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Research Article

Convoluted fractional differentials of various forms utilizing the generalized Raina's function description with applications

ORCID Icon & ORCID Icon
Pages 432-441 | Received 08 Mar 2022, Accepted 20 Apr 2022, Published online: 05 May 2022

Abstract

A generalized differential operator utilizing Raina's function is constructed in light of a certain type of fractional calculus. We next use the generalized operators to build a formula for analytic functions of type normalized. Our method is based on the concepts of subordination and superordination. As an application, a class of differential equations involving the suggested operator is studied. As seen, the solution is provided by a certain hypergeometric function. We also create a fractional coefficient differential operator. Its geometric and analytic features are discussed. Finally, we use the Jackson's calculus to expand the Raina's differential operator and investigate its properties in relation to geometric function theory.

2020 Mathematics Subject Classifications:

1. Introduction

Fractional calculus has grown in popularity in recent years, thanks to its applications in science and engineering. Fifty-first-order differential equations are used to model almost all nonlinear physical processes. In terms of the Mittag–Leffler function and its extensions, all classes of fractional differential equations have solutions in terms of this function (the Queen Function of Fractional Calculus) (see [Citation1–3]).

Basic power sums and polynomials, particularly the Mittag–Leffler function and its generalizations (Raina's function), as well as polynomials and their implications, are recognized to have extensive applications in various areas of number theory, such as the theory of partitions. Vector calculus, statistical studies, particle physics, optics, fluid studies, mechanical studies, quantum theory and applications, thermal study, and measurements all benefit from these functions (see [Citation4–12]). This function has been investigated in different types of inequalities and convex inequalities. Shu-Bo Chen et al. [Citation13] presented an integral formula inequality containing the Raina's function. Chu et al. [Citation14] generalized harmonically ψ-convex with respect to Raina's function on fractal set. Rashid et al. [Citation15] extended the Mittag–Leffler kernel. Mohammed et al. [Citation16–18] introduced various studies on the generalized Mittag–Leffler kernel.

In this study, we look at how Raina's function Aα,βμ(ζ)=n=0μ(n)Γ(αn+β)ζn may be used to extend a differential operator in the open unit disk. The fractional differential operator is employed to explain a variety of innovative normalized analytic functions. Therefore, we utilize the convolution product between the normalized Raina's function and analytic function satisfying the normalization equality χ(0)=χ(0)1=0. To investigate a collection of differential inequalities, the concept of differential subordination and superordination is employed. Furthermore, we investigate the geometric behaviour of the diffusive wave differential equation, a family of analytic functions. The novel convolution linear operator is used for a variety of applications.

2. Approaches

In this section, we'll go through the approaches we employed.

2.1. Geometric approaches

We'll go over some geometric function theory fundamentals covered in this book [Citation19]

Definition 2.1

Introduce the set K:={ζC:|ζ|<1}, which indicates the open unit disk. The analytic functions χ1,χ2 in K are subordinated χ1χ2 or χ1(ζ)χ2(ζ),ζKif for an analytic function ψ,|ψ||ζ|<1 fulfilling χ1(ζ)=χ2(ψ(ζ)),ζK.

Definition 2.2

Define the subclass of analytic functions χ(ζ)=ζ+n=2anζn,ηKdenoting by Λ and satisfying χ(0)=χ(0)1=0.

Moreover, two functions ϕ,φΛ are convoluted (ϕφ) if they achieve the product [Citation20] (ϕφ)(ζ)=(ζ+n=2ϕnζn)(ζ+n=2φnζn)=ζ+n=2ϕnφnζn.

Definition 2.3

Related to this class, the class S of starlike functions and the class C of convex functions. Moreover, the class P:={ρ:ρ(ζ)=1+ρ1ζ+ρ2ζ2+,ζK} is a special class of analytic functions in K with positive real part in K and ρ(0)=1.

2.2. Raina's function

Integrals and outcomes of many kinds of differential equations fall within the category of special functions. As a result, most integral sets contain descriptions of special functions, and these special functions entail the most fundamental integrals; at the very least, the integral representation of special functions. Because symmetries of differential equations are significant in both physics and mathematics, the theory of special functions is closely connected to several mathematical physics issues [Citation21]. To begin, we'll look at the Mittag–Leffler function, which is a well-known special function.

