Abstract
Given a graph G on n vertices, the total distance of G is defined as σ G=(1/2) ∑
u, v∈V(G)
d(u, v), where d(u, v) is the number of edges in a shortest path between u and v. We define the d-dimensional hypercube tree T
d
and show that it has a minimum total distance σ (T
d
)=2σ (H
d
)−=(dn
2/2)−
over all spanning trees of H
d
, where H
d
is the d-dimensional binary hypercube. It follows that the average distance of T
d
is μ(T
d
)=2 μ(H
d
)−1=d (1+1/(n−1))−1.