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Articles

Integral sum graphs Gn and G-r,n are perfect graphs

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Pages 77-83 | Received 08 May 2023, Accepted 17 Aug 2023, Published online: 04 Sep 2023

Abstract

A graph G is an integral sum graph (sum graph) if its vertices can be labeled with distinct integers (positive integers) so that e = uv is an edge of G if and only if the sum of the labels on vertices u and v is also a label in G. A graph G is perfect if the chromatic number of each of its induced subgraphs is equal to the clique number of the same. A simple graph G is of class 1 if its edge chromatic number and maximum degree are same. In this paper, we prove that integral sum graphs Gn, G0,n and Gr,n over the label sets [1,n],[0,n] and [r,n], respectively, are perfect graphs as well as of class 1 for r,nN. We also obtain a few structural properties of these graphs.

2010MATHEMATICS SUBJECT CLASSIFICATION:

1 Introduction

Harary [Citation6, Citation7] introduced the concepts of sum graphs and integral sum graphs. A graph G is called as an integral sum graph (sum graph) if the vertices of G can be labeled with distinct integers (positive integers) so that e = uv is an edge of G if and only if the sum of the labels on vertices u and v is also a label of a vertex in G. An anti-sum graph is defined [Citation11] as a graph G in which there exist a labeling f:V(G)N such that two vertices are adjacent in G if and only if the sum of their labels is not a label of any vertex in G.

Different notations are used for integral sum graphs by different authors. For any non-empty set S of integers, let G+(S) denote the integral sum graph on the vertex label set S, Gn denote the sum graph for S={1,2,,n} = [1,n],Gr denote the integral sum graph for S = [r,1], the integral sum graph with respect to S=[n,n] is denoted by Gn,n [Citation6, Citation7] which is generalized to Gr,n and G0,n denote the integral sum graph for S = [0,n],r,nN [Citation12]. Throughout this paper, for integral sum graph G+(S), we consider vi as the vertex with integral sum labeling i, iS.

The order of a graph G is |G|, the number of vertices in G. The join of two graphs A and B denoted by A + B is the graph AB together with edges joining each vertex of A with all the vertices of B [Citation14].

Theorem 1.1.

[Citation12] For positive integers r and n, Gr,nK1+(Gr+Gn).

An assignment of colors to the vertices of a graph so that adjacent vertices have the distinct colors is called a proper coloring of the graph. A color class is the set of all vertices with any one color and that is an independent set. The chromatic number χ(G) of a graph G is the minimum number of colors required to color the vertices of G for which G has a proper coloring [Citation5]. Similarly, an assignment of colors to the edges of a graph G in such a way that adjacent edges have distinct colors is termed as proper edge coloring. An edge color class is the set of all edges of G with any single color and it is an independent set of edges. The edge chromatic number χ(G) is defined as the minimum number of colors required to color the edges of G for which G has a proper edge coloring [Citation5]. A simple graph G is class 1 if χ(G) = Δ(G). It is class 2 if χ(G) = Δ(G)+1.

The clique of a graph G is the maximal complete subgraph in G and its order is the clique number of G, denoted by ω(G) [Citation5]. Clearly ω(Kn) = n. Here we denote the clique of the graph G by CG.

A graph G is perfect if for every induced subgraph of G, the clique number and the chromatic number have the same value. Equivalently, for every AV(G),χ(G[A]) = ω(G[A]) [Citation14]. A graph G is 1-perfect if χ(G) = ω(G) [Citation14]. It is also proved that graph G is perfect if and only if every induced subgraph of G is 1-perfect [Citation3].

Theorem 1.2.

[Citation8] The complement of a perfect graph is perfect as well.

Several graphs are proved as perfect [Citation1, Citation4, Citation14]. They include bipartite graphs and their line graphs, chordal graphs, comparability graphs, triangulated graphs, etc. Perfect graphs arise in the statistical competition of block designs and in graph coloring problems. Another application of perfect graphs is the optimal routing of garbage trucks related to urban science problems. The perfect graph is also closely related to perfect channels in communication theory [Citation9].

