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Research Article

On the use of reduced grids in conjunction with the Equator-Pole grid system

Pages 1-12 | Received 20 Feb 2020, Accepted 29 May 2020, Published online: 15 Jul 2020

Figures & data

Fig. 1. A small part 0λ45o and θ0 of a reduced grid for n = 160 and K = 3.

Fig. 1. A small part 0≤λ≤45o and θ≥0 of a reduced grid for n = 160 and K = 3.

Table 1. Reduced lat-lon grids with n = 360 and K segments on a hemisphere, using method I. Let NK be the total number of discretisation points for given K, pK is the decrease in per cent of N1, that is NK=(1pK/100)N1, and the quantity si is the number of parallels in the segment Sid. The area of the polar regions as per cent of the total area of the sphere is given by qK=100(1sinθK).

Table 2. Let N be the total number of discretisation points and si the number of parallels in the segment Sid. The areas of the polar regions as per cent of the total area of the sphere is given by q10=100(1sinθ10).

Table 3. Normalised errors for solid rotation of the Cosine bell, n = 360, Δt=600 s, T = 12 days, α=π/3, and minimisation over c.

Table 4. Normalised errors for time dependent flow(Läuter), ¯2(Ψ*,15) minimised over c, n = 360, T = 15 days, α=π/4.

Table 5. Normalised errors for time dependent flow(Läuter), r¯e(15) minimised over c, n = 360, 2p=6,Δt=300 s, T = 15 days, α=π/4.

Fig. 2. Contour curves for the total height H of the fluid for the mountain problem, no. 5 from Williamson et al. (Citation1992): n = 360, K = 3, 2p = 6, c=105, T = 15 days. Method I.

Fig. 2. Contour curves for the total height H of the fluid for the mountain problem, no. 5 from Williamson et al. (Citation1992): n = 360, K = 3, 2p = 6, c=10−5, T = 15 days. Method I.

Table 6. Zonal flow over an isolated mountain, θc=30o, n = 360, K = 3, Δt=300, T = 15 days, 6 or 4 before r¯m(15) or r¯e(15) denotes the approximation order.

Table 7. The mountain problem, θc=30o, n = 360, K = 3, Δt=300, T = 5 years.