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Articles

On best linear and Bayesian linear predictor in calibration

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Pages 3669-3693 | Received 29 Jul 2019, Accepted 21 Jul 2020, Published online: 31 Aug 2020
 

Abstract

The availability of some prior information, along with the current, may help us to improve the properties of statistical techniques. In this study, Bayesian best linear predictor is derived for simple and multivariate calibration situations. A comparative study of the mean squared errors of the Bayesian best linear predictor and the best linear predictor (classical) shows that Bayesian best linear predictor performs equally well. Interval estimates, both for known and unknown parameters, of the best linear predictor have been considered using different pivotal functions and different distributions for p(t). The outcomes have shown that the error probabilities depend upon N,BN,CN and to some extent on ρ, the same invariants upon which the mean squared error of the estimator depends.

Acknowledgements

The authors are grateful to the anonymous reviewers for their valuable suggestions that helped in improving the initial version of the manuscript.

Appendix. Mean squared error

There are two situations. i:α, β andΓ known; it is just of theoretical nature. ii: α, β andΓ unknown; it is the most practical situation.

  1. α, β and Γ known MSE = E[T -(C + DTX)]2 σ2 -  DTCOV(T,X) = σ2[1 - σ2βT(Γ + σ2ββT)-1β] σ2(1 - ρ2)

  2. MSE=E(T Ĉ D̂T X)2=EE[(T Ĉ D̂T X)2|Ĉ,D̂]

The expression E[(T Ĉ D̂T X)2|ĈD̂ is quadratic in Ĉ, D̂ and is minimized by Ĉ=C and D̂= and its minimum is σ2 (1ρ2). Thus E[(T Ĉ D̂T X)2|ĈD̂]=(ĈCD̂D)TM(ĈCD̂D)+ σ2 (1ρ2).

Here M is a (q+1)×(q+1 symmetric matrix i.e., M=[1EX1..EXqEx12..EX1Xq.....EXq2]

Now MSE=σ2 (1ρ2)+E trace MN, here N= (D̂DĈC)(ĈCD̂T-DT). Finally MSE=E(C^−C)2+2(EX1)E(C^-C)(D^1-D1)++2(EXq)E(C^-C)(D^q-Dq)+E(X12)E(D^1-D1)2++2(EX1Xq)E(D^1-D1)(D^q-Dq)+++(EXq2)E(D^q-Dq)2+σ2(1ρ2)

For q=p=1, it reduces to simple linear calibration and  MSE=(1ρ2)σ2(1+Qs).

Using Taylor series Qs is Q= ρ2N+1N2[2ρ2(1ρ2)+(12ρ2)CN+ρ2BN]  

It depends only on four invariants i.e., N, BN, C and ρ2. Here N is size of the experiment;C=(N2)σ2/STT, relative concentration of the experiment; B=(N2)(tμ)2/STT, relative bias of the experiment and ρ2 is squared correlation coefficient.

According to Muhammad and Riaz (Citation2016) MSE/σ2 in an invariant quantity and depends only on N, BN, CN,ρ and q as mean squared error in univariate case is MSE=E(C^C)2+2(EX)E(C^C)(D^D)+(EX2)E(D^D)2+(1ρ2)σ2 MŜEσ2= (1 ρ̂2)(1 +Q̂s)

Where Q̂s=E(ĈC)2+2(EX)E(ĈC)(D̂D)+(EX2)E(D̂D)2(1ρ2)σ2 SoQ̂s=MŜEσ2(1ρ̂2 )1

For the multivariate case mean squared error is MSE=E(C^C)2+2(EX1)E(C^C)(D^1D1)+...+2(EXq)E(C^C)(D^qDq)++(EX12)E(D^1D1)2+...+2(EX1Xq)E(D^1D1)(D^qDq)+...+E(Xq)2E(D^qDq)2+(1ρ2)σ2 Q̂s=MŜEσ2(1ρ̂2 )1

The mean squared error for the Bayesian linear predictor is MSEπ=σ2(1-ρπ2)=σ2(1ρ^2)(1+Qπ)SoQπ=(1ρπ2)1ρ^21

As ρπ2 is a function of the four invariants, N,BN,CN and ρ̂2 so would be the Qπ.

So comparing Qπ and Q̂s is equivalent to comparing MSEπ/σ² and MŜ E/σ². Qπ=(1ρπ2)(1ρ̂2)1=f+(1f)ρ̂2ρ̂2(1ρ̂2)[f+(1f)ρ̂2]1=(1f)ρ̂2f+(1f)ρ̂2=(f1)ρ̂2f(f1)ρ̂2 where f is = (N2)/(Nq3)[1+1/+ {σ²+(μt¯t¯)²}/STT]=(N2)/(Nq3)[1 + 1/+ BN/(N2) + CN/(N2)]

Note that when N is large; MLE or unbiased estimators of Γ are approximately equal to posterior expectationE (Γ ∣ expt.). Also when N is large;t¯ remaining fixed and STT → ∞, then f ≈ 1 Thus Cπ+ DπTX=Ĉ+ D̂TX and MSE = MSEπ

One may see more details of this appendix in Muhammad (Citation1987) and Muhammad and Riaz (Citation2016)

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