This paper contains 4 sections. Section 1 contains an introduction and some basic definitions and Section 2 presents a few structural properties which are required to prove results on integral sum graphs Gn, G0,n and Gr,n in the subsequent sections, n,rN. In Section 3, we prove that sum graphs Gn and integral sum graphs G0,n are perfect and in Section 4, we show that integral sum graphs Gr,n are perfect and graphs Gn, G0,n and Gr,n are of class 1 for r,nN.

While studying proper edge coloring of integral sum graphs, we felt that graphs Gn, G0,n and Gr,n must be perfect graphs and that is the motivation for this study.

All graphs we consider in this paper are simple and finite, and we follow Harary [Citation5] for all graph-theoretic notions which are not mentioned here.

2 Preliminaries

In this section, we present a few structural properties of integral sum graphs Gn, G0,n and Gr,n that are required to prove results in the subsequent sections, n,rN.

Theorem 2.1.

[Citation5] (Vizing’s Theorem) For any graph G, the edge chromatic number satisfies the inequalities, Δ(G)χ(G)Δ(G)+1.

A vertex and an edge of a graph are said to cover each other if they are incident [Citation5].

A set of vertices (edges) which covers all the edges (vertices) of a graph G is called a vertex cover (edge cover) for G. Vertex covering number (edge covering number) is the minimum cardinality among all the vertex covers (edge covers) for G and is denoted by α0(G) or α0 (α1(G) or α1) [Citation5].

A set of vertices (edges) in G is independent if none of them are adjacent. The maximum cardinality among all the vertex (edge) independent set is called its vertex independence number (edge independence number) and is denoted by β0(G) or β0 (β1(G) or β1) [Citation5]. We denote the independent set of the graph G by IG.

Theorem 2.2.

[Citation5] For any connected nontrivial graph G of order n, α0(G)+β0(G) = n = α1(G)+β1(G).

Lemmas 2.3

and 2.4 are related to clique, minimum vertex cover, minimum edge cover, maximum independent set and maximum matching and are given without proof since the proofs are obvious.

Lemma 2.3.

For every nN, the integral sum graph Gn has

  1. Clique of Gn, CGn = {viV(Gn):i=1,2,3,,n2}

and ω(Gn) = n2.
  1. Minimum vertex cover of Gn = {viV(Gn):i=1,2,3,,n21}

and α0(Gn) = n21.

  1. Maximum independent set of Gn, IGn = {viV(Gn):i=n2,n2+1,n2+2,,n}

and β0(Gn) = n2+1.

  1. Maximum matching of Gn = {vivjE(Gn):(i,j)=(1,n1),(2,n2),, (n21,n2)}

and β1(Gn) = n21.

  1. Any sum graph G+(S) has no edge cover since the vertex corresponding to the biggest label which is a natural number is an isolated vertex in G+(S). In particular, Gn has no edge cover, nN.

Lemma 2.4.

For every integral sum graph Gr,n,r,nN, we have

  1. Clique of Gr,n,

CGr,n={viV(Gr,n):i=r2,,2,1,0,1,2,,n2} and ω(Gr,n)=1+r2+n2.

  1. Minimum vertex cover of Gr,n={{viV(Gr,n):i=r,,1,0,1,,n21}ifrn.{viV(Gr,n):i=r2+1,,1,0,1,,n}ifrn.

and α0(Gr,n) = min{r,n}+ max {r,n}2.
  1. Maximum independent set of Gr,n = {{viV(Gr,n):i=n2,n2+1,,n1,n}ifrn.{viV(Gr,n):i=r,r+1,,r2}ifrn.

and β0(Gr,n) = max {r,n}2+1.

  1. Minimum edge cover of Gr,n = {{vivjE(Gr,n):i+j=nr}ifkis even.{vivjE(Gr,n):i+j=nr & (i,j)=(0,nr2)}if kis odd. = {{vivjE(Gr,n):(i,j)=(r,n),(r+1,n1),,(0,nr)}ifkis even.{vivjE(Gr,n):(i,j)=(r,n),(r+1,n1),,(0,nr)&(0,nr2)} ifkis odd.

and α1(Gr,n) = r+n+12 where k = r+n+1.

