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Classroom Notes

Modelling the evolution of human postmenopausal longevity using ordinary differential equations

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Received 30 Mar 2023, Published online: 27 Jun 2024

Figures & data

Figure 1. Diagram of female-only model (Equation1)–(Equation2).

Figure 1. Diagram of female-only model (Equation1(1) dF1dt=(1−ε)(a+γb)F1⏟OffspringproducedbyyoungandoldF1femaleswithnomutation−δF1⏟Death,(1) )–(Equation2(2) dF2dt=ε(a+γb)F1⏟OffspringproducedbyyoungandoldF1femaleswithmutation+aF2⏟OffspringproducedbyyoungF2females−δF2⏟Death,(2) ).

Table 1. Parameters and variables for (Equation1)–(Equation2).

Figure 2. Survival curve from the Hadza lifetable of Blurton Jones et al. (Citation2002, Table 3). We partition the population into three age classes: juvenile (age 0–15), young (age 15–45), and old (ages 45+).

Figure 2. Survival curve from the Hadza lifetable of Blurton Jones et al. (Citation2002, Table 3). We partition the population into three age classes: juvenile (age 0–15), young (age 15–45), and old (ages 45+).

Figure 3. Growth curves dU/dt vs U for (Equation4). (a) When 0<1ε(1+a/b), the positive equilibrium is stable and U=0 is unstable. (b) When 0<1ε(1+a/b), the equilibrium at U=0 is stable and the negative equilibirum is unstable.

Figure 3. Growth curves dU/dt vs U for (Equation4(4) dUdt=((1−ε)(a+γb)−a−γbU)U.(4) ). (a) When 0<1−ε(1+a/b), the positive equilibrium is stable and U=0 is unstable. (b) When 0<1−ε(1+a/b), the equilibrium at U=0 is stable and the negative equilibirum is unstable.

Figure 4. Bifurcation diagram of equilibrium points Ueq for the proportion of females with trait 1 (lifelong fertility) for various values of γ, the probability old, fertile females find mates. Equilibria cross at a transcritical bifurcation at γ=(ε/(1ε))(a/b), where they swap stabilities.

Figure 4. Bifurcation diagram of equilibrium points Ueq for the proportion of females with trait 1 (lifelong fertility) for various values of γ, the probability old, fertile females find mates. Equilibria cross at a transcritical bifurcation at γ=(ε/(1−ε))(a/b), where they swap stabilities.

Figure 5. Phase plane for (Equation11) and (Equation12). The population U is the proportion of females with lifelong fertility as opposed to old-age infertility, and V is the proportion of males who are unfussy and will mate with females of any age as opposed to fussy males who only mate young females. (Note that the figure is not drawn to scale to make certain features more prominent. In fact, it is generated by setting an artificially high mutation rate ε=0.05 and taking other parameter values from Table .)

Figure 5. Phase plane for (Equation11(11) dUdt=(b(1−ε−U)V−εa)U,(11) ) and (Equation12(12) dVdt=bUV(1−V).(12) ). The population U is the proportion of females with lifelong fertility as opposed to old-age infertility, and V is the proportion of males who are unfussy and will mate with females of any age as opposed to fussy males who only mate young females. (Note that the figure is not drawn to scale to make certain features more prominent. In fact, it is generated by setting an artificially high mutation rate ε=0.05 and taking other parameter values from Table 1.)

Figure 6. Trajectories for (Equation11) and (Equation12) using parameters from Table , including ε=0.0001. Nearly all trajectories approach the stable node at (U,V)=(0.9998,1). The population U is the proportion of females with lifelong fertility as opposed to old-age infertility, and V is the proportion of males who are unfussy and will mate with females of any age as opposed to fussy males who only mate young females.

Figure 6. Trajectories for (Equation11(11) dUdt=(b(1−ε−U)V−εa)U,(11) ) and (Equation12(12) dVdt=bUV(1−V).(12) ) using parameters from Table 1, including ε=0.0001. Nearly all trajectories approach the stable node at (U,V)=(0.9998,1). The population U is the proportion of females with lifelong fertility as opposed to old-age infertility, and V is the proportion of males who are unfussy and will mate with females of any age as opposed to fussy males who only mate young females.

Figure 7. Basin of attraction for the stable node (1ε(1+a/b),1). We can observe that all trajectories starting in the light grey region with U>0 and V>(ε/(1ε))(a/b) have positive dV/dt and are repelled from the line of equilibria at U=0, so they are guaranteed to approach the stable node (1ε(1+a/b),1). From numerical simulations, we find that the basin of attraction includes an additional region in dark grey below the dashed line V=(ε/(1ε))(a/b). (Note that this figure is not drawn to the correct scale as in Figure . It is drawn to the scale of Figure .).

Figure 7. Basin of attraction for the stable node (1−ε(1+a/b),1). We can observe that all trajectories starting in the light grey region with U>0 and V>(ε/(1−ε))(a/b) have positive dV/dt and are repelled from the line of equilibria at U=0, so they are guaranteed to approach the stable node (1−ε(1+a/b),1). From numerical simulations, we find that the basin of attraction includes an additional region in dark grey below the dashed line V=(ε/(1−ε))(a/b). (Note that this figure is not drawn to the correct scale as in Figure 6. It is drawn to the scale of Figure 5.).