124
Views
2
CrossRef citations to date
0
Altmetric
Original Articles

Lehmer Pairs Revisited

 

ABSTRACT

We seek to understand how the technical definition of a Lehmer pair can be related to more analytic properties of the Riemann zeta function, particularly the location of the zeros of ζ′(s). Because we are interested in the connection [CitationCsordas et al. 94] between Lehmer pairs and the de Bruijn–Newman constant Λ, we assume the Riemann hypothesis throughout. We define strong Lehmer pairs via an inequality on the derivative of the pre-Schwarzian of Riemann’s function Ξ(t), evaluated at consecutive zeros: Theorem 1 shows that strong Lehmer pairs are Lehmer pairs. Theorem 2 describes PΞ′(γ) in terms of ζ′(ρ) where ρ = 1/2 + iγ. Theorem 3 expresses PΞ′(γ+) + PΞ′(γ) in terms of nearby zeros ρ′ of ζ′(s). We examine 114, 661 pairs of zeros of ζ(s) around height t = 106, finding 855 strong Lehmer pairs. These are compared to the corresponding zeros of ζ′(s) in the same range.

2000 AMS Subject Classification:

Acknowledgments

We would like to thank David Farmer for sharing his computations of zeros of ζ′(s) in the range 106t ≤ 106 + 6 · 104 and the anonymous referee for a careful reading of the manuscript and helpful suggestions.

Notes

1 Red–yellow–green–blue, as one travels around the origin counterclockwise.

2 In [CitationDueñez et al. 10, Section 6], Y is assumed to be 0.

3 And with a slight bias to be negative, since the π/4 term gives Y a slight bias to be positive.

4 It would be desirable to bound the error in making this approximation.

Reprints and Corporate Permissions

Please note: Selecting permissions does not provide access to the full text of the article, please see our help page How do I view content?

To request a reprint or corporate permissions for this article, please click on the relevant link below:

Academic Permissions

Please note: Selecting permissions does not provide access to the full text of the article, please see our help page How do I view content?

Obtain permissions instantly via Rightslink by clicking on the button below:

If you are unable to obtain permissions via Rightslink, please complete and submit this Permissions form. For more information, please visit our Permissions help page.