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Abstract
We prove that any Lie subgroup G (with finitely many connected components) of an infinite-dimensional topological group which is an amalgamated product of two closed subgroups can be conjugated to one factor. We apply this result to classify Lie group actions on Danielewski surfaces by elements of the overshear group (up to conjugation).
AMS Subject ClassificationS:
1. Introduction
The motivation of this paper is the study of holomorphic automorphisms of Danielewski surfaces. These are affine algebraic surfaces defined by an equation in
, where
is a polynomial with simple zeros. These surfaces are intensively studied in affine algebraic geometry, and their algebraic automorphism group has been determined by Makar-Limanov [Citation1, Citation2]. More results on algebraic automorphisms of Danielewski surfaces can be found in Refs. [Citation3–7].
From the holomorphic point of view, their study began in the paper of Kaliman and Kutzschebauch [Citation8] who proved that they have the density and volume density property, important features of the so called Andersén–Lempert theory. For definitions and an overview over Andersén–Lempert theory, we refer to Ref. [Citation9].
Another important study in the borderland between affine algebraic geometry and complex analysis is the classification of complete algebraic vector fields on Danielewski surfaces by Leuenberger [Citation10]. In fact we explain in Remark 4.1 how to use his results together with our Classification Theorem 1.3 to find holomorphic automorphisms of Danielewski surfaces which are not contained in the overshear group.
In Ref. [Citation11], we define the notion of an overshear and shear on Danielewski surfaces as follows:
Definition 1.1
A mapping of the form
(or with the role of first and second coordinates exchanged,
) is called an overshear map, where
are holomorphic functions (and the involution I of
is the map interchanging x and y). When
, we say that
is a shear map on
.
These mappings are automorphisms of . The maps of the form
form a group, which we call
. It can be equivalently described as the subgroup of
, leaving the function x invariant. It is therefore a closed subgroup of
(endowed with compact-open topology). Analogously, the maps
form a group, the closed subgroup of
leaving y invariant, which we call
.
The main result of Ref. [Citation11] says that the group generated by overshears, i.e. by and
(we call it the overshear group
), is dense (with respect to the compact-open topology) in the component of the identity of the holomorphic automorphism group
of
. This fact generalizes the classical results of Andersén and Lempert [Citation12] from
. It is worth to be mentioned at this point that
for p of degree 1 is isomorphic to
.
In Ref. [Citation13], the authors together with Andrist proved a structure result of the overshear group.
Theorem 1.2
Theorem 5.1 in Ref. [Citation13]
Let be a Danielewski surface and assume that
, then the overshear group,
, is a free amalgamated product of
and
.
The main result of our paper is a classification result for Lie group actions on Danielewski surfaces by elements of the overshear group.
Theorem 1.3
Let be a Danielewski surface and assume that
. Let a real connected Lie group G act on
by automorphisms in
. Then G is abelian, isomorphic to the additive group
and is conjugated (in
) to a subgroup of
.
The exact formulas for such actions are described in Corollary 3.3.
For the overshear group of (instead of Danielewski surfaces), many results in the same spirit have been proven by Ahern and Rudin [Citation14] for G finite cyclic group, by Kutzschebauch and Kraft [Citation15] for compact G and for one-parameter subgroups in the thesis of Andersén [Citation16] by de Fabritiis [Citation17], Ahern and Forstnerič [Citation18] and Ahern et al. [Citation19]. For Danielewski surfaces, our result is the first of that kind. The proof relies on our second main result, which seems to be of independent interest.
Theorem 1.4
Let be a topological group which is a free amalgamated product
of two closed subgroups O, L. Furthermore, let G be a Lie group with finitely many connected components and
be a continuous group homomorphisms. Then
is conjugate to a subgroup of O or L.
The outline of this paper is the following. In Section 2, we prove Theorem 1.4. In Section 3, we prove Theorem 1.3. In Section 4, we apply Theorem 1.2 to give new examples of holomorphic automorphisms of not contained in the overshear group
.
2. Lie subgroups of a free amalgamated product
The aim of this section is to prove the following theorem. For the notion of amalgamated product, we refer the reader to Ref. [Citation20].