Definition 2.4

The power of the generalized Mittag–Leffler function is as follows: [Citation4] Lα,βμ(ζ)=n=0(μ)nΓ(αn+β)ζnn!,where Γ(ζ)=0χζ1eχdχ,(ζ)>0is the gamma function and (μ)n=Γ(μ+1)Γ(μn+1)is the Pochhammer operator. Obviously, we have [Citation10] Lα,β1(ζ)=n=0ζnΓ(αn+β).

Continue by defining Raina's function.

Definition 2.5

The power series determines Raina's function as follows [Citation22]: Aα,βμ(ζ)=n=0μ(n)Γ(αn+β)ζn,ζK,where α>0,β1 and μ:={μ(0),μ(1),,μ(n)} is a bounded sequence of positive real numbers.

Remark 2.6

  • If μ(n)=1, then we have Lα,β1(ζ);

  • If μ(n)=(μ)nn!, then we obtain Lα,βμ(ζ);

  • If α=1,β=1,μ(n)=(a)n(b)n(c)n, then we receive the hypergeometric function 2G1(a,b;c;ζ)=n=0(a)n(b)n(c)nζnΓ(n+1).

Utilizing the function Aα,βμ(ζ), we the convolution operator, for χΛ Aα,βμχ(ζ)=(Γ(α+β)μ(1))(Aα,βμχ)(ζ)=((Γ(α+β)μ(1))μ(0)+ζ+n=2(Γ(α+β)μ(1))(μ(n)Γ(αn+β))ζn)(ζ+n=2anζn)=ζ+n=2(Γ(α+β)Γ(αn+β))(μ(n)μ(1))anζn:=ζ+n=2nanζn,where n:=(Γ(α+β)Γ(αn+β))(μ(n)μ(1)).(χΛ,ζK,α>0,β1,μ={μ(0),,μ(n)})Now by using the Sàlàgean derivative [Citation23], we have Aα,βμχ(ζ)=ζ+n=2nanζnAα,βμ,2χ(ζ)=ζ+n=2nnanζnAα,βμ,kχ(ζ)=ζ+n=2nknanζn.Clearly, Aα,βμ,kχ(ζ)Λ. As a result, the Raina fractional differential operator can be studied geometrically.

Remark 2.7

 

  • The linear operator Aα,βμχ(ζ) is a natural transform of the analytic function χ(ζ) (χ(ζ)Aα,βμχ(ζ)). The Raina's summation, which is a generalization of the Mittag–Leffler summation, is the name for this function Lαχ(ζ)n=0anΓ(1+αn)ζn.And the Borel's summation Bχ(ζ)n=0ann!ζn.

  • In the geometric function theory, the operator Aα,βμχ(ζ) is a generalization of the well-known linear Carlson–Shaffer operator [Citation24], when α=β=1, and μ(n)=(1)n()n()nsuch that (,c)χ(ζ)=n=0((1)n()nΓ(n+1)(c)n)anζn.

  • When μ(n)=Γ(αn+β) for all n1, we obtain the well known the Sàlàgean differential operator [Citation23] Aα,βμ,kχ(ζ)=ζ+n=2nkanζn.

2.3. Preparatory

The conclusions of this investigation into the differential subordination theory are established using the following preliminaries:

Lemma 2.8

[Citation19]

Suppose that f(ζ) and g(ζ) are convex univalent defining in K with f(0)=g(0). In addition, for a constant ξ0,(ξ)0, the subordination f(ζ)+(1/ξ)ζf(ζ)g(ζ)yields f(ζ)g(ζ).

Lemma 2.9

[Citation19]

Define the general class of analytic functions Π[,n]={υ:υ(ζ)=+nζn+n+1ζn+1+},where C and n is a positive integer. If ıR, then {υ(ζ)+ıζυ(ζ)}>0(υ(ζ))>0.Furthermore, if ı>0 and υΠ[1,n], then there occurs two positive numbers ξ1>0 and ξ2>0 satisfying the relation υ(ζ)+ıζυ(ζ)(1+ζ1ζ)ξ1implies υ(ζ)(1+ζ1ζ)ξ2.

Lemma 2.10

see [Citation25]

Let ,υΠ[,n], where υ is convex univalent in K and for v1,v2C,v20, then v1(ζ)+v2ζ(ζ)v1υ(ζ)+v2ζυ(ζ)(ζ)υ(ζ).

