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Original Article

On super (a,d)-Cn-antimagic total labeling of disjoint union of cyclesFootnote

Pages 22-26 | Received 19 Apr 2017, Accepted 22 Jan 2018, Published online: 10 Jun 2020

Abstract

Let H and G be finite simple graphs where every edge of G belongs to at least one subgraph that is isomorphic to H. An (a,d)-H-antimagic total labeling of a graph G is a bijection f:V(G)E(G){1,2,,|V(G)|+|E(G)|} such that for all subgraphs H isomorphic to H, the H-weights, w(H)=vV(H)f(v)+uvE(H)f(uv) form an arithmetic progression {a,a+d,,a+(k1)d} where a>0,d0 are two fixed integers and k is the number of subgraphs of G isomorphic to H. Moreover, if the vertex set V(G) receives the minimum possible labels {1,2,,|V(G)|}, then f is called a super (a,d)-H-antimagic total labeling. In this paper we study super (a,d)-Cn-antimagic total labeling of a disconnected graph, namely mCn.

1 Introduction

Let G and H be finite, undirected and simple graphs. Let V(G),V(H),E(G) and E(H) be the vertex set of G, the vertex set of H, the edge set of G and the edge set of H, respectively. Let |V(G)|=pG, |V(H)|=pH, |E(G)|=qG and |E(H)|=qH. A graph G admits an H-covering if every edge of G belongs to at least one subgraph H that is isomorphic to H.

Gutiérrez and Lladó [Citation1] defined an H-magic labeling of a graph as a generalization of a magic valuation by Kotzig and Rosa [Citation2]. An H-magic total labeling of a graph G admitting an H-covering is a bijection f:V(G)E(G){1,2,,|V(G)|+|E(G)|} such that for all subgraphs H isomorphic to H, w(H)=vV(H)f(v)+uvE(H)f(uv) is a constant. Moreover, if f has an additional property f(V(G))={1,2,,|V(G)|}, then f is called an H-supermagic total labeling. A graph G that admits an H-(super)magic total labeling is called H-(super)magic.

Meanwhile, Simanjuntak, Bertault, and Miller [Citation3] define an (a,d)-edge-antimagic total labeling for a graph G(V,E) as a bijection f from V(G)E(G) onto the set {1,2,,|V(G)|+|E(G)|} such that the edge-weights w(uv) defined by w(uv)=f(u)+f(uv)+f(v), uvE(G), constitute an arithmetic sequence {a,a+d,,a+(|E(G)|1)d} for some positive integers a and d. Inspired by the two previous concepts, Inayah, Salman, and Simanjuntak [Citation4] introduced an (a,d)-H-antimagic total labeling of a graph. Let G be a graph that admits an H-covering. An (a,d)-H-antimagic total labeling of a graph G is a bijection f:V(G)E(G){1,2,,|V(G)|+|E(G)|} such that for all subgraphs H isomorphic to H, the H-weights, w(H)=vV(H)f(v)+uvE(H)f(uv) form an arithmetic progression {a,a+d,,a+(k1)d} where a>0,d0 are two fixed integers and k is the number of subgraphs of G isomorphic to H. In this condition, G is said to be (a,d)-H-antimagic. Particularly, if f(V(G))={1,2,,|V(G)|}, then f is called a super (a,d)-H-antimagic total labeling. In this condition, G is said to be super (a,d)-H-antimagic.

Many results about super (a,d)-H-antimagic total labeling have been found. For instances, in [Citation5] Inayah et al. proved that shack (H,k) is super (a,d)-H-antimagic. Laurence and Kathiresan [Citation6] investigated super (a,d)-Ph-antimagic total labeling of stars. Susilowati et al. [Citation7] studied super (a,d)-Cn-antimagic total labeling for ladder graph. Meanwhile, cycle-super antimagicness of tensor product of graphs has been studied by Purnapraja et al. [Citation8].

In this paper we investigate the existence of super (a,d)-Cn-antimagic total labeling of one kind of disconnected graphs, namely the disjoint union of m copies of cycles denoted by mCn.

