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Original Article

On cyclic orthogonal double covers of circulant graphs by special infinite graphsFootnote

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Pages 269-276 | Received 15 Nov 2015, Accepted 11 Apr 2017, Published online: 10 Jun 2020

Abstract

In this article, a technique to construct cyclic orthogonal double covers (CODCs) of regular circulant graphs by certain infinite graph classes such as complete bipartite and tripartite graphs and disjoint union of butterfly and K1,2n10 is introduced.

1 Introduction

Let H be a graph with vertex set V. A collection G=(Gv)vV of isomorphic spanning subgraphs (called pages) of H is an orthogonal double cover (ODC) of H by G if the following two conditions hold

(1) Every edge in H belongs to exactly two of the pages (double cover property) and

(2) Gx and Gy share an edge if and only if x and y are adjacent in H (orthogonality).

This concept is a natural generalization of earlier definitions of an ODC for complete and complete bipartite graphs, that have been studied extensively (see the survey [Citation1]). The necessary condition for an ODC of H by G is that H is regular.

An effective technique to construct ODCs in the above cases was based on the idea of translating a given subgraph of G by a group acting on V(H).

The purpose of this article is to investigate the existence of cyclic orthogonal double covers of circulant graphs. The existence problem of ODCs by given graphs has attracted much attention during the last 10 years. The problem is known to be hard in general as it includes some long-standing open problems like the existence problems of biplanes as special cases. Also, the ODC problem originally stems from problems in database optimization and statistical design, and design theory. In [Citation2,Citation3], Demetrovics et al. investigated Armstrong database of minimum size for key and functional dependence. Armstrong database of size n is equivalent to ODCs of Kn whose pages consist of distinct cliques. The problem, however, subsequently earned a life of its own, resulting in a relatively rich literature, generalizing the problem to an expanding class of graphs, whereas the initial interest was connected to complete graphs. Research on ODCs has motivated the development of various direct and recursive methods for constructing ODCs. This article contains seven technical results (four theorems and three corollaries), regarding the existence of cyclic ODCs for certain classes of regular circulant graphs (of which complete graphs are a special case).

An automorphism of an ODC G=(Gv)vV of H is a permutation σ:V(H)V(H) such that {σ(Gv)vV}=G where σ(Gv) is a subgraph of H with V(σ(Gv))={σ(v):vV(Gv)} and E(σ(Gv))={(σ(u),σ(v)):(u,v)E(Gv)}. An ODC G of H is cyclic (CODC) if the cyclic group of order |V(H)| is a subgroup of the automorphism group of G.

Let B be an Abelian group with identity 0. Let S be a subset of B satisfying 0S and S=S -that is, sS if and only if sS. The Cayley graph Cay(B;S) on B with connection set S is defined as follows (i) the vertices are the elements of B and (ii) there is an edge joining u and v if and only if u=s+v for some sS. The Cayley graphs on cyclic groups have played a special role in the study of Cayley graphs. They are widely known as circulant graphs, because their adjacency matrices are circulant matrices. We use the notation Circ(n;S) to denote the circulant graph of order n with connection set S. The length of an edge (u,v) in Circ(n;S), is defined by d(u,v)=min{uv,nuv}. An example, the circulant graph Circ(7;{2,3,4,5}) is given in .

Fig. 1 The circulant graph Circ(7;{2,3,4,5}).

In this article we make use of the usual notation: Km,n for the complete bipartite graph with partition sets of sizes m and n, Kn for the complete graph on n vertices, GF for the disjoint union of G and F, Km,n,k for the complete tripartite graph with partition sets of sizes m,n and k, Pn for the path on n vertices, and GF represents the graph obtained by removing the edges of a subgraph F from the graph G, where the graphs G and F are spanning subgraphs of H. Let k1,n1,n2,,nk be positive integers, n1,nk1 and ni0 for i{2,3,,k1}, the caterpillar Ck(n1,n2,,nk) is the tree obtained from the path Pk:=x1x2xk by joining vertex xi to ni new vertices, i{1,2,3,,k}.

Orthogonal labelling notion is introduced by the authors of [Citation1]. Given a graph G=(V,E) with m1 edges, a 11 mapping Ψ:V(G)Zm is an orthogonal labelling of G if (1)G contains exactly two edges of length d{1,2,,(m1)2}, and exactly one edge of length m2 if m is even, and (2){r(d):d{1,2,,(m1)2}}={1,2,,(m1)2}, where r(d) is the rotation-distance between two edges, see [Citation1].