Lemma 2.11

see [Citation26]

Let υ,Π[,n], where ℘ is convex univalent in K and the functional υ(ζ)+ωζυ(ζ) is univalent for ω>0. Then (ζ)+ωζ(ζ)υ(ζ)+ωζυ(ζ)(ζ)υ(ζ).

Lemma 2.12

[Citation27]

Assume that ℏ analytic in K fulfilling (0)=0. Then the upper value of ℏ on the circle |ζ|=1 at the point ζ0=reiθ,θ[π,π],0<q<1 is ζ0(ðq(ζ0))=ı(ζ0),ı1,where ðq represents the Jackson fractional derivative (or quantum fractional derivative).

3. Outcomes

In this study, we formulate the next class of normalized analytic functions and study its properties in view of the geometric function theory.

Definition 3.1

A function χΛ is called to be in the class Ωα,βμ,k(ς,ρ) if it fulfils the inequality (1) (1ςζ)[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)]ρ(ζ).(ζK,ς[0,1],ρ(0)=1,α>0,β1),(1) where ρ is convex univalent in K.

Obviously, the convex univalent function ρ(ζ)=Aζ+1Bζ+1,is a member in the class P:={ρK:ρ(η)=1+n=1ρiζn}.Consider the functional Σχ:KK, as in the following structure: (2) Σχ(ζ):=(1ςζ)[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)](2) Based on Definition 3.1, we have the following inequality: Σχ(ζ)Aζ+1Bζ+1,ζK.Our study is as follows:

3.1. Inequalities outcomes

We start with the next property of Raina' s operator.

Theorem 3.2

Let χΩα,βμ,k(ς,ρ) such that {Σχ(ζ)}={(1ςζ)[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)]}:={1+n=1σn}>0Then the inequality is fully filled by the coefficient boundaries of Σχ with the probability measure dω(θ): |σn|202π|einθ|dω(θ),Moreover, if (eiυΣχ(ζ))>0,ζK,υRthen χΩα,βμ,k(Aζ+1Bζ+1) and Σχ(ζ)=Aζ+1Bζ+1,ξK,|A|=|B|=1.

Proof.

Since (Σχ(ζ))=(1+n=1σnζn)>0,then Σχ(ζ) is a Carathéodory function in the open unit disk. Continuously, the Carathéodory positivist methodology brings that |σn|202π|einθ|dω(θ),where dω is a probability measure. Additionally, if (eiυΣχ(ζ))>0,ζK,υRthen in virtue of [Citation20, Theorem 1.6] and for fixed number υR, we get ρ(ζ)=Aζ+1Bζ+1,ζK,|A|=|B|=1.Moreover, we have from the proof of [Citation20, Theorem 1.6] Σχ(ζ)ρ(ζ)0,and that such that the range (Σχρ)(K) i s contained in the interior of ρ(K). This yields 0(Σχρ)(K). Hence, χΩα,βμ,k(ς,Aζ+1Bζ+1).

The next outcomes indicate the necessary and sufficient method for the functional sandwich theory.

Theorem 3.3

Let the following conditions hold: (3) ςζ[Aα,βμ,kχ(ζ)]+[Aα,βμ,kχ(ζ)]p2(ζ)+ζp2(ζ),(3) where p2(0)=1 and convex in K. Additionally, assume that Σχ(ζ) is univalent in K such that ΣχΠ[p1(0),1]O, where O presents the set of all univalent analytic functions g with limζOg and (4) p1(ζ)+ζp1(ζ)ςζ[Aα,βμ,kχ(ζ)]+[Aα,βμ,kχ(ζ)].(4) Then p1(ζ)Σχ(ζ)p2(ζ)and p1(ζ) is the best sub-dominant and p2(ζ) is the best dominant.

Proof.

Let Σχ(ζ)=(1ςζ)[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)].A computation implies Σχ(ζ)+ζΣχ(ζ)=ς[Aα,βμ,kχ(ζ)]+ζ(ςζ[Aα,βμ,kχ(ζ)](ς1)[Aα,βμ,kχ(ζ)])+(ς1)[Aα,βμ,kχ(ζ)]ζ+(1ς)[Aα,βμ,kχ(ζ)]ζ=ςζ[Aα,βμ,kχ(ζ)]+[Aα,βμ,kχ(ζ)].As a result, the following double inequality is obtained p1(ζ)+ζp1(ζ)Σχ(ζ)+ζΣχ(ζ)p2(ζ)+ζp2(ζ).As a conclusion, the desired result is yielded by Lemmas 2.10 and 2.11.