2 An upper bound of d for super (a,d)-H-antimagic graphs

Lemma 1

Let G and H be graphs and let k2 be the number of subgraphs of G that is isomorphic to H. If G is super (a,d)- H-antimagic, then dpH(pGpH)+qH(qGqH)k1

Proof

Let |V(G)|=pG, |E(G)|=qG, |V(H)|=pH and |E(H)|=qH. Since G is super (a,d)-H-antimagic, the minimum H-weight is at least 1+2++pH+(pG+1)+(pG+2)++(pG+qH)=pH(pH+1)2+qH(pG+1)+(pG+qH)2. Hence, (1) apH(pH+1)+qH((pG+1)+(pG+qH))2(1) On the other hand, the maximum H-weight is at most pG+(pG1)++(pG(pH1))+(pG+qG)+(pG+qG1)++(pG+qG(qH1))=pH(pG+(pG(pH1)))2+qH((pG+qG)+(pG+qG(qH1)))2. Therefore, (2) a+(k1)dpH(pG+(pG(pH1)))2+qH((pG+qG)+(pG+qG(qH1)))2(2) By combining (Equation(1)Equation(2)), we obtain (k1)dpH(pGpH)+qH(qGqH)Since k2, dpH(pGpH)+qH(qGqH)k1

3 Super (a,d)-Cn-antimagic total labeling of mCn

In this section we present super (a,d)-Cn-antimagic total labeling of mCn. Let GmCn be the disjoint union of m copies of Cn with V(G)={vij|1in,1jm} and E(G)={vijvi+1j|1in1,1jm}{vnjv1j|1jm}.

Observation 2

It follows from Lemma 1 that if mCn is super (a,d)- Cn-antimagic, where m2 and n3, then d2n2.

In the next theorem, we give a necessary condition for mCn to be super (a,d)-Cn-antimagic.

Theorem 3

For m2,n3, if mCn super (a,d)- Cn-antimagic, then

(i)

d is odd and m is odd, or

(ii)

d is even and m is arbitrary

Proof

Let f:V(mCn)E(mCn){1,2,,2mn} be a super (a,d)-Cn-antimagic total labeling of mCn. The sum of Cn-weights is a+a+d++(m1)d. On the other hand, in the computation of Cn-weights, the label of each vertex and edge of G are counted once. Therefore, we obtain the following equation vV(mCn)f(v)+uvE(mCn)f(uv)=w(Cn) mn(1+mn)2+mn(mn+1+2mn)2=m(a+a+(m1)d)2 a=n(2mn+1)(m1)d2 The value a is an integer if and only if (i) d is odd and m is odd, or (ii) d is even and m is arbitrary.  □

In the following theorem we prove the existence of super (a,d)-Cn-antimagic total labeling of mCn.

Theorem 4

mCn has a super n(2mn+1)(m1)d2,d- Cn-antimagic total labeling for m2,n3, and d{0,2,4,,2n}

Proof

Define a total labeling f:V(G)E(G){1,2,,|V(G)|+|E(G)|} in the following way.

For d=0

f(vij)=m(i1)+j,for 1in and 1jm

f(vijvi+1j)=m(n+i)j+1,for 1in1 and 1jm

f(vnjv1j)=2mnj+1,for 1jm

For d={2,4,,2n4}

f(vij)=m(i1)+j,for 1in and 1jm

f(vijvi+1j)=m(n+i1)+j,for 1id2 and 1jmm(n+i)j+1,for d2+1in1 and 1jm

f(vnjv1j)=2mnj+1,for 1jm

For d=2n2

f(vij)=m(i1)+j,for 1in and 1jm

f(vijvi+1j)=m(n+i1)+j,for 1in1 and 1jm

f(vnjv1j)=2mnj+1,for 1jm

For d=2n

f(vij)=m(i1)+j,for 1in and 1jm

f(vijvi+1j)=m(n+i1)+j,for 1in1 and 1jm

f(vnjv1j)=m(2n1)+j,for 1jm

Clearly, f(V(G)){1,2,,|V(G)|}. Next, let Cn(1),Cn(2),,Cn(m) be the subgraphs of G with V(Cn(j))={vij|1in,1jm} and E(Cn(j))={vijvi+1j|1in1,1jm}{vnjv1j|1jm}. Then, consider the following cases for the Cn-weights as follows.

For d=0

It can be checked that for 1jm, w(Cn(j))=i=1nf(vij)+i=1n1f(vijvi+1j)+f(vnjv1j)=n(2mn+1)(m2j+1)d2

For d={2,4,,2n4}

It can be checked that for 1jm, w(Cn(j))=i=1nf(vij)+i=1n1f(vijvi+1j)+f(vnjv1j)=n(2mn+1)(m2j+1)d2

For d=2n2

It can be checked that for 1jm, w(Cn(j))=i=1nf(vij)+i=1n1f(vijvi+1j)+f(vnjv1j)=n(2mn+1)(m2j+1)d2

For d=2n

It can be checked that for 1jm, w(Cn(j))=i=1nf(vij)+i=1n1f(vijvi+1j)+f(vnjv1j)=n(2mn+1)(m2j+1)d2

From all cases above, we can see that w(Cn(j)), 1jm, build an arithmetic sequence with first term a=n(2mn+1)(m1)d2 and common difference d{0,2,4,,2n}. Therefore, for m2,n3, and d{0,2,4,,2n}, mCn has a super n(2mn+1)(m1)d2,d-Cn-antimagic total labeling.  □

Theorem 5

mCn has a super ((2n2n1)m+2(n+1)1,2n+2)- Cn-antimagic total labeling for m2,n3

Proof

Define a total labeling f:V(G)E(G){1,2,,|V(G)|+|E(G)|} in the following way.

