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Original Articles

Computing L-Invariants for the Symmetric Square of an Elliptic Curve

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Abstract

Let E be an elliptic curve over Q, and p2 a prime of good ordinary reduction. The p-adic L-function for Sym2E always vanishes at s = 1, even though the complex L-function does not have a zero there. The L-invariant itself appears on the right-hand side of the formula ddsLp(Sym2E,s)|s=1=Lp(Sym2E)×(1αp2)(1pαp2)×L(Sym2E,1)(2πi)1ΩE+ΩE where X2ap(E)X+p=(Xαp)(Xβp) with αpZp×. We first devise a method to calculate Lp(Sym2E) effectively, then show it is non-trivial for all elliptic curves E of conductor NE300 with 4|NE, and almost all ordinary primes p < 17. Hence, in these cases at least, the order of the zero in Lp(Sym2E,s) at s = 1 is exactly one.

2000 MATHEMATICS SUBJECT CLASSIFICATION:

Acknowledgments

The first author warmly thanks John Coates and Ralph Greenberg for originally suggesting this problem. Both authors are also grateful to Antonio Lei, Max Flander, and Denis Benois for their helpful suggestions on computing symmetric square L-invariants. They are also grateful to the referee for their insights, in particular the theoretical approach suggested in Section 2.5 (although we have been unable to implement this approach in practice).

Disclosure statement

No potential conflict of interest was reported by the authors.

Notes

1 In the case of split multiplicative reduction the L-invariant for Sym2E is the same as the L-invariant for E, and it is further conjectured (by Greenberg) that the L-invariants for SymmE should be independent of m > 0.

2 We also computed Lp(Sym2E) for E=304e1 at the good ordinary prime p = 5, using an identical method. In fact L5(Sym2(304e1))=L5(Sym2(19a1)) because Eϖ2 is Q-isogenous to 19a1; thankfully, the value we obtained numerically agreed with the 5-adic expansion for L5(19a1) given in [CitationDummit et al. 16, p. 52], at the weight k+2=2.

Additional information

Funding

The second named author is financially supported by a University of Waikato PhD scholarship.

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