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Original Articles

Influence of Cationic Micelle on the Oxidation of Acetaldehyde by N-Bromophthalimide

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Pages 863-870 | Received 12 Mar 2011, Accepted 05 Apr 2011, Published online: 30 May 2012
 

Abstract

The kinetics of oxidation of acetaldehyde by N-bromophthalimide (NBP) has been studied in the presence of cationic surfactant, cetyltrimethylammonium bromide (CTAB) at 308 K. The order of the reaction with respect to substrate (acetaldehyde) and oxidant (NBP) is first and positive fractional with respect to the [H+]. The rate of the reaction decreased with increase in dielectric constant of the medium. The rate constant first increased with increasing concentration of CTAB and after attaining peak, this rate constant decreased with increase in CTAB concentrations, on further increasing the concentration, it became almost constant. Addition of the inorganic salts, that is, [Cl] and [Br] rate of the reaction increased. CH3COOH was identified as the main oxidation product of the reaction. Activation parameters have been calculated. The rate constant and binding constant with the surfactant have also been evaluated.

Acknowledgments

Y. R. Katre thanks the University Grants Commission Regional Office Bhopal for the research project grant.

Notes

Reaction conditions: [CH3CHO] = 0.01 mol/L, Hg(OAc)2 = 2 × 10−4 mol/L, [H+] = 0.01 mol/L, [CTAB] = 3.6 × 10−4 mol/L, CH3COOH = 50%, temp. 308 K.

Reaction conditions: [NBP] = 1 × 10−4 mol/L, Hg(OAc)2 = 2 × 10−4 mol/L, [H+] = 0.01 mol/L, [CTAB] = 3.6 × 10−4 mol/L, CH3COOH = 50%, temp. 308 K.

Reaction conditions: [NBP] = 1 × 10−4 mol/L, Hg(OAc)2 = 2 × 10−4 mol/L, [CH3CHO] = 0.01 mol/L, [CTAB] = 3.6 × 10−4 mol/L, CH3COOH = 50%, temp. 308 K.

Reaction conditions:[NBP] = 1 × 10−4 mol/L, Hg(OAc)2 = 2 × 10−4 mol/L, [CH3CHO] = 0.01 mol/L, [CTAB] = 3.6 × 10−4 mol/L, [H+] = 0.01 mol/L, temp. 308 K.

Reaction conditions: [NBP] = 1 × 10−4 mol/L, Hg(OAc)2 = 2 × 10−4 mol/L, [CH3CHO] = 0.01 mol/L, [H+] = 0.01 mol/L, CH3COOH = 50%, temp. 308 K.

Reaction conditions: [NBP] = 1 × 10−4 mol/L, Hg(OAc)2 = 2 × 10−4 mol/L, [CH3CHO] = 0.01 mol/L, [H+] = 0.01 mol/L, CH3COOH = 50%, [CTAB] = 3.6 × 10−4 mol/L.

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