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Research Article

On α-skew McCoy ideals related to a monoid

ORCID Icon & | (Reviewing editor)
Article: 1564169 | Received 14 Sep 2018, Accepted 22 Dec 2018, Published online: 01 Aug 2019

Abstract

Let α be an endomorphism of an arbitrary ring R with identity. The aim of this article is to introduce the ideal I of R as an α-skew M-McCoy which is a generalization of α-rigid ideals and McCoy ideals and to investigate its properties. α-skew M-McCoy is an α-skew McCoy ideals relative to a monoid M. The findings show that if αt=IR for some positive integer t and I be an α-skew M-McCoy left ideal of R then I[M,α] is α-skew M-McCoy left ideal of R[M,α]. Also if R be a locally finite ring and I be an α-skew M-McCoy left ideal of R, then I is α-semicommutative left ideal of R.

PUBLIC INTEREST STATEMENT

Let α be an endomorphism of an arbitrary ring R with identity. In this article we introduce ideal I of R is α-Skew M-McCoy (α-Skew McCoy ideals related to a monoid) which are a generalization of McCoy ideals and investigate their properties. We do this by considering the α-Skew McCoy condition on polynomials in R[M, α] instead of R[M]. This provides us with an opportunity to study skew McCoy ideals in a general setting and several known results on skew McCoy ideals that are obtained.

1. Introduction

Throughout this paper, R denotes an associative ring with unity. In (Nielsen, Citation2006), Nielsen introduced the notion of a McCoy ring. A ring R is said to be right McCoy (resp., left McCoy) if for each pair of nonzero polynomials f(x),g(x)R[x] with f(x)g(x)=0, then there exists a nonzero element rR with f(x)r=0 (resp., rg(x)=0). A ring R is McCoy if it is that left and right McCoy. Kamal paykan in (Paykan & Mussavi, Citation2017) express definition of right (M,ω)- McCoy αβRM-0 satisfy αβ=0, then there exists 0rR such that αr=0. where M is a monoid, and ω:MEnd(R) a monoid homomorphism. The ring R is called weak α- skew McCoy with respect to α if for any nonzero polynomials p(x)=i=0naixi and q(x)=j=0mbjxj in R[x;α] with p(x)q(x)=0, there exists rR0 such that aiαi(r)nil(R) for 0in (Nikmehr, Nejati, & Deldar, Citation2014). Aghapouramin and Nikmehr (Citation2018) introduced the notion of a nil-M-McCoy ring. A ring R is right nil-M-McCoy, if whenever α=a1g1++angn, β=b1h1++bmhmR[M]0, with gi,hjM, ai,bjR satisfy αβnil(R)[M], then airnil(R) for some nonzero rR and for each 1in. Left nil-M-McCoy rings are defined similarly. If R is both left and right nil-M-McCoy, then R is nil-M-McCoy. According to Nikmehr (Citation2014), a left ideal I of R is called α-skew Armendariz if the following conditions are satisfied:

1. For any f(x)=i=0naixi and g(x)=j=0mbjxjR[x,α],f(x)g(x)rR[x,α](I[x]) implies aiαi(bj)rR(I),

2. abrR(I) if and only if aα(b)rR(I).

Aghayev, Harmanci, and Halicioglu (Citation2010) defined a ring R that is called α-abelian if, for any a,bR, and any idempotent eR, ea=ae and ab=0 if and only if aα(b)=0 and a ring R is called α-semicommutative if, for any a,bR, ab=0 implies aRb=0 and ab=0 if and only if aα(b)=0. According to Krempa (Citation1996), an endomorphism α of a ring R is called rigid if aα(a)=0 implies a=0 for aR. We call a ring R α-rigid if there exists a rigid endomorphism α of R (see Esmaeili & Hashemi, Citation2012). There are many ways to generalize the McCoy condition, and we direct reader to the excellent papers (Chen & Tong, Citation2005; Cui & Chen, Citation2012; Habibi & Mousavi, Citation2012; Mousavi, Keshavarz, Rasuli, & Alhevaz, Citation2011; Song, Liand, & Yang, Citation2011; Zhao & Liu, Citation2009) for nice introduction to these topics. Given the fact that α-skew McCoy rings has been studied, but its connection with the monoid has not been investigated yet. Therefore the present study tries to fill the gap.

