Figures & data
FIGURE 3 Domain partition consistent with parallel beams of radiation, and corresponding rotated coordinate system.
![FIGURE 3 Domain partition consistent with parallel beams of radiation, and corresponding rotated coordinate system.](/cms/asset/5d690a9d-3730-40c8-9b96-0caa142fd661/gipe_a_10054449_f0003.gif)
FIGURE 6 Rotated pixel Knj, mjj and representation of radiation intensities for the discontinuous Galerkin finite element method.
![FIGURE 6 Rotated pixel Knj, mjj and representation of radiation intensities for the discontinuous Galerkin finite element method.](/cms/asset/515e0b8b-44c1-4dea-b200-684d927a5cc9/gipe_a_10054449_f0006.gif)
FIGURE 8 Solution of the direct radiative transfer problem for configuration 1 with 2J=12 and 2M = 20. Radiation originated at source j = 1 is coming into the medium only through the strip n1 = 10.
![FIGURE 8 Solution of the direct radiative transfer problem for configuration 1 with 2J=12 and 2M = 20. Radiation originated at source j = 1 is coming into the medium only through the strip n1 = 10.](/cms/asset/1a9ee0f1-95e5-48c1-85a2-20e30ff0767e/gipe_a_10054449_f0008.gif)
FIGURE 9 Reconstructed values for the combination of absorption and scattering coefficients. Test case 1 with configuration 1. α1 = β1 = 10.
![FIGURE 9 Reconstructed values for the combination of absorption and scattering coefficients. Test case 1 with configuration 1. α1 = β1 = 10.](/cms/asset/4624dabc-ab5a-41c1-b3ab-9359460d5f98/gipe_a_10054449_f0009.gif)
FIGURE 10 Reconstructed values for the combination of absorption and scattering coefficients. Test case 2 with configuration 1. α1=β1=12.5.
![FIGURE 10 Reconstructed values for the combination of absorption and scattering coefficients. Test case 2 with configuration 1. α1=β1=12.5.](/cms/asset/de90e805-4197-4528-a112-0557be161470/gipe_a_10054449_f0010.gif)
FIGURE 12 Solution of the direct radiative transfer problem for configuration 2 with 2J = 12 and 2M = 20. Radiation originated at source j = 1 is coming into the medium only through the strip n1 = 10.
![FIGURE 12 Solution of the direct radiative transfer problem for configuration 2 with 2J = 12 and 2M = 20. Radiation originated at source j = 1 is coming into the medium only through the strip n1 = 10.](/cms/asset/8a0ff448-fd71-4519-ac49-c2f05861ac10/gipe_a_10054449_f0012.gif)
FIGURE 13 Reconstructed values for the combination of absorption and scattering coefficients. Test case 1 with configuration 2. α1 = 10, β1 = 1, α2 = 1, β2 = 10.
![FIGURE 13 Reconstructed values for the combination of absorption and scattering coefficients. Test case 1 with configuration 2. α1 = 10, β1 = 1, α2 = 1, β2 = 10.](/cms/asset/95101989-2f9f-4366-9882-5337f952060f/gipe_a_10054449_f0013.gif)
FIGURE 14 Reconstructed values for the combination of absorption and scattering coefficients. Test case 2 with configuration 2. α1=12.5, β1 = 1, α2 = 1, β2 = 20.
![FIGURE 14 Reconstructed values for the combination of absorption and scattering coefficients. Test case 2 with configuration 2. α1=12.5, β1 = 1, α2 = 1, β2 = 20.](/cms/asset/66358a72-1f47-45b6-abac-0dd33d2bd09f/gipe_a_10054449_f0014.gif)
Table
Table