  1. Maximum matching of Gr,n = {vivjE(Gr,n):i+j=nr}

and β1(Gr,n) = r+n+12.

Note 2.5. By putting r = 0 in Lemma 2.4, we obtain the corresponding properties of G0,n,nN.

Note 2.6. In the integral sum graph Gr,n of even order, every maximum matching is a perfect matching for r,nN{0}.

For any integral sum graph Gn, G0,n or Gr,n, maximum independent set, minimum vertex cover, minimum edge cover, and maximum matching need not be unique but clique is unique, r,nN.

3 Sum graphs Gn and Integral sum graphs G0,n are perfect

In this section, we prove that for nN, sum graphs Gn and integral sum graphs G0,n are perfect.

Theorem 3.1.

For a positive integer n, the sum graph Gn is perfect.

Proof.

Let Gn be the sum graph of order n obtained by the labeling f:V(Gn)N defined by f(vi)=i,1in. Let H be any induced subgraph of Gn. Our aim is to prove that χ(H)= ω(H) for all subgraphs H of Gn where χ(H) is the chromatic number of H and ω(H) is its clique number.

Gn is a split graph with clique CGn = {viV(Gn):i=1,2,,n2} and the independent set IGn={viV(Gn):i=n2,n2+1,n2+2,,n}. To prove the theorem we consider the following three cases of H.

Case 1. V(H)V(CGn).

Every induced subgraph of a clique is another clique of order fewer than or equal to the maximal clique. And thereby H itself a clique and χ(H)= ω(H).

Case 2. V(H)V(IGn).

Induced subgraph of an independent set is also an independent set and the clique number of any induced subgraph of an independent set is 1. This implies, χ(H)= ω(H) = 1 for every V(H)V(IGn).

Case 3. V(H)V(CGn)V(IGn).

In this case, vertices of H belong to either CGn or IGn. Let V(H) = V(CH)V(IH) where V(CH)CGn and V(IH)IGn,V(CH),V(IH). Let ω(H)=k. This implies that |CH| = k = χ(CH) where CH is the clique in H. If H itself is a clique, then H = CH and thereby χ(H) = ω(H) = k. Hence the result is true in this case. If H is not a clique, let ω(H) = k. This implies, χ(CH) = |CH| = k.

For each vertex vjV(IH), there exists atleast one viV(CH) such that vivjE(H) (since i+j>n) so that there will not be a clique of higher order than that of CH and thus vi and vj can be assigned with the same color. That is, the colors used in CH are enough for coloring V(IH). This implies, χ(H)= χ(CH) = k. Hence we get χ(H) = k = ω(H).

Thus in all the three cases we obtain χ(H) = ω(H) for every induced subgraph H of Gn and thereby graph Gn is perfect for nN. □

Illustration 3.2. Consider the sum graph G13 as given in . Vertices v1,v2,v3,v4,v5,v6 and v7 (vertices joined by edges with blue color) form a clique in G13 and ω(G13)=7. These vertices are colored by the colors c1,c2,,c7. All the remaining vertices are nonadjacent to v7 and so, they can be colored by c7. Or, the vertices v8,v9,v10, v11,v12 and v13 are nonadjacent to the vertices v6,v5,v4,v3,v2 and v1 respectively, and can be colored by the corresponding colors c1,c2,,c6. Therefore, the chromatic number of the sum graph G13 is 7. i.e., χ(G13) = 7 = ω(G13). Thus G13 is 1-perfect. Clearly every pair of nonadjacent vertices in G13 are also nonadjacent in any of its induced subgraphs. This shows that every induced subgraph of G13 is 1-perfect. This implies, graph G13 is 1-perfect and thereby G13 is perfect.

Fig. 1 G13: vertex coloring and clique.

Fig. 1 G13: vertex coloring and clique.

Corollary 3.3.