We are motivated to introduce the notion of α-skew M-McCoy left ideal I of R with respect to an endomorphism α of R. This notion extends both ideal skew McCoy ideals an α-skew McCoy ideals. We do this by considering the α-skew McCoy condition on polynomials in R[M,α] instead of R[M]. This provides us with an opportunity to study skew McCoy ideals in a general setting and several known results on skew McCoy ideals that are obtained. Constructing various examples, we classify how the α-skew McCoy ideals relative to a monoid M property behaves under various ring extensions.

2. α-Skew McCoy ideals related to a monoid

We begin this section by the following two definitions and also we study properties of α-skew M-McCoy left ideals.

Definition 2.1 Let α be an endomorphism, a left ideal I of R is called α-skew McCoy if the following are satisfied:

1. For any f(x)=i=0naixi and g(x)=j=0mbjxjR[x,α],f(x)g(x)rR[x,α](I[x]) implies

 i) ideal I of R is a left α-skew McCoy if there exists a nonzero element rR with rbjrR(I) for all Q,

 ii) ideal I of R is a right α-skew McCoy if there exists a nonzero element sR with aiαi(s)rR(I) for all 0in.

2. abrR(I) if and only if aα(b)rR(I).

If ideal I of R is both left α-skew McCoy and right α-skew McCoy, then we say that ideal I of R is an α-skew McCoy.

Definition 2.2 Let M be a monoid and let α be an endomorphism of a ring R, a left ideal I of R is called α-skew M-McCoy if the following satisfied:

1. For any f(x)=i=0naigi and g(x)=j=0mbjhjR[M,α],f(x)g(x)rR[M,α](I[M]) such that ai,bjR and gi,hjM;

 i) ideal I of R is a left α-skew M-McCoy if there exists a nonzero element rR with rbjrR(I), for all 0jm,

 ii) ideal I of R is a right Z-skew M-McCoy if there exists a nonzero element sR with aiαi(s)rR(I) for all 0in.

2. abrR(I) if and only if aα(b)rR(I).

If ideal I of R is both left α-skew M-McCoy and right α-skew M-McCoy, then we say that ideal I of R is an α-skew M-McCoy.

Example 2.1 Let M be a monoid and let Q be an α-skew M-McCoy and consider S=rab0ra00rrZ,a,bQ where Z and Q are the sets of all integers and all rational numbers, it is clear that I=0ab00a000|a,bQ is the left ideal of S. Let α:SS be an automorphism defined by αrab0ra00r=ra/2b/40ra/200r. Then

(1) S is not α-rigid since 00b000000α00b000000=0, but 00b0000000 if b0.

(2) I of S is α-skew M-McCoy left ideal.

let α=A0+A1g++Angn and β=B0+B1g++BmgmS[M,α]0, where Ai= a0ia1ia2i0a0ia1i00a0i, Bj=b0ib1ib2i0b0ib1i00b0i for i=0,,n, j=0,,n such that αβrQ[M,α](I[M]). Let α=α0(g)α1(g)α2(g)0α0(g)α1(g)00α0(g), β=β0(g)β1(g)β2(g)0β0(g)β1(g)00β0(g), α0(g)=a00+a01g++a0ngn, β0(g)=b00+b01g++b0mgm. Since αβrQ[M,α](I[M]) thus for any h(g)=00γ(g)000000I[M], that γ(g)=γ0+γ1g++γtgt, γ(g)αβ=0, thus γ(g)α0(g)β0(g)=0. Since Q is α-skew M-McCoy, left ideal, hence γkαk(a0iαi(b0j))=0 for all k=0,...,t, i=0,...,n and j=0,...,m. If set k=o, then γ0(a0iαi(b0j))=0. Since γ0R is arbitrary, thus 00γ0000000I. Therefore, a0iαi(b0j)rQ(I). If C=001000000. We have CbjrQ(I) for all j and Aiαi(C)rQ(I) for all i. Now we consider a1b1c10a1b100a1, a2b2c20a2b200a2S, 00c3000000I, a1b1c10a1b100a1a2b2c20a2b200a2rQ(I). Thus

00c3000000a1a2a1b2+b1a2a1c2+b1b2+c1a20a1a2a1b2+b1a200a2=000000000

and hence c3a1a2=0. Since Q is α-skew M-McCoy, c3α(a2)=0. Thus

a1b1c10a1b100a1a2b2c20a2b200a2rQ(I) if and only if
a1b1c10a1b100a1α(a2b2c20a2b200a2)rQ(I).