Theorem 2.1
Let be a topological group which is a free amalgamated product
of two closed subgroups O, L. Furthermore, let G be a Lie group with finitely many connected components and
be a continuous group homomorphism. Then
is conjugate to a subgroup of O or L.
We need the following facts:
Proposition 2.2
Every element of a free amalgamated product is conjugate either to an element of O or L or to a cyclically reduced element. Every cyclically reduced element is of infinite order.
Proof.
See Proposition 2 in Section 1.3 in Ref. [Citation20].
Lemma 2.3
A subgroup H of a free amalgamated product is conjugate to a subgroup of O or L if and only if H is of bounded length.
Proof.
This is a direct consequence of Proposition 2.2.
Lemma 2.4
Let and
be two commuting elements of
with lengths
, then
and
are both even or both odd.
Proof.
Assume that and
are two commuting elements. Assume, for a contradiction, that
is even and
is odd. Since
has even length, the first and last element of the chain
have to alter between O and L. Similarly, the first and last element of the chain
s has to be contained in either O or L.
Assume first that and
and that
. Then, since
and
alter between L and O,
. The assumption that
and
are commuting yields that the corresponding length of
has to be the same as the length of
. Clearly,
where
. Hence,
, which contradicts our assumption.
If we assume that and
and that
, a similar contradiction is obtained. In fact,
.
Similar calculations are obtained if and
, where we have to consider both of the cases
and
.
Lemma 2.5
If an element g of a free amalgamated product has roots of arbitrary order, then it is conjugate to an element in O or to an element in L.
Proof.
Assume that g is not conjugate to an element in O or to an element in L. Then, by Proposition 2.2, g is conjugate to a cyclically reduced element, say , which has even length
by definition of a cyclically reduced element. For each n>0, we have that
, since g as roots of arbitrary order. Hence,
is not an element of O or L, since it equals
. Furthermore,
We conclude that
and
commute. Whence, Lemma 2.4 implies that
has even length (since
has even length) and is thus cyclically reduced. Hence,
for all n>0, contradicting the fact that all elements of
have finite length.
First let us establish Theorem 2.1 in the case of a one-parameter subgroup:
Proposition 2.6
Let be a topological group which is a free amalgamated product
of two closed subgroups O and L. Let
be a continuous one-parameter subgroup. Then,
is conjugate to a subgroup of O or L.
Proof.
Since φ is a group homomorphism, we know that and
have roots of all orders. Hence, we can use Lemma 2.5 to conjugate both elements to O or L. Consider the dense subgroup
of
. Since
we conclude that
have bounded length. Therefore, Lemma 2.3 implies that
is conjugate to O or L. Let
be an element such that
is contained in O or L. Finally, as O and L are closed, we get that
is contained in O or L.
The key ingredient in the Proof of Theorem 1.4 will rely on the following result which seems to be of independent interest. In the language of Ref. [Citation21], this means that every Lie group G is uniformly finitely generated by one-parameter subgroups.
Proposition 2.7
For any connected real Lie group G, there are finitely many elements ,
, for which the product map of the one-parameter subgroups
defined by
is surjective.
Proof.
By Levi-Malcev decomposition [Citation22] and Iwasawa decomposition [Citation23], we can write
where S is semisimple, R is solvable, A is abelian, N is nilpotent and K is compact.
If we can prove the claim of the proposition for each of the factors in the above decomposition, we will be done.
For abelian groups, the fact holds trivially.
Case 1: K a compact connected Lie group: Take any basis of the Lie algebra
. Then the product map
is a submersion at the unit element. Thus its image contains an open neighborhood U of the unit element. Since the powers of a neighborhood U of the unit element in any connected Lie group cover the whole group, for a compact Lie group K there is a finite number m such that
. This means that for our purpose
is surjective.
Case 2: Consider N, a nilpotent connected Lie group. Then for the universal covering
and Γ a normal discrete subgroup of
. Since the exponential map for
factors over
, it is enough to prove the claim for simply connected N.
Then, the following fact (due to Malcev [Citation24]) is true: If N is simply connected then for a certain (Malcev) basis of
, the map
is a diffeomorphism. We will now prove the claim by induction of the length of the lower central series of
. For length 1, the group is abelian and the fact holds trivially. Let
. By repeated use of Lemma 2.8, we write
(1)
(1)
with
.