Theorem 3.4

Let Σχ(ζ)=(1ς)ζ[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)]then (Aα,βμ,kχ(ζ)]ζ)ε1+[Aα,βμ,kχ(ζ)][ε1+3ε2]+ε2ζ[Aα,βμ,kχ(ζ)](1+ζ1ζ)ξ1Σχ(ζ)(1+ζ1ζ)ξ2.(ξ1>0,ξ2>0,ε1=1ς,ε2=ς>0)

Proof.

A computation yields Σχ(ζ)+ζΣχ(ζ)=(1ς)ζ[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)]+ζ((1ς)ζ[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)])=([Aα,βμ,kχ(ζ)]ζ)ε1+[ε1+3ε2][Aα,βμ,kχ(ζ)]+ε2ζ[Aα,βμ,kχ(ζ)](1+ζ1ζ)ξ1According to Lemma 2.9 with ı=1, we get Σχ(ζ)(1+ζ1ζ)ξ2.

3.2. Fractional differential equation

In this part, we continue our study using the convolution linear operator. We formulate the operator to present a generalized formula of the diffusive wave differential equation. When inertial acceleration is substantially lower than all other sources of acceleration, or when there is mostly sub-critical flow with low Froude values, the diffusive wave is viable.

In light of the suggested operator, we utilize the class Ωα,βμ,k(ς,1+ζ1ζ) to develop a class of fractional diffusive wave differential equations. We look at the upper bound of the diffusive wave equation. The formula is as follows: (5) (1ςζ)[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)]=Aζ+1Bζ+1,([Aα,βμ,kχ(0)]=0,ς[0,1],ζK).(5) The solution to (Equation5) is given by the following result.

Theorem 3.5

Let χΩα,βμ,k(ς,1+ζ1ζ). Then (Equation5) has a solution expressed by (6) [Aα,βμ,kχ(ζ)]=ζ(2ζ2G1(1,1+1ς,2+1ς,ζ)ς+1+1),(6) where 2G1(a,b,c;ζ) indicates the hypergeometric function.

Proof.

Assume that χΩα,βμ,k(ς,1+ζ1ζ). Then it satisfies the differential equation (1ςζ)[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)]=φ(ζ)+11φ(ζ),where φ is a Schwarz function with the property: |φ||ζ|<1 and φ(0)=0. Now, by using Schwarz lemma, equality φ(ζ)=σζ,|σ|=1 (see [Citation28, Theorem 5.34]) implies the differential equation (1ς)ζ[Aα,βμ,kχ(ζ)]+ς[Aα,βμ,kχ(ζ)]=ζ+11ζ.Rearrange the above equation, we have [Aα,βμ,kχ(ζ)]+1ςςζ[Aα,βμ,kχ(ζ)]=(1ς)(1+ζ1ζ).Multiply the above equation by the functional T(ζ)=exp(1ςςζdζ)=ζ1ςς,we have ζ1ςς[Aα,βμ,kχ(ζ)]+(1ςς)ζ12ςς[Aα,βμ,kχ(ζ)]=(1ς)(1+ζ1ζ).ζ1/ς1[Aα,βμ,kχ(ζ)][Aα,βμ,kχ(ζ)]((1ς)ζ1/ς2)ς=(ζ1/ς1ς)(1+ζ1ζ).The solution of the above first-order differential equation is [Aα,βμ,kχ(ζ)]=ζ(2ζ2G1(1,1+1ς,2+1ς,ζ)ς+1+1),where 2G1(a,b,c;ζ) indicates the hypergeometric function. This completes the proof.

Example 3.6

Let χΩα,βμ,k(ς,1+ζ1ζ), where ς=1/2. Then in view of Theorem 3.5, we get the solution [Aα,βμ,kχ(ζ)]=ζ(4ζ2G1(1,3,4,ζ)3+1)=ζ+1.3ζ2+ζ3+0.8ζ4+0.67ζ5+0.57ζ6+O(ζ7),|ζ|<1.

3.3. First order differential operator

In the next study, we employ the Raina's operator to define a new generalized differential operator.