Therefore, I is an α-skew M-McCoy left ideal.

One may conjecture that a ring R may be right ideal α-skew M-McCoy when R/I and I are both right ideal α-skew M-McCoy rings for any nonzero proper ideal I of R, where I is considered as a ring without identity. However, the answer is the following:

Example 2.2 Let F be a field and consider R=U2(F), then R is not right α-skew M-McCoy (hence not right ideal α-skew M-McCoy) by (Hirano, Hong, & Kim, Citation2014, Remark 2.2(2)). Note that all nonzero proper ideals of R are

FF00,0F0Fand0F00.

We will show that R/I and I are both right ideal α-skew M-McCoy for any nonzero ideal I of R. First, let I=FF00. Then R/IF is right ideal α-skew M-McCoy. Let γβrR[M,α](I[M]) such that γ=A0+A1g++Amgm and β=B0+B1h++BnhnrR[M,α](I[M]) where Ai=aibi00 and Bj=cjdj00 for 1im, 1jn. We can write γ=γ1(g)γ2(g)00 and β=β1(g)β2(g)00 where γ1(g)=i=0maigi, γ2(g)=i=0mbigi and β1(h)=j=0ncjhj, β2(h)=j=0ndjhj. From γβrR[M,α](I[M]) we have γ1(g)β1(h)rR[M](I[M]) and γ1(g)β2(h)rR[M](I[M]) if γ1(g)rR[M](I[M]), then β1(h)=β2(h)rR[M](I[M]) and so βrR[M,α](I[M]) a contradiction. Thus γ1(g)rR[M](I[M]) and γ2(g)rR[M](I[M]), i.e., γ=γ1(g)γ2(g)00. This yields that γαi(C)rR[M,α](I[M]) for every nonzero C, in the ideal of I generated by B\,_j^^,S. Next let I=0F0F. Then R/IF is right ideal α-skew M-McCoy. Let γβrR[M,α](I[M]) for γ=A0+A1g++Amgm=0γ1(g)0γ2(g) and β=B0+B1h++Bnhn= 0β1(h)0β2(h)rR[M,α](I[M]), and γ,βI[M], where Ai=0ai0bi and Bj=0cj0dj for 1im, 1jn, since γ1(g)rR[M](I[M]) or γ2(g)rR[M](I[M]), we get β2(h)rR[M](I[M]) from γβrR[M,α](I[M]), entailing β=0β1(h)0β2(h). This yields that γαi(D)rR[M,α](I[M]) for every nonzero D, in the ideal of I generated by B\,_j^^,S. Finally let I=0F00. Then R/I=FF is right α-skew M-McCoy. I is clearly right ideal α-skew M-McCoy, since I2=0. Similarly we show that I is left ideal α-skew M-McCoy. Now we consider F1F10F1, F2F20F2R, 0F300I, F1F10F1F2F20F2 rR[M](I[M]). Thus 0F300F1F22F1F20F1F2=0000, and hence F3F1F2=0, since I is α-skew M-McCoy, F3F1α(F2)=0. Thus F1F10F1F2F20F2rR[M](I[M]) if and only if F1F10F1 αF2F20F2rR[M](I[M]). Therefore, I is an α-skew M-McCoy left ideal.

The following example shows that there exists a ring R such that R is α-skew M-McCoy. But R/I and I is not α-skew M-McCoy.

Example 2.3 Let Z be the ring of integers and Z4 be the ring of integers modulo 4. Consider a ring

R=abˉ0a| aZ,bˉZ4.

