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Original Articles

A Sharkovsky theorem for vertex maps on trees

Pages 103-113 | Received 07 Oct 2008, Accepted 19 Mar 2009, Published online: 11 Dec 2009
 

Abstract

Let T be a tree with n vertices. Let be continuous and suppose that the n vertices form a periodic orbit under f. We show:

    1. If n is not a divisor of 2 k then f has a periodic point with period 2 k .

    2. If , where is odd and , then f has a periodic point with period 2 p r for any .

    3. The map f also has periodic orbits of any period m where m can be obtained from n by removing ones from the right of the binary expansion of n and changing them to zeroes.

  1. Conversely, given any n, there is a tree with n vertices and a map f such that the vertices form a periodic orbit and f has no other periods apart from the ones given above.

1991 Mathematics Subject Classification::

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