For every positive integer n, graph Gnc is perfect.

Proof.

The proof follows from Theorems 3.1 and 1.2. □

Theorem 3.4.

For every nN,

  1. the chromatic number of Gn is n2;

  2. the edge chromatic number of G1 is 0 and for n2, the edge chromatic number of Gn is n – 2.

i.e., χ(G1) = 0 and for n2,χ(Gn) = n – 2.

Proof.

The sum graph Gn is obtained by the labeling f:V(Gn)N defined by f(vi)=i, i = 1 to n.

  1. From Theorem 3.1, Gn is perfect and thereby the chromatic number of Gn is equal to its clique number. This implies, χ(Gn) = ω(Gn) = n2. Hence we get the result (i). Vertex coloring and clique of G13 are shown in .

  2. For n = 1, Gn is an empty graph and thus the edge chromatic number χ(G1) = 0.

For n2, the maximum degree of sum graph Gn is Δ(Gn) = n – 2. Using Theorem 2.1, we have, Δ(Gn)χ(Gn)Δ(Gn)+1. Here, we present the edge coloring of the sum graph Gn with exactly n – 2 colors so that χ(Gn)=n2,n2.

Let ck denote kth color assigned to an edge and Ck denote the color class of edges each with color ck in Gn, n2. Color the set of edges {vivjE(Gn):i+j=k+2,1i,jn,ij} of Gn with the color ck.

It is clear from the above edge coloring that colors c1 to cn2 are assigned to the edges of Gn and no more edge colors are required. And all the colors of edges incident at each vertex vi of sum graph Gn are all distinct since there are exactly n – 2 possibilities of j, ij,1jn for which i+j=k+2 in Gn, 1kn2. This implies, χ(Gn) = n – 2 for n2. Hence we get the result (ii). □

Illustration 3.5. Consider the sum graph G13. The vertices v1,v2,v3,v4,v5,v6 and v7 in G13 (vertices joined by edges with blue color) form a clique, ω(G13) = 7 and Δ(G13) = 11. Since G13 is perfect, χ(Gn) = ω(G13) which implies, χ(Gn) = 7 = 132. As in the proof, color the set of edges {vi,vjE(Gn):i+j=k+2,1i,jn, ij} of Gn with the color ck. The colors of each edge of G13 is given as follows. c1v1v2; c2v1v3; c3v1v4,v2v3; c4v1v5,v2v4; c5v1v6,v2v5,v3v4; c6v1v7,v2v6,v3v5; c7v1v8,v2v7,v3v6,v4v5; c8v1v9,v2v8,v3v7,v4v6; c9v1v10,v2v9,v3v8,v4v7,v5v6; c10v1v11,v2v10,v3v9,v4v8,v5v7; c11v1v12,v2v11,v3v10,v4v9,v5v8,v6v7.

See with the edge coloring of G13 with 11 colors using the method given in the proof of Theorem 3.4. Here, χ(G13)=11=132.

Fig. 2 G13: edge coloring.

Fig. 2 G13: edge coloring.

Results are available for the composition of perfect graphs which allows different types of graph operations [Citation2]. But the graph operation join is not available yet. Following is the result corresponding to join of two perfect graphs.

Theorem 3.6.

Join of two perfect graphs is also perfect.

Proof.

Let G and F be two perfect graphs with χ(G) = ω(G) = p and χ(F) = ω(F) = q. Also let J = G + F, the join of the graphs G and F. When we take the join of two graphs G and F, the clique in G together with clique in F form a higher clique of order p + q. i.e., ω(J) = p + q. Let H be any induced subgraph of J. We have to prove that χ(H)= ω(H).

Let ω(H) = k and let CH be the clique in H of order k. Then ω(H) = |CH| = k = χ(CH). That is CH can be colored using k colors.