Let α:RR be an endomorphism defined by

αabˉ0a=abˉ0a.

Then R is α-skew M-McCoy by the similar method in the proof of (Hong, Kim, & Kwak, Citation2003, Proposition 15). However, for an ideal I=a0ˉ0a| a4Z of R, the factor ring

R/Iaˉbˉ0aˉ| aˉ,bˉZ4

is not α-skew M-McCoy. In fact,

2ˉ0ˉ02ˉ+2ˉ1ˉ02ˉg2=0(R/I)[M,α],

but

2ˉ1ˉ02ˉα2ˉ0ˉ02ˉ0.

Recall that if α is an endomorphism of a ring R, then the map R[M]R[M] defined by i=0naigii=0nα(ai)gi is an endomorphism of the polynomial ring R[M] and clearly this map extends α. We shall also denote the extended map R[M]R[M] by α and the image of fR[M] by α(f).

Theorem 2.1 Let M be a monoid and α be an endomorphism such that αt=IR for some positive integer t. And I be a left ideal of R. If I is an α-skew M-McCoy, then I[M,α] is α-skew M-McCoy.

Proof. Let α(y)=f0+f1y++fnyn, β(y)=g0+g1y++gmgmR[M,α][y,α]0 with α(y)β(y)rR[M,α](I[M,α]) where fi,gjR[M,α] we need to prove each fiαi(s)rR[M](I[M]), and rgjrR[M](I[M]) for some nonzero r,sR.□

Assume that fi=ai0+ai1g1++aiuigui,gi=bj0+bj1h1++bjvjhvj for each 1in and 1jm, where ai0,...,aiui,bj0,...,bjvjR and gi,hjM. Take a positive integer k such that k>maxdeg(fi),deg(gj) for any 1in and 1jm, where the degree is as polynomial in R[M,α] and the degree of zero polynomial is taken to be 0.

Suppose that α(gtk)=f0+f1gtk+1++fngntk+n, β(htk)=g0+g1htk+1++gmhmtk+m. Then α(gtk),β(htk)rR[M,α](I[M,α]). And the set of coefficient of fi,S (resp., gj,S) equal the set of coefficients of α(gtk) (resp., β(htk)). It is easy to check that α(gtk)β(htk)rR[M,α](I[M,α]), since α(y)β(y)rR[M,α](I[M,α]) and αtk=IR. Since I is α-skew M-McCoy, there exists r,sR0 such that rβ(htk)rR[M,α](I[M,α]) and α(gtk)srR[M,α](I[M,α]). And rβ(htk)rR[M,α](I[M,α]) implies rbjkrR[M](I[M]) for any 0jm, and 0kvj. Hence rgjrR[M](I[M]) for any 0jn.

Therefore I[M,α] is left α-skew M-McCoy, α(gtk)srR[M,α](I[M,α]) implies ailαitk+i+lrR[M](I[M]) for any 0in and 0lui, since αi+l=IR. Hence we have

fiαi(s)=(ai0+ai1++aiuigui)αi(s)
=ai0αi+0(s)+ai1αi+1(s)g++aiuiαi+u(s)guirR[M](I[M]),

for any 0in. Therefore I[M,α] is right α-skew M-McCoy. Now we consider f,gR[M,α], λI[M], fgrR[M](I[M]). Thus λfg=0. Since I is α-skew M-McCoy, λfα(g)=0. Thus fgrR[M](I[M]) if and only if fα(g)rR[M](I[M]). Therefore I[M,α] is α-skew M-McCoy. The proof is completed.□

Recall that an element a in R is called regular if rR(a)=0=lR(a), i.e., a is not a zero divisor. For subrings of an α-skew M-McCoy ring, we have the following.

Proposition 2.1 Let M be a monoid and α be an endomorphism of a ring R and I be an ideal of R satisfying that every nonzero element in I is regular. If R is α-skew M-McCoy, then I is α-skew M-McCoy (without identity).