Definition 3.7

For non-negative real numbers λ let [[λ]] be the integer part of λ. For χΛ, and by employing the Raina's operator [Aα,βμ,kχ(ζ)], we have the following extended linear differential operator: (7) Aλ[Aα,βμ,kχ(ζ)]=Aλ[[λ]](A[[λ]][Aα,βμ,kχ(ζ)])=k1(λ[[λ]],ζ)k1(λ[[λ]],ζ)+k0(λ[[λ]],ζ)×(A[[λ]][Aα,βμ,kχ(ζ)])+k0(λ[[λ]],ζ)k1(λ[[λ]],ζ)+k0(λ[[λ]],ζ)×(ζ(A[[λ]][Aα,βμ,kχ(ζ)]),(7) where for ν=λ[[λ]][0,1), A0[Aα,βμ,kχ(ζ)]=[Aα,βμ,kχ(ζ)]Aν[Aα,βμ,kχ(ζ)]=k1(ν,ζ)k1(ν,ζ)+k0(ν,ζ)[Aα,βμ,kχ(ζ)]+k0(ν,ζ)k1(ν,η)+k0(ν,ζ)(ζ[Aα,βμ,kχ(ζ)])=k1(ν,ζ)k1(ν,η)+k0(ν,ζ)[ζ+n=2nnkanζn]+k0(ν,ζ)k1(ν,ζ)+k0(ν,ζ)([ζ+n=2nnk+1anζn])=ζ+n=2(k1(ν,ζ)+nk0(ν,ζ)k1(ν,ζ)+k0(ν,ζ))nknanζn:=ζ+n=2κnnknanζnA1[Aα,βμ,kχ(ζ)]=ζ([Aα,βμ,kχ(ζ)]),,A[[λ]][Aα,βμ,kχ(ζ)]=A1(A[[λ]]1[Aα,βμ,kχ(ζ)]),where κn:=(k1(ν,ζ)+nk0(ν,ζ)k1(ν,ζ)+k0(ν,ζ));and the functions k1,k0:[0,1]×KK are analytic in K with k1(ν,ζ)k0(ν,ζ),limν0k1(ν,ζ)=1,limν1k1(ν,ζ)=0,k1(ν,ζ)0,ζK,ν(0,1),and limν0k0(ν,ζ)=0,limν1k0(ν,ζ)=1,k0(ν,ζ)0,ζK,ν(0,1).

It is clear that, for constant coefficients, Aν[Aα,βμ,kχ(ζ)]Λ. For example k0(ν,ζ)=ν and k1(ν,ζ)=1ν.

Clearly, if λ assumes only non-negative integer values, that is if λ[[λ]]=0,α=β=1,μ(n)=n!,n1, then we have the Sàlàgean differential operator [Citation23]. We also have the differential operator in [Citation29], which is based on the same assumptions. In this section, we examine the geometric properties of the complex conformable derivative (Equation7) when applied to functions with a positive real portion.

Theorem 3.8

For a fixed number ε(0,1) and λ[0,) let k0(λ[[λ]],ζ)=(ε1ε)k1(λ[[λ]],ζ).Then Aλ+2[Aα,βμ,kχ(ζ)]Aλ+1[Aα,βμ,kχ(ζ)]PAλ+1[Aα,βμ,kχ(ζ)]Aλ[Aα,βμ,kχ(ζ)]P.

Proof.