Gronau et al. [Citation1] relates CODCs of Km and the orthogonal labelling by the following theorem.

Theorem 1

[Citation1]

A CODC of Km by a graph G exists if and only if there exists an orthogonal labelling of G.

The following theorem of Sampathkumar and Srinivasan is a generalization of Theorem 1.

Theorem 2

[Citation4]

A CODC of Circ(m;d1,d2,,dk) by a graph G exists if and only if there exists an orthogonal d1,d2,,dk-labelling of G.

For results on orthogonal double cover of circulant graphs, see [Citation4Citation5Citation7]. In [Citation1Citation8Citation10], other results of ODCs by different graph classes can be found. In [Citation11], the other terminology not defined here can be found. We use Theorem 2 to prove the existence of CODC of circulant graphs by a graph G.

2 CODCs of circulant graphs by complete bipartite and tripartite graphs

Theorem 3

For all positive integers n>1, there exists a CODC of 4nregular Circ (4n+2;{1,2,,2n}) by K2,2n.

Proof

Let us define Ψ:V(K2,2n)Z4n+2 byΨ(v0)=0,Ψ(v1)=2n+1,Ψ(vj)=2n+j, where 2jn+1, and Ψ(vj)=4n+1+j, where n+2j2n+1. Then the edges of lengths l, where 1ln, are (Ψ(v1),Ψ(vl+1)), and (Ψ(v1),Ψ(vn+l+1)), and the edges of lengths l, where n+1l2n are (Ψ(v0),Ψ(vln+1)), and (Ψ(v0),Ψ(vl+1)). Hence for l{1,2,,2n},K2,2n contains exactly two edges of length l, and since every two edges of the same length are adjacent {r(l):l{1,2,,2n}}={1,2,,2n}. Hence K2,2n has an orthogonal labelling.  

A CODC generating graph of 8regular Circ (10;{1,2,3,4}) by K2,4, is shown in .

Fig. 2 CODC generating graph of 8regular Circ (10;{1,2,3,4}) by K2,4.

Theorem 4

For any positive integer n5, there exists a CODC of (3n1)regular Circ (3n;{1,2,,3n2}) by K1,2,n1.

Proof

Let us define Ψ:V(K1,2,n1)Z3n byΨ(v0)=0,Ψ(v1)=2,Ψ(v2)=4, and Ψ(vj)=3j6, where 3jn+1. E(K1,2,n1)={{(Ψ(v0),Ψ(v1))}{(Ψ(v0),Ψ(v2))}{(Ψ(v0),Ψ(vj)):3jn+1}{(Ψ(v1),Ψ(vj)):3jn+1}{(Ψ(v2),Ψ(vj)):3jn+1}}.

Case 1. n=2m+1; m2.

The edges of length 1 are (Ψ(v1),Ψ(v3)) and (Ψ(v2),Ψ(v3)); the edges of length 2 are (Ψ(v0),Ψ(v1)) and (Ψ(v2),Ψ(v4)); the edges of length 4 are (Ψ(v0),Ψ(v2)) and (Ψ(v1),Ψ(v4)); the edges of length 3i where 1im are (Ψ(v0),Ψ(vi+2)) and (Ψ(v0),Ψ(v2m+3i)); the edges of length 3i+2 where 1im1 are (Ψ(v2),Ψ(vi+4)) and (Ψ(v1),Ψ(v2m+3i)); the edges of length 3i+4 where 1im1 are (Ψ(v1),Ψ(vi+4)) and (Ψ(v2),Ψ(v2m+3i)). Hence for l{1,2,,3n2}, K1,2,n1 contains exactly two edges of length {1,2,,3n2}, and {r(l):{1,2,,3n2}}={1,2,,3n2}. Hence K1,2,n1 has an orthogonal labelling.

Case 2. n=2m; m3.