Since has shorter length of lower central series, by the induction hypothesis, each of the factors
is a product of one-parameter subgroup. This proves the claim.
Case 3: R is solvable: Let denote the commutator subgroup of R. Then
is nilpotent and
is abelian. If
is any element, we can per definition write its image
in A as
for some
:s in
which form a basis. Let
denote the quotient map and let
be elements with
. Thus we get
for some
. Since
is nilpotent this reduces our problem to case 2.
Lemma 2.8
For a nilpotent Lie group G with Lie algebra and
, there is
with
Proof.
The key fact is the Baker–Campbell–Hausdorff formula proven by Dynkin [Citation25]. In the nilpotent case, it says that it is a finite sum of iterated Lie brackets (number of iterations of brackets bounded by the lower central series of
) such that for all
Moreover,
. Now
(2)
(2)
Setting
finishes the proof, since the terms without bracket cancel, i.e.
.
Now we are ready to prove the main result of this section.
Proof
Proof of Theorem 1.4.
Let denote a connected component of G containing the identity. By Proposition 2.7, there are finitely many one-parameter subgroups
such that the product map
is surjective. By Proposition 2.6 and Lemma 2.3, the elements of each of the
have bounded length, say
. Thus the length of the elements in
is bounded by
. As G has only finitely many connected components, the lengths of elements of
are bounded. The assertion now follows from Lemma 2.3.
3. Classification of Lie group actions by overshears
In this section, we prove Theorem 1.3 from the introduction. We assume and use Theorem 1.2 from the introduction stating that
is a free amalgamated product
, where
is generated by
and
is generated by
. By Theorem 2.1, we can conjugate any Lie group G with finitely many components acting continuously on
by elements of
into
or
. Without loss of generality, we can assume that we can conjugate any connected Lie subgroup G of
, in particular any one-parameter subgroup, to
. Now we have reduced our problem to classify Lie subgroups of
. We start with one-parameter subgroups.
We recall the definitions of overshear fields and shear fields from Ref. [Citation11].
(V1) | |||||
(V2) |
where f, g are entire functions on . In the special case,
then
is the shear field
.
The set of overshear fields is a Lie algebra which consists of complete vector fields only. The formula for the bracket is given by Equation (Equation4(4)
(4) ).
Any one-parameter subgroup of which is contained in the overshear group
is the flow of an overshear field. Let us prove this. The connection between a vector field
and the flow
is given by the ODE
(3)
(3)
Since any action of a real Lie group on a complex space by holomorphic automorphisms is real analytic [Citation26, 1.6], we can write the flow
contained in
as
for entire functions
and
. Using Equation (Equation3
(3)
(3) ) for
leads to
, an overshear field.
Calculating the commutator, we find that for any f, g, h and k, entire functions on , we have
(4)
(4)
In particular, shear fields commute and
(5)
(5)
Proposition 3.1
Let f, g and h be fixed holomorphic functions with . Then the Lie algebra
generated by
and
is of infinite dimension.
Proof.
By expression (Equation5(5)
(5) ) and the fact that shear fields commute, we get that
Assume that the Lie algebra is of finite dimension. This means that there is an n and there are constants
such that
It follows that b = 0, whence we get a functional equation of the form
where y is holomorphic and has a zero at x = 0. This is impossible for non-zero functions y, since the right-hand side has a higher order of vanishing at x = 0 than the left-hand side.
Proposition 3.2
Let be a Lie algebra contained in
and suppose that
. Then
is abelian.
Proof.
Assume that is not abelian. Let
be two non-commuting vector fields. As explained above, they are overshear fields and since they do not commute, their bracket
is by Equation (Equation4
(4)
(4) ) a nontrivial shear field. Now the result follows from Proposition 3.1.
Proof
Proof of Theorem 1.3.
As explained in the beginning of the section, the action of G on by overshears can be conjugated into
. The action of G by elements of
gives rise to a Lie algebra homomorphism of
into the Lie algebra of vector fields on
fixing the variable x. This Lie algebra is exactly the set of overshear vector fields
(which consists of complete fields only). By Proposition 3.2, the finite dimensional Lie algebra
has to be abelian. Since all one-parameter subgroups of G give rise to an overshear vector field, they are isomorphic to
(not
). Thus G is isomorphic to the additive group
generated by the flows of n linear independent commuting overshear vector fields
which commute. By formula (Equation4
(4)
(4) ), this is equivalent to
. An equivalent way of expressing this is that the meromorphic functions
are the same for all i or that all
are identically zero.
