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Original Articles

Online Education of Older Adults and its Relation to Life Satisfaction

Pages 127-143 | Published online: 12 Jan 2007
 

Abstract

The purpose of this research was to study the effect of participation in online education on the life satisfaction of the older adult. Life satisfaction was assessed by scores obtained using questions the from Nuegarten, Havighurst, and Tobin (Citation1961) Life Satisfaction Index-A (LSI-A). Other data was obtained using demographic and procedural questions.

Raw data suggested that participation in online education can, in fact, increase life satisfaction. However, when results were tested significance was not determined.An implication of the research is that older adults are positively impacted by even minimal exposure to online education.

Notes

Note. Sum of squares (1) = 2893; Sum of squares (2) = 8789; df = 91; p (probability) = .05; t value (probability of getting t) = .93; T value (distribution of t) for probability of .05 and df = 91 is 1.990 (Gay, Citation1996, p. 611); t = .93 < 1.990.

Note. Sum of squares (1) = 2893; Sum of squares (2) = 2613; Standard deviation (1) = 3.3; Standard deviation (2) = 3.5; df = 40; p (probability) = .05; t value (probability of getting t) = .61; T value (distribution of t) for probability of .05 and df = 40 is 2.021 (Gay, Citation1996, p. 611); t = .61 < 2.021.

Note. Sum (1) = 34; Sum (2) = 34; Mean (1) = 1.62; Mean (2) = 1.62; Sum of squares (1) = 60; Sum of squares (2) = 60; Standard deviation (1) = 50; Standard deviation (2) = 50; df = 40; p (probability) = .05; t value (probability of getting t) = 0, T value (distribution of t) for probability of .05 and df = 40 is 2.021 (Gay, Citation1996, p. 611); t = 0 > 2.021.

Note. N1 = 69 (from Table 4); N2 = 24; Sum (1) = 138; Sum (2) = 33; Mean (1) = 2; Mean (2) = 1.38; Sum of squares (1) = 276; Sum of squares (2) = 51; Standard deviation (1) = 0; Standard deviation (2) = 5.62; df = 91, p (probability) = .05, t value (probability of getting t) = 12.4, T value (distribution of t) for probability of .05 and df = 91 is 1.990 (Gay, Citation1996, p. 611) t = 12.47 > 1.990.

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