The edge of length 3m is (Ψ(v0),Ψ(vm+2)); the edges of length 1 are (Ψ(v1),Ψ(v3)) and (Ψ(v2),Ψ(v3)); the edges of length 2 are (Ψ(v0),Ψ(v1)) and (Ψ(v2),Ψ(v4)); the edges of length 4 are (Ψ(v0),Ψ(v2)) and (Ψ(v1),Ψ(v4)); the edges of length 3i where 1im1 are (Ψ(v0),Ψ(vi+2)) and (Ψ(v0),Ψ(v2m+2i)); the edges of length 3i+2 where 1im1 are (Ψ(v2),Ψ(vi+4)) and (Ψ(v1),Ψ(v2m+2i)); the edges of length 3i+4 where 1im2 are (Ψ(v1),Ψ(vi+4)) and (Ψ(v2),Ψ(v2m+2i)). Hence for l{1,2,,3n21}, K1,2,n1 contains exactly two edges of length {1,2,,3n21}, and {r(l):{1,2,,3n21}}={1,2,,3n21}. Hence K1,2,n1 has an orthogonal labelling.  

A CODC generating graph of 14regular Circ (15;{1,2,3,4,5,6,7}) by K1,2,4, is shown in .

Fig. 3 CODC generating graph of 14regular Circ (15;{1,2,3,4,5,6,7}) by K1,2,4.

3 CODCs of regular circulant graphs by certain graph Hn

Let Hn (as shown in ) be a graph with the edge set:

Fig. 4 CODC generating graph of (2n1)regular Circ (2n;{1,2,,n}) by Hn.

E(Hn)={(Ψ(v1),Ψ(v3)),(Ψ(v0),Ψ(v2)),(Ψ(v3),Ψ(v0)),(Ψ(v3),Ψ(v2)),(Ψ(v0),Ψ(v4)),(Ψ(v5),Ψ(v4)),(Ψ(v0),Ψ(v5)),(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2))}{(Ψ(v6),Ψ(vα+4)):3αn3}{(Ψ(v6),Ψ(vβ1)):n+3β2n3}, where Ψ:V(Hn)Z2n is defined by Ψ(v0)=0,Ψ(v1)=1,Ψ(v2)=2,Ψ(v3)=n+1,Ψ(v4)=2n1,Ψ(v5)=2n2,Ψ(v6)=n,Ψ(vα+4)=α, where 3α n3,Ψ(vβ1)=β, where n+3β2n3. We denote by V(Hn) the vertex set of the graph Hn.

Theorem 5

For all positive integers n6, there exists a CODC of (2n1)regular Circ (2n;{1,2,,n}) by Hn.

Proof

The edge of length n is (Ψ(v1),Ψ(v3)), the edges of length 1 are (Ψ(v0),Ψ(v4)) and (Ψ(v5),Ψ(v4)); the edges of length 2 are (Ψ(v0),Ψ(v2)) and (Ψ(v0),Ψ(v5)); the edges of length l where 3l n3 are (Ψ(v6),Ψ(vnl+4)) and (Ψ(v6),Ψ(vl+n1)); the edges of length n2 are (Ψ(v6),Ψ(v5)) and (Ψ(v6),Ψ(v2)); the edges of length n1 are (Ψ(v3),Ψ(v0)) and(Ψ(v3),Ψ(v2)). Hence for every l{1,2,,n}, Hn contains exactly two edges of length {1,2,,n1}, and exactly one edge of length n, and {r(l1):l1{1,,n1}}={1,,n1}. Hence Hn has an orthogonal labelling.  

A CODC generating graph of 15regular Circ (16;{1,2,3,4,5,6,7,8}) by H8, is shown in .

Fig. 5 CODC generating graph of 15 regular Circ(16;{1,2,3,4,5,6,7,8}) by H8.

For the following Corollary, E(Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2))})={(Ψ(v1),Ψ(v3)),(Ψ(v0),Ψ(v2)),(Ψ(v3),Ψ(v0)),(Ψ(v3),Ψ(v2)),(Ψ(v0),Ψ(v4)),(Ψ(v5),Ψ(v4)),(Ψ(v0),Ψ(v5))}{(Ψ(v6),Ψ(vα+4)):3αn3}{(Ψ(v6),Ψ(vβ1)):n+3β2n3}, where Ψ:V(Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2))})Z2n is defined by Ψ(v0)=0,Ψ(v1)=1,Ψ(v3)=n+1,Ψ(v4)=2n1,Ψ(vα+4)=α, where 3αn3,Ψ(vβ1)=β, where n+3β2n3.