For k0(λ[[λ]],ζ)=ε1εk1(λ[[λ]],ζ) and by Definition 3.7, we get Aγ[Aα,βμ,kχ(ζ)]=(1ε)(A[[λ]][Aα,βμ,kχ(ζ)])+εζ(A[[λ]][Aα,βμ,kχ(ζ)])Aλ+1[Aα,βμ,kχ(ζ)]=ζ(A[[λ]][Aα,βμ,kχ(ζ)])+εζ2(A[[λ]][Aα,βμ,kχ(ζ)])and Aλ+2[Aα,βμ,kχ(ζ)]=ζ(A[[λ]][Aα,βμ,kχ(ζ)])+(1+2ε)×λ2(A[[λ]][Aα,βμ,kχ(ζ)])+εζ3(A[[λ]][Aα,βμ,kχ(ζ)]).Obviously, we obtain (Aλ+2[Aα,βμ,kχ(ζ)]Aγ+1[Aα,βμ,kχ(ζ)])>0if and only if {1+(1+ε)ζ(A[[λ]][Aα,βμ,kχ(ζ)])+εζ2(A[[λ]][Aα,βμ,kχ(ζ)])(A[[λ]][Aα,βμ,kχ(ζ)])+εζ(A[[λ]][Aα,βμ,kχ(ζ)])}>0.Accordingly, if and only if (8) {1+ζ[(1ε)(A[[λ]][Aα,βμ,kχ(ζ)])+εζ(A[[λ]][Aα,βμ,kχ(ζ)])][(1ε)(A[[λ]][Aα,βμ,kχ(ζ)])+εζ(A[[λ]][Aα,βμ,kχ(ζ)])]}>0.(8) The convexity of a function is obtained by combining the inequality Equation8 with the idea of convex functions: (1ε)(A[[λ]][Aα,βμ,kχ(ζ)])+εζ[A[[λ]][Aα,βμ,kχ(ζ)]].But all convex functions are starlike, then we obtain that (9) {ζ[(1ε)(A[[λ]][Aα,βμ,kχ(ζ)])+εζ(A[[λ]][Aα,βμ,kχ(ζ)])](1ε)(A[[λ]][Aα,βμ,kχ(ζ)])+εζ(A[[λ]][Aα,βμ,kχ(ζ)])}>0.(9) The inequality Equation9 occurs if and only if (Aλ+1[Aα,βμ,kχ(ζ)]Aλ[Aα,βμ,kχ(ζ)])>0and this ends the proof.

The main condition to put on the operator A[[λ]][Aα,βμ,kχ(ζ)] is computed by our second theorem, for the functional Aλ+1[Aα,βμ,kχ(ζ)]ζ(A[[λ]][Aα,βμ,kχ(ζ)])to be of positive real part.

Theorem 3.9

For a positive number ε(0,1) and λ[0,) let k1(λ[[λ]],ζ)=(ε1ε)k0(λ[[λ]],ζ).If A[[λ]][Aα,βμ,kχ(ζ)]C, then Aλ+1[Aα,βμ,kχ(ζ)]ζ(A[[λ]][Aα,βμ,kχ(ζ)])P(ϵ).

Proof.

Applying the differential operator rule to Aλ+1[Aα,βμ,kχ(ζ)]=A(Aλ[Aα,βμ,kχ(ζ)])implies (10) Aλ+1[Aα,βμ,kχ(ζ)]=Aλ[[λ]](A[[λ]]+1[Aα,βμ,kχ(ζ)])=Aλ[[λ]]{A[A[[λ]][Aα,βμ,kχ(ζ)]}=Aλ[[λ]]{ζ[A[[λ]][Aα,βμ,kχ(ζ)]]}=k1(λ[[λ]],ζ)k1(λ[[λ]],ζ)+k0(λ[[λ]],ζ)×{ζ[A[[λ]][Aα,βμ,kχ(ζ)]]}+k0(λ[[λ]],ζ)k1(λ[[λ]],ζ)+k0(λ[[λ]],ζ)×{ζ[(A[[λ]][Aα,βμ,kχ(ζ)])+ζ(A[[λ]][Aα,βμ,kχ(ζ)])]}=k1(λ[[λ]],ζ)k1(λ[[λ]],ζ)+k0(λ[[λ]],ζ)×{ζ[A[[λ]][Aα,βμ,kχ(ζ)]]}+k0(λ[[λ]],ζ)k1(λ[[λ]],ζ)+k0(λ[[λ]],ζ)×{ζ[A[[λ]][Aα,βμ,kχ(ζ)]]}+k0(λ[[λ]],ζ)k1(λ[[λ]],ζ)+k0(λ[[λ]],ζ)×{ζ2[A[[λ]][Aα,βμ,kχ(ζ)]]}=ζ[A[[λ]][Aα,βμ,kχ(ζ)]]+k0(λ[[λ]],ζ)k1(λ[[λ]],ζ)+k0(λ[[λ]],ζ)×{ζ2[A[[λ]][Aα,βμ,kχ(ζ)]]}.(10) Dividing Equation Equation10 by the term ζ(A[[λ]][Aα,βμ,kχ(ζ)]) and utilizing the relation k1(λ[[λ]],ζ)=(ε1ε)k0(λ[[λ]],ζ),we get Aλ+1[Aα,βμ,kχ(ζ)]ζ(A[[λ]][Aα,βμ,kχ(ζ)])=1+(1ε)ζ(A[[λ]][Aα,βμ,kχ(ζ)])(A[[λ]][Aα,βμ,kχ(ζ)]).The convexity of A[[λ]][Aα,βμ,kχ(ζ)], it becomes {1+ζ(A[[λ]][Aα,βμ,kχ(ζ)])(A[[λ]][Aα,βμ,kχ(ζ)])}>0.Hence, it yields that {Aλ+1[Aα,βμ,kχ(ζ)]ζ(A[[λ]][Aα,βμ,kχ(ζ)])}>ε.This ends the proof.

