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Original Articles

On log-linear modeling for an incomplete two-way contingency table with one variable subject to nonresponse

, &
Pages 973-988 | Received 22 Nov 2017, Accepted 13 Jun 2018, Published online: 17 Nov 2018
 

Abstract

In this paper we address two issues in the use of the nonresponse log-linear models for the analysis of an incomplete two-way contingency table with one variable subject to nonresponse, the occurrence of nonresponse boundary solutions and the assessment of the missing data mechanism. To this end, we employ a set of response odds from the fully classified counts and nonresponse odds from partially classified counts. We first investigate the role of the set of odds in identifying the occurrence of boundary solutions and assessing the nonresponse log-linear models suitable for the data, and then propose a data analytic guideline for the analysis of an incomplete two-way contingency table. We also examine the theoretical properties of the set of odds when nonresponse boundary solutions occur.

MATHEMATICS SUBJECT CLASSIFICATION:

Disclosure statement

On behalf of all authors, the corresponding author states that there is no conflict of interest.

Funding

This research was supported by Basic Science Research Program through the National Research Foundation of Korea funded by the Ministry of Education (NRF-2016R1D1A3B03930392) and National Research Foundation of Korea grant funded by the Korea government (MSIP; Ministry of Science, ICT & Future Planning) (No. 2017R1C1B5077065).

Appendix A. Proof of Theorem 3.1

Proof. Define βij=πij2/πij1. From NMAR model, it is immediate that βij=exp[λR2λR1+λYRj2λYRj1], which does not depend on the subscript i and can be written by βij=β·j. For a I×I×2 contingency table, Baker and Laird (Citation1988); Baker, Rosenberger, and Dersimonian (Citation1992) showed that ML estimates of β·j denoted by β̂·j satisfied (11) jNπ̂ij1β̂·j=yi+2 for i=1,,I(11) where π̂ij1=yij1/N which is ML estimates in the interior of the parameter space. Thus, β̂·j can be obtained by solving system of equations in EquationEq. (11). They also showed ML estimates of πij2 fall on the boundary solution if any β̂·j is nonpositive for all j. For the I×I×2 contingency table, EquationEq. (11) gives ν̂(i,i)=yi+2yi+2=jNπ̂ij1β̂·jjNπ̂ij1β̂·j=jπ̂ij1β̂·jjπ̂ij1β̂·j.

This yields (12) ν̂m(i,i)ν̂(i,i)=jm(π̂im1π̂ij1π̂im1π̂ij1)β̂·jπ̂im1jπ̂ij1β̂·j,(12) (13) ν̂(i,i)ν̂n(i,i)=jn(π̂ij1π̂in1π̂in1π̂ij1)β̂·jπ̂in1jπ̂ij1β̂·j(13) where the subscripts m and n indicate the categories of Y corresponding to ν̂m(i,i) and ν̂n(i,i), respectively. The relationship between ν̂m(i,i),ν̂n(i,i) and ν̂(i,i) given by ν̂m(i,i)=π̂im1π̂im1>π̂ij1π̂ij1=ν̂j(i,i)>π̂in1π̂in1=ν̂n(i,i),

also yields (14) π̂im1π̂ij1>π̂im1π̂ij1andπ̂ij1π̂in1>π̂in1π̂ij1 for jm,n.(14)

We prove Theorem 3.1 by contrapositive. First, we suppose β̂·j>0 for all j=1,,I. Plugging these two inequalities in EquationEq. (14) into EquationEqs. (12) and Equation(13) together with positiveness of β̂·j, then ν̂m(i,i)ν̂(i,i)>0 and ν̂(i,i)ν̂n(i,i)>0. This completes the proof. □

Appendix B. Parameter values used in the simulation study for 2×2×2 and 3×3×2 contingency tables

Table A1. Values of πij1 in a 2×2×2 table.

Table A2. Values of πij2 for the NMAR model in a 2×2×2 table.

Table A3. Parameters for three nonresponse models in a 2×2×2 table.

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