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Section A

On the average distance of the hypercube tree

Pages 1208-1216 | Received 17 Nov 2006, Accepted 21 Mar 2008, Published online: 14 Oct 2008
 

Abstract

Given a graph G on n vertices, the total distance of G is defined as σ G=(1/2) ∑ u, vV(G) d(u, v), where d(u, v) is the number of edges in a shortest path between u and v. We define the d-dimensional hypercube tree T d and show that it has a minimum total distance σ (T d )=2σ (H d )−=(dn 2/2)− over all spanning trees of H d , where H d is the d-dimensional binary hypercube. It follows that the average distance of T d is μ(T d )=2 μ(H d )−1=d (1+1/(n−1))−1.

2000 AMS Subject Classification: :

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