Proof. Let α=Σi=0naigi, β=Σj=0mbjhjI[M,α]0 with αβrR[M,α](I[M]), since I is an ideal of R and R is α-skew M-McCoy, there exists nonzero elements r,sR satisfying rbjrR(I) for any 0jm, and aiαi(s)rR(I) for any 0in. Therefore tr,stI0 for any nonzero element tI (otherwise, if trrR(I) (resp., strR(I)) for a element tI0, then rrR(I) (resp., srR(I)). Hence r=0 (resp., s=0) since every nonzero element in I is regular. This is a contradiction). Consequently, we have

t(rbj)=(tr)bjrR(I),(aiαi(s))αi(t)=aiαi(st)rR(I)

for any 0in, and 0jm. Thus I is left (resp., right) α-skew M-McCoy. Now we consider a,bR, cI, abrR(I). Thus c(ab)=0. Since R is α-skew M-McCoy, caα(b)=0. Thus aα(b)rR(I). Therefore I is an α-skew M-McCoy left ideal.□

Theorem 2.2 Let M be a monoid and R be a ring and I,J be left ideals of R. If IJ and J/I an α-skew M-McCoy left ideal of R/I,then J is an α-skew M-McCoy left ideal of R.

Proof. Let δ=Σi=0naigi and β=Σj=0mbjhjR[M,α]0 such that δβrR[M,α](J[M]). Then Σi=0naˉgiΣj=0mbˉhjrR/I[M,α]((J/I)[M]). Thus there exists r,s such that aˉαi(sˉ)rR/I(J/I) and rbˉrR/I(J/I), hence aiαi(s)rR(J) and rbjrR(J).

Now we consider aˉ,bˉR/I, cˉJ/I, aˉbˉrR/I(J/I). Thus cˉ(aˉbˉ)=0. Since J/I is α-skew M-McCoy, cˉ aˉα(bˉ)=0. Thus abrR(J) if and only if aα(b)rR(J). Therefore, J is an α-skew M-McCoy.□

The following is an immediate corollary of Theorem 2.2:

Corollary 2.1 Let R be a ring and I an left ideal of R. If R/I is α-skew M-McCoy then R is an α-skew M-McCoy ring.

To prove Proposition 2.4, we state the following propositions:

Proposition 2.2 If I is an α-skew M-McCoy left ideal of R and for some a,b,cR and some integer n1, abrR(I) and acnαn(b)rR(I) then acbrR(I).

Proof. Consider γ=a(1cg), β=(1+cg++cn1gn1)bR[M,α], γβ=abacnαn(b)gn rR[M,α](I(M)). Since I is an α-skew M-McCoy left ideal of R, so acbrR(I).□

Recall that a left ideal I of R is called α-abelian if, for any a,bR and any idempotent eR, we have the following conditions:

1. eaaerR(I),

2. abrR(I) if and only if aα(b)rR(I).

Next, we show that every α-skew M-McCoy left ideal of R is an α-abelian left ideal.

Proposition 2.3 If I is an α-skew M-McCoy left ideal of R, then I is an α-abelian left ideal.

Proof. Assume that I is an α-skew M-McCoy left ideal of R. Consider e=e2R and let a=e, b=(1e), c=er(1e) with rR. Then clearly abrR(I) and e2=0rR(I) and hence ac2α2(b)rR(I) and then by Proposition 2.3, acbrR(I). So erererR(I). Let a1=1e, b1=e, and c1=(1e)re, we also have a1b1c1rR(I). So reererR(I) then reerrR(I).□

Recall that a left ideal I of R is called α-semicommutative if, for any a,bR we have the following conditions:

1. abrR(I) then aRbrR(I),

2. abrR(I) if and only if aα(b)rR(I).

A ring R is called locally finite if every finite subset of R generated a finite semigroup multiplicatively. Finite rings are clearly locally finite and the algebraic of a finite field is locally finite but it is not finite.

Proposition 2.4 Let R be a locally finite ring and I be an α-skew M-McCoy left ideal of R. Then I is α-semicommutative left ideal of R.