Let D=V(H)V(CH). For each vj DV(G) and vy DV(F), there exist vi V(CH)V(G) and vx V(CH)V(F) such that vivj,vxvyE(H) so that there does not exist a clique of higher order than that of CH. Hence, the colors of vi and vx can be assigned to vj and vy, respectively. And thereby the vertices of D can be colored using the colors of vertices of CH. This implies, χ(H) = χ(CH) = ω(H). Thus, for every induced subgraph H of J, χ(H) = ω(H). Thus the graph J is perfect. □

Theorem 3.7.

For every nN, the integral sum graph G0,n is perfect.

Proof.

The integral sum graph G0,n = K1 + Gn where K1 = G1 is labeled with 0. Then using Theorems 3.1 and 3.6, the graph G0,n is perfect, nN. □

shows the clique in G0,12 and its vertex coloring.

Fig. 3 G0,12: vertex coloring and clique.

Fig. 3 G0,12: vertex coloring and clique.

Theorem 3.8.

For every nN, the integral sum graph G0,n has

  1. the chromatic number χ(G0,n) = n2+1;

  2. the edge chromatic number χ(G0,n) = n.

Proof.

The integral sum graph G0,n is obtained by the labeling f:V(G0,n)N{0} defined by f(vi)=i, i = 0 to n.

  1. Using Theorem 1.1, G0,nK1+Gn which implies, χ(G0,n) = χ(K1) + χ(Gn) = 1+n2 using Theorem 3.4

  2. For nN, the maximum degree of integral sum graph G0,n is Δ(G0,n) = n. Using Theorem 2.1, we get, Δ(G0,n)χ(G0,n)Δ(G0,n)+1. Now, we present a proper edge coloring of G0,n with n colors so that χ(G0,n) = n.

Let ck denote kth color assigned to an edge and Ck denote the color class of edges, each with color ck in G0,n,nN. Color all the edges in the set {vivjE(G0,n):i+j=k, 0i,jn, ij,1kn} with the same color ck. Clearly, the edges of G0,n take at the most n colors since 1i+jn. Also, there are n edges incident at the vertex v0, and all these n edges take n distinct colors. That is, χ(G0,n) = n, nN. See for the edge coloring of G0,12 and it can be done as the illustration 3.5 for G13. □

Fig. 4 G0,12: edge coloring.

Fig. 4 G0,12: edge coloring.

4 Integral sum graphs Gr,n are perfect

In this section, we prove that for r,nN, (i) integral sum graphs Gr,n are perfect; (ii) the chromatic number of Gr,n = 1+r2+n2 and (iii) the edge chromatic number of Gr,n = r + n. These results are illustrated by examples.

Theorem 4.1.

For r,nN, the integral sum graph Gr,n is perfect.

Proof.

Using Theorem 1.1, Gr,nK1+(Gr+Gn)K1+(Gn+Gr)(K1+Gn)+GrGo,n+Gr since join operation is associative as well as commutative among undirected graphs. Graphs Gr and Gr are isomorphic without vertex labeling and so both are perfect by Theorems 3.1 whereas G0,n is perfect by Theorem 3.7 for r,nN. Therefore using Theorem 3.6, graph Go,n+Gr is perfect for r,nN. This implies, graph Gr,nGo,n+Gr is perfect for r,nN. □

Illustration 4.2. Consider the integral sum graph G5,7 given in . Vertices v1,v2,v3,v4,v0,v1,v2,v3 (Vertices joined by the edges with magenta color) in G5,7 form a clique. Thus, ω(G5,7) = 8. These vertices can be colored by 8 distinct colors, say c1,c2,c3,c4,c5,c6,c7,c8, respectively. Vertices v4 and v5 are nonadjacent to v3 and can be colored by c8, the color of v3. Vertices v7, v6 and v5 are nonadjacent to v4 and can be colored by c4. Therefore, χ(G5,7) = 8. This implies, G5,7 is 1-perfect. Likewise we can show that every induced subgraph of G5,7 is 1-perfect. This implies, graph G5,7 is perfect.

Fig. 5 G5,7: vertex coloring.

Fig. 5 G−5,7: vertex coloring.

Theorem 4.3.

[Citation13] For nN,

  1. χ(G1,1) = 3.

  2. χ(G1,n) = n + 1 for n2.

