph.□

Remark 2.14.

If G is a graph of order n and having Hamiltonian path, then PnH is a spanning subgraph of GH. Hence, by Theorem 2.13, we have γb(GH)γb(PnH)2n5, when γb(H)2.

3. Modular product

In this section, we give an upper bound of γb(GH) when none of the graphs G and H is complete and give the exact value of γb(GH) in terms of one of its factors, when exactly one of G and H is a complete graph. Also, we determine the broadcast domination numbers of PmPn,PmCn and CmCn. Before that, we characterize those modular products whose broadcast domination number is 1.

Observation 3.1.

For any two connected graphs G and H, the degree of any vertex (u,v)V(GH) is n(GH)dG¯(u)(dH(v)+1)dH¯(v)(dG(u)+1)1.

Proposition 3.2.

For any two connected graphs G and H, γb(GH)=1 if and only if γb(G)=1 and γb(H)=1.

Proof.

For any two connected graphs G and H, γb(GH)=1 if and only if there exists a vertex (u,v)V(GH) such that dGH((u,v))=n(GH)1. Then by Observation 3.1, we have dG¯(u)(dH(v)+1)+dH¯(v)(dG(u)+1)=0, which holds if and only if dG¯(u)=0 and dH¯(v)=0. Hence, the statement.□

Now, to give an upper bound, we prove that the radius of the modular product of two connected non-complete graphs is at most 3.

Lemma 3.3.

If G and H are two connected non-complete graphs, then rad(GH)3.

Proof.

We prove that dGH((u1,v1),(u2,v2))3 for any two vertices (u1,v1),(u2,v2)V(GH). The vertices (u1,v1) and (u2,v2) are non-adjacent only in the following cases.

Case 1: u1=u2 and v1v2.

As G is connected and non-complete, there exists an induced path P3 containing u1. Let w1 and w2 be the other two vertices in that path. There are two possibilities for the path: u1w1w2 or w1u1w2. If u1w1w2 is the path, then we have the path below. (1) (u1,v1)(w2,v2)(w1,v2)(u2,v2)(1)

If w1u1w2 is the path, then we have the following path. (2) (u1,v1)(w1,v1)(w2,v2)(u2,v2)(2)

Case 2: u1u2 and v1v2.

Since G is connected and non-complete, G has an induced path P3 containing u1. There are four possibilities for the path P3: u1u2w or u2u1w or u1w1w2 or w1u1w2. If u1u2w is the path, we have (u1,v1)(w,v2)(u2,v2). If u2u1w is the path, then we have (u1,v1)(w,v1)(u2,v2). For the other two possibilities, the paths (1) and (2) are (u1,v1)(u2,v2)-paths of length 3.

Case 3: u1u2 and v1=v2.

This case is similar to Case 1.

Case 4: u1u2 and v1v2.

This case is similar to Case 2.

Therefore, we have rad(GH)3.

The proof of the following theorem is evident from Lemma 3.3 and Theorem 1.1.

Theorem 3.4.

For any two connected non-complete graphs G and H, γb(GH)3.

Since KmKn is again a complete graph, we have γb(KmKn)=1. If exactly one of G and H is a complete graph, then E(G¯×H¯)=ϕ. Therefore, in this case, GHGH and hence γb(GH)=γb(GH). Using this observation, we prove the next result.

Theorem 3.5.

For any connected graph H, γb(KmH)=γb(H).

Proof.

It is easy to see that for any pair of vertices (u1,v1),(u2,v2)V(Km)×V(H),dKmH((u1,v1),(u2,v2))=dH(v1,v2). So, from any ODBL of H we can have a DBL of KmH of same cost, and from any ODBL of KmH we can have a DBL of H of same cost. Therefore γb(KmH)=γb(H).

Now, we determine the broadcast domination number of PmPn, for m3 and n4.

Proposition 3.6.

For m3 and n4,γb(PmPn)=2.

Proof.

As m3 and n4, by Proposition 3.2, γb(PmPn)2. Let Pm: u1u2u3um and Pn: v1v2v3vn be the two paths. Now, we prove either rad(PmPn)=2 or γ(PmPn)=2. It can be verified easily that e((u1,v1))=2 for m,n7 or (m,n){(3,6),(3,7)}, and e((u1,v3))=2 for m = 3 and n = 4, 5. Again, it is easy to observe that {(u1,v1),(u4,v1)} is a minimum dominating set of P4P7 and {(u2,v1),(u5,v1)} is a minimum dominating set of PmP7 for m = 5, 6.□

As PmPn (m3,n4) is a spanning subgraph of PmCn (m3,n4) and CmCn (m3,n4), the result below is a straight forward from Propositions 3.2 and 3.6.

Proposition 3.7.

For m3 and n4,

  1. γb(PmCn)=2.

  2. γb(CmCn)=2.

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