3.4. Quantum starlike methodology

Quantum calculus (QC) is a novel field of mathematical analysis and its applications, with applications in physics and mathematics. Jackson [Citation30, Citation31] originally defined and enhanced the functions of q-differentiation and q-integration. The geometric function theory idea of q-calculus was later incorporated by Ismail et al. [Citation32]. QC is now being used by researchers to propose and build new Ma and Minda classes. Seoudy and Aouf [Citation33] suggested a quantum starlike function subclass based on q-derivatives. Recently, Zainab et al. [Citation34] employed a novel curve to create appropriate q-stralikeness criteria. Different types of q-stralik functions dominated by a 2D-Julia set were explored by Samir et al. [Citation35]. Furthermore, QC is used to generalize a variety of differential and integral operators [Citation36–42].

Definition 3.10

The Jackson derivative may be shown using the difference operator below. (11) (ðq)p(ζ)=p(ζ)p(qζ)ζ(1q),q(0,1)(11) such that ðq(ζc)=(1qc1q)ζc1.The total of the numbers is also included in the Maclaurin's series representation. (12) (ðqp)(ζ)=k=0pk[k]qζk1,(12) where [k]q:=1qk1q.

Note that ðq=0,limq1(ðqp)(ζ)=p(ζ),where ∁ is a constant. Then there's the multiplication rule, which is formulated by multiplying two numbers together ðq(p1(ζ)p2(ζ))=p2(ζ)ðqp1(ζ)+p1(qζ)ðqp2(ζ)=p2(qζ)ðqp1(ζ)+p1(ζ)ðqp2(ζ).We then use the q-parametric Mandelbrot function to formulate our q-starlike class, linking it to the normalized function subclass in the process K (13) G()(ζ)=+ζ2(C,ζK).(13) We aim to investigate the sufficient conditions on the two parameters ℓ and q to obtain the q-starlike function.

Theorem 3.11

Assume that K with (0)=1 and (14) 1+ζ(ðq(ζ))1+ζ,ζK.(14) If for some positive constant j achieves the inequalities (15) ȷ>1+32,0<q2ȷ24ȷ12ȷ2,(15) then for some C, we have (16) (ζ)G()(ζ)=+ζ2.(16)

Proof.

Formulate a function by (ζ):=1+ζ(ðq(ζ)).The condition (Equation14) implies that 1+ζ(ðq(ζ))=1+υ(ζ),(υ(0)=0,|υ(ζ)||ζ|<1)A computation gives υ(ζ)=2(ζ)1.Our aim is to show that |υ(ζ)|=|2(ζ)1|<1,where ζ0K satisfying (ζ)=[+υ2(ζ)].Consume not; if so, the preceding conclusion applies (η)=1+η(ðq[+υ2(η)]).Employing Jackson's derivative principles as well as the formula υ(qζ)=υ(ζ)(1q)ζðqυ(ζ),and ðqυ2(ζ)=ðqυ(ζ)[2υ(ζ)(1q)ζðqυ(ζ)],we obtain (ζ)=1+ζðqυ(ζ)[2υ(ζ)(1q)ζðqυ(ζ)].Consider the existence of a point ζ0K such that max|ζ||ζ0||υ(ζ)|=|υ(ζ0)|=1and ζ0(ðqυ(ζ0))=ȷυ(ζ0),ȷ1.We proceed to prove |υ(ζ)|=|2(ζ)1|<1,utilizing Jack Lemma 2.12.