Corollary 6

For all positive integers n6, there exists a CODC of (2n3)regular Circ (2n;{{1,2,,n}{n2}}) by Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2))}.

Proof

The edge of length n is (Ψ(v1),Ψ(v3)), the edges of length 1 are (Ψ(v0),Ψ(v4)) and (Ψ(v5),Ψ(v4)); the edges of length 2 are (Ψ(v0),Ψ(v2)) and (Ψ(v0),Ψ(v5)); the edges of length l where 3l n3 are (Ψ(v6),Ψ(vnl+4)) and (Ψ(v6),Ψ(vl+n1)); the edges of length n1 are (Ψ(v3),Ψ(v0)) and(Ψ(v3),Ψ(v2)). Hence for every l{1,2,,n}{n2}, Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2))} contains exactly two edges of length {1,2,,n1}{n2}, and exactly one edge of length n, and {r(l1):l1{1,,n1}{n2}}={1,,n1}{n2}. Hence Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2))} has an orthogonal labelling.  

A CODC generating graph of 13regular Circ (16;{1,2,3,4,5,7,8}) by H8{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2))}, is shown in .

Fig. 6 CODC generating graph of 13regular Circ (16;{1,2,3,4,5,7,8}) by H8{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2))}.

For the following Corollary, E(Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2)),(Ψ(v0),Ψ(v2)),(Ψ(v0),Ψ(v5))})={(Ψ(v1),Ψ(v3)),(Ψ(v3),Ψ(v0)),(Ψ(v3),Ψ(v2)),(Ψ(v0),Ψ(v4)),(Ψ(v5),Ψ(v4))}{(Ψ(v6),Ψ(vα+4)):3αn3} {(Ψ(v6),Ψ(vβ1)):n+3β2n3}, where Ψ:V(Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2)),(Ψ(v0),Ψ(v2)),(Ψ(v0),Ψ(v5))})Z2n is defined by Ψ(v1)=1,Ψ(v3)=n+1,Ψ(v4)=2n1,Ψ(vα+4)=α, where 3αn3,Ψ(vβ1)=β, where n+3β2n3.

Also, we denote by C3(1,0,2) the caterpillar Ck(n1,n2,,nk) with k=3,n1=1,n2=0, and n3=2.

Corollary 7

For all positive integers n6, there exists a CODC of (2n5)regular Circ (2n;{{1,2,4,,n}{2,n2}}) by C3(1,0,2)K1,2n10Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2)),(Ψ(v0),Ψ(v2)),(Ψ(v0),Ψ(v5))}.

Proof

The edge of length n is (Ψ(v1),Ψ(v3)), the edges of length 1 are (Ψ(v0),Ψ(v4)) and (Ψ(v5),Ψ(v4)); the edges of length l where 3l n3 are (Ψ(v6),Ψ(vnl+4)) and (Ψ(v6),Ψ(vl+n1)); the edges of length n1 are (Ψ(v3),Ψ(v0)) and(Ψ(v3),Ψ(v2)). Hence for every l{1,2,,n}{2,n2}, Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2)),(Ψ(v0),Ψ(v2)),(Ψ(v0),Ψ(v5))} contains exactly two edges of length {1,2,,n1}{2,n2}, and exactly one edge of length n, and {r(l1):l1{1,,n1}{2,n2}}={1,,n1}{2,n2}. Hence Hn{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2)),(Ψ(v0),Ψ(v2)),(Ψ(v0),Ψ(v5))} has an orthogonal labelling.  

A CODC generating graph of 11regular Circ (16;{1,3,4,5,7,8}) by H8{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2)),(Ψ(v0),Ψ(v2)),(Ψ(v0),Ψ(v5))}C3(1,0,2)K1,6, is shown in .

Fig. 7 CODC generating graph of 11regular Circ (16;{1,3,4,5,7,8}) by H8{(Ψ(v6),Ψ(v5)),(Ψ(v6),Ψ(v2)),(Ψ(v0),Ψ(v2)),(Ψ(v0),Ψ(v5))}C3(1,0,2)K1,6.