  3. χ(Gn,n) = 2n for 2n6.

In [Citation13] (also see [Citation10]), Vilfred proposed Theorem 4.4 (ii) as a conjecture and here we provide a proof.

Theorem 4.4.

For r,nN,

  1. the chromatic number of Gr,n is χ(Gr,n) = 1+r2+n2;

  2. the edge chromatic number of Gr,n is χ(Gr,n) = r + n.

Proof.

For rin and r,nN, let f:V(Gr,n)Z defined by f(vi)=i be the integral sum labeling of the graph Gr,n.

  1. For r,nN, integral sum graph Gr,n is perfect by Theorem 4.1. Therefore χ(Gr,n) = ω(Gr,n) = 1+r2+n2 follows from Lemma 2.4. Hence the result is true in this case. shows the vertex coloring and clique in G5,7.

  2. For r,nN, the maximum degree of integral sum graph Gr,n is Δ(Gr,n) = r + n. And using Theorem 2.1, we get, Δ(Gr,n)χ(Gr,n)Δ(Gr,n)+1. Here we present a proper edge coloring of the integral sum graph Gr,n with r + n colors so χ(Gr,n)=r+n for r,nN.

Let ck denote kth color assigned to an edge and Ck denote the color class of edges, each with color ck in Gr,n,r,nN. For r,nN, color the edges of Gr,n as follows.

v0vj cj, 1jn; i.e., edge v0vj is taking color cj, 1jn; v0vici+n,1ir;

vivjci+j, 1ir and 1jn1;

vivnc2i+n, 1ir2;

vivncir2, r2<ir,n>r2;

vivncir2, r2<ir2+n1,nr2;

vivnc2(ir2)n+1, r2+nir,nr2;

vivjci+j+r, 1i,j,i+jn and i < j and

vivjci+j+n, 1i,j,i+jr and i < j.

It is clear from the above edge coloring that colors c1 to cn+r are assigned to the edges of Gr,n and no more edge colors are required. And also colors of edges at each vertex of Gr,n are all distinct by the following. By Theorem 1.1, we have Gr,nK1+(Gr+Gn). Also, Gr+GnGrGnKr,n.

In Gr,n, colors c1, c2, …, cn+r are assigned to the n + r edges incident at the vertex v0.

In Kr,n, we get the following possible colors taken by its edges incident at each of its vertices under the coloring already assigned to the edges of Gr,n.

  1. For 1jn1, distinct colors cj+1,cj+2, …, cj+r are assigned to the r edges incident at vj. And these colors are also different from color cj of the edge v0vj at v0.

  2. For n>r2, distinct colors c2+n,c4+n, …, c2(r21)+n,c2r2+n,c1,c2,,crr2 are assigned to the r edges incident at vn and these colors are different from color cn of the edge v0vn at vn. Clearly, 2r2+n r + n and thus the colors assigned are from the r + n colors only.

  3. For nr2, distinct colors c2+n,c4+n, …, c2(r21)+n,c2r2+n,c1,c2,,cr2+n1,cn+1,cn+3,,c2r2n+1 are assigned to the r edges incident at vn and these colors are different from color cn of the edge v0vn at vn. Clearly, 2r2+n,2r2n+1 r + n and atmost r + n colors are assigned.

  4. For 1ir2, distinct colors ci+1,ci+2, …, ci+n1,c2i+n are assigned to the n edges incident at vi. And all these colors are different from color ci+n of the edge v0vi at vi.

  5. For n>r2 and r2<ir, distinct colors ci+1,ci+2, …, ci+n1,cir2 are assigned to the n edges incident at vi and all these colors are different from color ci+n of the edge v0vi at vi.

  6. For nr2 and r2<ir2+n1, distinct colors ci+1,ci+2, …, ci+n1,cir2 are assigned to the n edges incident at vi and all these colors are different from color ci+n of the edge v0vi at vi.

  7. For nr2 and r2+nir, distinct colors ci+1,ci+2, …, ci+n1,c2(ir2)n+1 are assigned to the n edges incident at vi and all these colors are different from color ci+n of the edge v0vi at vi.