Letting υ(ζ0)=eiθ, we get |2(ζ)1|=|1+2t[1+ζðqυ(ζ)[2υ(ζ)(1q)ζðqυ(ζ)]]+[1+ζðqυ(ζ)[2υ(ζ)(1q)ζðqυ(ζ)]]21|ζ=ζ0=|2+2ζðqυ(ζ)[2υ(ζ)(1q)ζðqυ(ζ)]+1+2ζðqυ(ζ)[2υ(ζ)(1q)ζðqυ(ζ)]+[ζðqυ(ζ)[2υ(ζ)(1q)ζðqυ(ζ)]]2|ζ=ζ0=|3+2ζ0ðqυ(ζ0)[2υ(ζ0)(1q)ζ0ðqυ(ζ0)]+2ζ0ðqυ(ζ0)[2υ(ζ0)(1q)ζ0ðqυ(ζ0)]+[ζ0ðqυ(ζ0)[2υ(ζ0)(1q)ζ0ðqυ(ζ0)]]2|=|3+2ȷυ(ζ0)[2υ(ζ0)(1q)ȷυ(ζ0)]+2ȷυ(ζ0)[2υ(ζ0)(1q)ȷυ(ζ0)]+[ȷυ(ζ0)[2υ(ζ0)(1q)ȷυ(ζ0)]]2||3+4ȷυ2(ζ0)[2(1q)ȷ]|=|3+4ȷe2iθ[2(1q)ȷ]|1,where ȷ>1+32,2ȷ24ȷ12ȷ2q<1,which contradicts (Equation15). Hence, we obtain (Equation16).

The following examples involve the Raina' s operator.

Example 3.12

For a positive number ε(0,1) and λ[0,) let k1(λ[[λ]],ζ)=ε1εk0(λ[[λ]],ζ).

  • If A[[λ]][Aα,βμ,kχ(ζ)]C, then in view of Theorem 3.9, we have (ζ):=Aλ+1[Aα,βμ,kχ(ζ)]ζ(A[[λ]][Aα,βμ,kχ(ζ)])P(ϵ).That is (0)=1. Moreover, if 1+ζðq(Aλ+1[Aα,βμ,kχ(ζ)]ζ(A[[λ]][Aα,βμ,kχ(ζ)]))1+ζ,where q satisfies (Equation15) then according to Theorem 3.11 Aλ+1[Aα,βμ,kχ(ζ)]ζ(A[[λ]][Aα,βμ,kχ(ζ)])G()(ζ).

  • If Aλ+2[Aα,βμ,kχ(ζ)]Aλ+1[Aα,βμ,kχ(ζ)]Pthen in view of Theorem 3.8, we get (ζ):=Aλ+1[Aα,βμ,kχ(ζ)]Aλ[Aα,βμ,kχ(ζ)]P.That is (0)=1. In addition, if 1+ζðq(Aλ+1[Aα,βμ,kχ(ζ)]Aλ[Aα,βμ,kχ(ζ)])1+ζ,where q satisfies (Equation15) then by Theorem 3.11, we have Aλ+1[Aα,βμ,kχ(ζ)]Aλ[Aα,βμ,kχ(ζ)]G()(ζ).

  • Let ϕ(ζ)=[Aα,βμ,kχ(ζ)]ζ,where ϕ(0)=1. If 1+ζðqϕ(ζ)1+ζ,where q achieves the inequality (Equation15) then in virtue of Theorem 3.11, we obtain ϕ(ζ)G()(ζ).

4. Conclusion

Raina's transformations in K were generalized utilizing conformable calculus and Jackson calculus in the above investigation. The Raina's convolution operator is acted on the normalized subclass. As an application, we considered the proposed linear convolution operator in fractional differential equation, type wave equation. The solution of a certain type of diffusion differential equation, which is utilized as a case study, is determined by the hypergeometric function.

More investigation is presented by formulating the Raina's convolution operator in a conformable fractional calculus. We studied the main sufficient conditions to get stralike geometry of the operator (see Theorems 3.8 and 3.9).

Finally, the quantum calculus is utilized to recognize the q-starlike function together with the q-parametric Mandelbort function. As an application, we applied the result using the Raina's convolution operator (see Example 3.12).

Author contributions

All authors contributed equally and significantly to writing this article. All authors read and agreed to the published version of the manuscript.

Disclosure statement

No potential conflict of interest was reported by the author(s).

Data availability statement

Data sharing not applicable to this article as no data-sets were generated or analysed during the current study.

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