Corollary 3.3
Suppose . Every one-parameter subgroup of
is conjugate by elements of
to the flow of an overshear field
which in turn is given by the formula
Here the expression
for a = 0 is interpreted as the limit of this expression for
, i.e. as b.
Remark 3.1
It is directly seen from Theorem 1.3 that any action of a real Lie group G on extends to a holomorphic action of the universal complexification
, which in our case has just the additive group
as connected component. This is a general fact proven by the first author in Ref. [Citation27].
4. Examples of automorphisms of ![](//:0)
not contained in ![](//:0)
![](//:0)
In Ref. [Citation13], it is shown that the overshear group is a proper subset of the automorphism group. In fact, using Nevanlinna theory, it is shown that the hyperbolic mapping
is not contained in the overshear group. This is analogous to the result by Andersén [Citation28], who showed that the automorphism of
defined by
is not finite compositions of shears. Hence, the shear group is a proper subgroup of the group of volume-preserving automorphisms. For another proof of this fact, see also Ref. [Citation15]. Note that our Classification Theorem 1.3 immediately implies that the elements of the
-action
cannot all be contained in
, since there are no
-actions in
.
We will present yet another way of finding an automorphism of a Danielewski surface which is not a composition of overshears.
Theorem 4.1
Assume that . Then, the overshear group
is a proper subset of the component of the identity of
.
Proof.
We look at complete algebraic vector fields on Danielewski surfaces. These are algebraic vectorfields which are globally integrable, however their flow maps are merely holomorphic maps. As shown in Ref. [Citation29], there is always a - or a
-fibration adapted to these vector fields. That is, there is a map
such that the flow of the complete field θ maps fibers of π to fibers of π. These maps π have general fiber
or
. In case of at least two exceptional fibers, the vector field θ has to preserve each fiber, i.e. it is tangential to the fibers of π. For example, the overshear fields in
have adapted fibration
. They are tangential to this
-fibration, the fibers outside x = 0 are parametrized by
via
. The exceptional fiber is
consisting of
copies of
, one for each zero
of the polynomial p and parametrized by
via
. A typical example of a field with adapted
-fibration is the hyperbolic field
with adapted fibration
. There are
exceptional fibers at the zeros of the polynomial p, each of them isomorphic to the cross of axis xy = 0. The same
-fibration is adapted to the field
for a nontrivial polynomial f.
Now take any complete algebraic vector field θ with an adapted -fibration (and thus generic orbits
). Assume that the flow maps (or time-t maps)
of θ are all contained in the overshear group
. Then by Theorem 1.3, this one-parameter subgroup
can be conjugated into
. This would mean that the one-parameter subgroup would be conjugate to a one-parameter subgroup of an overshear field
(since these are all complete fields respecting the fibration x). This would imply that the generic orbit of the overshear field is
, which is equivalent to
. However, the generic orbits of these fields
(isomorphic to
) are not closed in
, they contain a fixed point in their closure. Thus our assumption that all
are contained in
leads to a contradiction. In particular, we have shown that for any non-zero entire function f, there is a
such that the time t-map of the hyperbolic field given by
is not contained in
.
Remark 4.1
More examples of complete algebraic vector fields on with adapted
-fibration can be found in the work of Leuenberger [Citation10] who up to automorphism classifies all complete algebraic vector fields on Danielewski surfaces. Interesting examples (whose flow maps are not algebraic) are fields whose adapted
-fibration is given by
for coprime numbers
,
and
. The exact formula for these fields can be found in the Main Theorem of loc.cit.
Remark 4.2
Without specifying a concrete automorphism which is not in the group generated by overshears, Andersén and Lempert use an abstract Baire category argument in Ref. [Citation12] to show that the group generated by overshears in is a proper subgroup of the group of holomorphic automorphisms
of
. We do believe that such a proof could work in the case of Danielewski surfaces as well.
Disclosure statement
No potential conflict of interest was reported by the author(s).
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