4 CODCs of regular circulant graphs by disjoint union of butterfly and K1,2n10

Let Gn(as shown in ) be a graph with the edge set: E(Gn)=E(ButterflyK1,2n10)={(Ψ(v2),Ψ(v0)),(Ψ(v2),Ψ(v1)),(Ψ(v0),Ψ(v4)),(Ψ(v0),Ψ(v1)),(Ψ(v0),Ψ(v3)),(Ψ(v4),Ψ(v3))} {(Ψ(v5),Ψ(vα+3)):3αn3}{(Ψ(v5),Ψ(vβ2)):n+3β2n3}, where Ψ:V(Gn)Z2n is defined by Ψ(v0)=0,Ψ(v1)=2,Ψ(v2)=n+1,Ψ(v3)=2n1,Ψ(v4)=2n2,Ψ(v5)=n,Ψ(vα+3)=α , where 3αn3,Ψ(vβ2)=β , where n+3β2n3. We denote by V(Gn) the vertex set of the graph Gn.

Fig. 8 CODC generating graph of (2n4)regular Circ(2n;{{1,2,,n1}{n2}}) by GnButter fly K1,2n10.

Theorem 8

For all positive integers n6, there exists a CODC of (2n4)regular Circ (2n;{{1,2,,n1}{n2}}) by Gn Butterfly K1,2n10.

Proof

The edges of length 1 are (Ψ(v0),Ψ(v3)) and (Ψ(v4),Ψ(v3)); the edges of length 2 are (Ψ(v0),Ψ(v1)) and (Ψ(v0),Ψ(v4)); the edges of length l where 3l n3 are (Ψ(v5),Ψ(vnl+3)) and (Ψ(v5),Ψ(vl+n2)); the edges of length n1 are (Ψ(v2),Ψ(v0)) and(Ψ(v2),Ψ(v1)). Hence for every l{{1,2,,n1}{n2}}, Gn contains exactly two edges of length {{1,2,,n1}{n2}}, and {r(l):l{{1,2,,n1}{n2}}}={{1,2,,n1}{n2}}. Thus Gn has an orthogonal labelling.  

A CODC generating graph of 12regular Circ (16;{1,2,3,4,5,7}) by G8Butterfly K1,4, is shown in .

Fig. 9 CODC generating graph of 12regular Circ (16;{1,2,3,4,5,7}) by G8Butterfly K1,4.

For the following Corollary, E(Gn{(Ψ(v0),Ψ(v1)),(Ψ(v0),Ψ(v4))})=E(P5K1,2n10)={(Ψ(v2),Ψ(v0)),(Ψ(v2),Ψ(v1)),(Ψ(v0),Ψ(v3)),(Ψ(v4),Ψ(v3))}{(Ψ(v5),Ψ(vα+3)):3αn3} {(Ψ(v5),Ψ(vβ2)):n+3β2n3}, where Ψ:V(P5K1,2n10)Z2n is defined by Ψ(v0)=0,Ψ(v1)=2,Ψ(v2)=n+1,Ψ(v3)=2n1,Ψ(v4)=2n2,Ψ(v5)=n,Ψ(vα+3)=α, where 3α n3,Ψ(vβ2)=β, where n+3β2n3.

Corollary 9

For all positive integers n6, there exists a CODC of (2n6)regular Circ (2n;{{1,3,4,,n1}{n2}}) by Gn{(Ψ(v0),Ψ(v1)),(Ψ(v0),Ψ(v4))}P5K1,2n10.

Proof

The edges of length 1 are (Ψ(v0),Ψ(v3)) and (Ψ(v4),Ψ(v3)); the edges of length l where 3l n3 are (Ψ(v5),Ψ(vnl+3)) and (Ψ(v5),Ψ(vl+n2)); the edges of length n1 are (Ψ(v2),Ψ(v0)) and(Ψ(v2),Ψ(v1)). Hence for every l{{1,3,,n1}{n2}}, P5K1,2n10 contains exactly two edges of length {{1,3,,n1}{n2}}, and {r(l):l{{1,3,,n1}{n2}}}={{1,3,,n1}{n2}}. Thus P5K1,2n10 has an orthogonal labelling.  

A CODC generating graph of 10regular Circ (16;{1,3,4,5,7}) by P5K1,6, is shown in .

Fig. 10 CODC generating graph of 10regular Circ (16;{1,3,4,5,7}) by P5K1,6.

Notes

Peer review under responsibility of Kalasalingam University.

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