Proof. Let abrR(I) with a,bR. For any rR, since R is locally finite there exists integers m,k1 such that rm=rm+k. So we obtain inductively rm=rmrk=rmr2k==rmrmk=rm(k+1), put h=k+1 then rm=(rm)h with h2. Notice that r(h1)m=r(h2)mrm=r(h2)m(rm)h=r2(h1)m=(r(h1)m)2. Hence, r(h1)m is an idempotent and so by Proposition 2.3, ar(h1)mr(h1)marR(I) and abr(h1)mr(h1)mabrR(I). Thus, abr(h1)mrR(I). On the other hand by Proposition 2.3, ar(h1)mr(h1)marR(I), so ar(h1)mbr(h1)mabrR(I), and hence ar(h1)mbrR(I). Since I is an α-skew M-McCoy left ideal of R so ar(h1)mα(h1)m(b)rR(I), and by Proposition 2.2, we imply that arbrR(I) for all rR.□

Let α be an endomorphism of a ring R and Mn(R) be the n×n matrix over ring R and αˉ:Mn(R)Mn(R) defined by αˉ(aij)=(α(aij)). Then αˉ is an endomorphism of Mn(R). It is obvious that, the restriction of αˉ to Dn(R) is an endomorphism of Dn(R), where Dn(R) is the n×n diagonal matrix ring over R. We also denote αˉ|Dn(R) by αˉ.

Proposition 2.5 Let α be an endomorphism of a ring R. Then Dn(I) is an αˉ-skew M-McCoy left ideal of Dn(R) if I is an α-skew M-McCoy left ideal for any n.

Proof. Let α=A0+A1g1++Apgp and β=B0+B1h1++BqhqDn(R)[M,αˉ] satisfying αβrDn(R)[M,αˉ](Dn(I)[M]), where

Ai=a11(i)000a22(i)0000ann(i) and Bj=b11(j)000b22(j)0000bnn(j).

Then from αβrDn(R)[M,αˉ](Dn(I)[M]), it follows that,

i=0pass(i)gij=0qbss(j)hjrR[M,α](I[M])

for each 1sn. Since I is an α-skew M-McCoy left ideal of R, then there exists r,sR such that r(bss(j))rR(I) and ass(i)αi(s)rR(I) for any 1ip and 1jq. Therefore

r(Bj)=r(b11(j))000r(b22(j))0000r(bnn(j))rDn(R)(Dn(I))and
Aiαi(Bj)=a11(i)αi(b11(j))000a22(i)αi(b22(j))0000ann(i)αi(bnn(j))rDn(R)(Dn(I)).

Now we consider Ai=a11(i)000a22(i)0000ann(i), Bj=b11(j)000b22(j)0000bnn(j)Dn(R), Ck= c11(k)000c22(k)0000cnn(k)Dn(I),

a11(i)000a22(i)0000ann(i)b11(j)000b22(j)0000bnn(j)rDn(R)(Dn(I)).

Thus c11(k)000c22(k)0000cnn(k)a11(i)b11(j)000a22(i)b22(j)0000ann(i)bnn(j)=0000000000, and hence c11(k)a11(i)b11(j)=0. Since I is an α-skew M-McCoy, c11(k)a11(i)α(b11(j))=0. Thus a11(i)000a22(i)0000ann(i)a11(i)b11(j)000a22(i)b22(j)0000ann(i)bnn(j)rDn(R)(Dn(I)) if and only if a11(i)000a22(i)0000ann(i)a11(i)b11(j)000a22(i)b22(j)0000ann(i)bnn(j)rDn(R)(Dn(I)).

Therefore Dn(I) is an αˉ-skew M-McCoy left ideal.□

Additional information

Funding

The authors received no direct funding for this research.

Notes on contributors

Vahid Aghapouramin

Vahid Aghapouramin is a assistant professor, at the department of mathematics, Bonab Branch, Islamic Azad university, Bonab, Iran. His research interests are pure mathematics, Commutative Algebra, Noncommutative Algebra.

Mohammad Javad Nikmehr

Mohammad Javad Nikmehr is a associate professor, Faculty of Mathematics, K.N. Toosi, University of Technology, P.O. Box 16315- 1618, Tehran, Iran. His research interest are Commutative Algebra, Graph Theory, Noncommutative Algebra, Algebraic Combinatorics.

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