For m2 and n=3

f(vij)=2j+i12(m1)1+i,for 1i2 and 1jm2m+j,for i=3 and 1jm

f(vijvi+1j)=m(i+2)+j,for 1i2 and 1jm

f(v3jv1j)=5m+j,for 1jm

For m2,n>3 and n is odd

f(vij)=2j+i12(m1)1+i,for 1in1 and 1jmm(n1)+j,for i=n and 1jm

f(vijvi+1j)=m(n+i1)+j,for 1in+32 and 1jmm(n+i)j+1,for n+32+1in1 and 1jm

f(vnjv1j)=2mnj+1,for 1jm

For m2,n>3 and n is even

f(vij)=2j+i12(m1)1+i,for 1in and 1jm

f(vijvi+1j)=m(n+i1)+j,for 1in+22 and 1jmm(n+i)j+1,for n+22+1in1 and 1jm

f(vnjv1j)=2mnj+1,for 1jm

Clearly, f(V(G)){1,2,,|V(G)|}. Next, let Cn(1),Cn(2),,Cn(m) be the subgraphs of G with V(Cn(j))={vij|1in,1jm} and E(Cn(j))={vijvi+1j|1in1,1jm}{vnjv1j|1jm}. Then, we get the Cn-weights as follows.

For m2 and n=3

It can be checked that for 1jm, w(Cn(j))=i=1nf(vij)+i=1n1f(vijvi+1j)+f(vnjv1j)=(2n2n1)m+2j(n+1)1

For m2,n>3 and n is odd

It can be checked that for 1jm, w(Cn(j))=i=1nf(vij)+i=1n1f(vijvi+1j)+f(vnjv1j)=(2n2n1)m+2j(n+1)1

For m2,n>3 and n is even

It can be checked that for 1jm, w(Cn(j))=i=1nf(vij)+i=1n1f(vijvi+1j)+f(vnjv1j)=(2n2n1)m+2j(n+1)1

w(Cn(j)), 1jm, build an arithmetic sequence starting from (2n2n1)m+2(n+1)1 with difference 2n+2. Therefore, the graph mCn, for m2,n3, has a super ((2n2n1)m+2(n+1)1,2n+2)-Cn-antimagic total labeling.  □

Theorem 6

mCn has a super (n(2mn+1)n2(m1),2n2)- Cn-antimagic total labeling for m2,n3

Proof

Define a total labeling f:V(G)E(G){1,2,,|V(G)|+|E(G)|} in the following way.

f(vij)=n(j1)+i,for 1in and 1jm

f(vijvi+1j)=n(m+j1)+i,for 1in1 and 1jm

f(vnjv1j)=n(m+j),for 1jm

Clearly, f(V(G)){1,2,,|V(G)|}. Next, let Cn(1),Cn(2),,Cn(m) be the subgraphs of G with V(Cn(j))={vij|1in,1jm} and E(Cn(j))={vijvi+1j|1in1,1jm}{vnjv1j|1jm}. Then, we get the Cn-weights as follows. w(Cn(j))=i=1nf(vij)+i=1n1f(vijvi+1j)+f(vnjv1j)=n(2mn+1)n2(m2j+1) w(Cn(j)), 1jm, build an arithmetic progression {n(2mn+1)n2(m1),n(2mn+1)n2(m3),,n(2mn+1)n2(1m)}. Therefore, the graph mCn, for m2,n3, has a super (n(2mn+1)n2(m1),2n2)-Cn-antimagic total labeling.  □

Open Problem 1

For arbitrary m2 and n3, determine a super (a,d)- Cn-antimagic total labeling of mCn for the remaining even d{2n+4,2n+6,,2n22}

Open Problem 2

For odd m3 and arbitrary n3, determine a super (a,d)- Cn-antimagic total labeling of mCn for odd d{1,3,,2n21}

Notes

Peer review under responsibility of Kalasalingam University.

References

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