Thus, in the above edge coloring of Gr,n, edges of Kr,n take colors from the r + n colors and colors of edges incident at each vertex of Kr,n are all distinct.

In Gn, for 1i,jn,ij and 3i+jn, color of edge vivj is ci+j+r and thereby edges of Gn are taking colors only from the colors c3+r,c4+r, …, cn+r; edge colors ci+j+r at vi are all distinct and also different from ci of the edge v0vi at vi as well as that of other possible colors of edges which incident at vi in Gr,n where ij and 3i+jn. The same arguments also hold when i and j are interchanged.

In Gr, for 1i,jr,ij and 3i+jr, color of edge vivj is ci+j+n and thereby edges of Gr are taking colors only from the colors c3+n,c4+n, …, cr+n; edge colors ci+j+n at vi are all distinct and also different from ci+n of the edge v0vi at vi as well as that of other possible colors of edges which incident at vi in Gr,n where ij and 3i+jr. The same arguments also hold when i and j are interchanged in this case.

Thus, in the above edge coloring, edges of Gr,n takes only r + n number of colors and colors of edges incident at each vertex of Gr,n are all distinct and thereby χ(Gr,n) = r+n  since  Δ(Gr,n)χ(Gr,n)Δ(Gr,n)+1 by Theorem 2.1. □

Illustration 4.5. Consider the integral sum graph G8,3, the case where nr2. We know Δ(G8,3) = 11. Using the algorithm given in the above proof, we can color the edges of G8,3 as follows. c1v0v1,v5v3; c2v0v2,v1v1,v6v3; c3v0v3,v1v2,v2v1; c4v0v1,v2v2,v3v1,v7v3; c5v0v2,v1v3,v3v2,v4v1; c6v0v3,v1v2,v4v2,v5v1,v8v3; c7v0v4,v1v3,v2v3,v5v2,v6v1; c8v0v5,v1v4,v2v3,v6v2,v7v1; c9v0v6,v1v5,v2v4,v3v3,v7v2,v8v1; c10v0v7,v1v6,v2v5,v3v4,v8v2; c11v0v8,v1v7,v2v6,v3v5,v4v3,v1v2.

See for the edge coloring of G8,3. Here we colored the integral sum graph G8,3 using 11 colors. That is, χ(G8,3) = 11 = 8 + 3. Similarly the integral sum graph G5,7, the case where n>r2, can be colored using 12 colors by the algorithm given in the above proof. That is χ(G5,7) = 12 = 5 + 7. See for the edge coloring of G5,7.

Fig. 6 G5,7 with edge coloring.

Fig. 6 G−5,7 with edge coloring.

Fig. 7 G8,3 with edge coloring.

Fig. 7 G−8,3 with edge coloring.

Theorem 4.6.

For positive integers r and n, integral sum graphs Gn, G0,n and Gr,n are of class 1.

Proof.

Using Theorems 3.4, 3.8 and 4.4, we get χ(Gn) = n – 2 = Δ(Gn) = degree of the vertex with label 1, χ(G0,n) = n = Δ(G0,n) = degree of the vertex with label 0 and χ(Gr,n) = r + n = Δ(Gr,n) = degree of the vertex with label 0. □

Acknowledgments

The first, second and fourth authors express their sincere gratitude to the Central University of Kerala, Periye, Kasaragod - 671316, Kerala, India for providing facilities to carry out this research work. Also, the authors are thankul to the anonymous reviewers for their valuable comments and suggestions to improve the presentation of the paper.

Disclosure statement

The authors declare that there is no conflict of interests regarding the publication of this paper.

Additional information

Funding

The first author would like to acknowledge her gratitude to the University Grants Commission (UGC), India, for providing financial support in the form of Junior Research fellowship (Ref. No.: 19/06/2016(i)EU-V). The second author would like to acknowledge her gratitude to the Council of Scientific and Industrial Research (CSIR), India, for the financial support under the CSIR Junior Research Fellowship scheme.

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