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Articles

Series representations for generalized harmonic functions in the case of three parameters

Pages 677-694 | Received 20 Nov 2021, Accepted 12 Dec 2022, Published online: 28 Dec 2022

Abstract

We present a canonical series expansion for generalized harmonic functions in the open unit disc in the complex plane that generalizes that recently obtained for the class of (p,q)-harmonic functions.

AMS Subject Classifications:

1. Introduction

Denote by D the open unit disc in the complex plane C and by z=/z and ¯z=/z¯ the usual complex partial derivatives. We shall consider second order partial differential operators of the form (1) Lp,q,r;z=(1|z|2)z¯z+pzz+qz¯¯zr,zD,(1) where p,q,rC are complex parameters. Of particular concern are solutions to the homogeneous equation (2) Lp,q,ru=0inD.(2) A function u is said to be (p,q,r)-harmonic if u is twice continuously differentiable in D and satisfies Equation (Equation2). Recall the Pochhammer symbol ()n defined by (a)n=a(a+1)(a+n1) for n=1,2, and (a)0=1. Commonly referred to below is the familiar Gaussian or hypergeometric function (3) F(a,b,c;z)=n=0(a)n(b)n(c)nznn!,zD,(3) where a,bC and cC{0,1,2,}. A recent publication together with Olofsson [Citation1] concerned a series expansion for (p,q,pq)-harmonic functions in D, or (p,q)-harmonic for short, as they have been called in the case r = pq. Footnote1,Footnote2,Footnote3

As was shown in Theorem 5.1 of that paper, a function u in D is (p,q)-harmonic if and only if it has the form (4) u(z)=m=0cmF(p,mq,m+1;|z|2)zm+m=1cmF(q,mp,m+1;|z|2)z¯m,zD,(4) for some sequence {cm}m= of complex numbers such that lim sup|m||cm|1/|m|1. The sums appearing in (Equation4) are absolutely convergent in the space C(D) of smooth functions, by which we mean C(D)=n=0Cn(D), where Cn(D) is the space of n-times continuously differentiable functions in D for nN. The space C(D) is complete in the topology induced by the semi-norms uj,k;K=maxzK|j¯ku(z)|, where j,kN are non-negative integers and KD is a compact subset of D.

In this paper we extend these ideas and show that a similar such result holds for (p,q,r)-harmonic functions. For this purpose, we follow earlier practice and introduce the m-th homogeneous part for a suitably smooth function u in D and define it by the formula (5) um(z)=12πTeimθu(ez)dθ,zD,(5) for mZ.

We show that (see Theorem 4.3) the m-th homogeneous part of a (p,q,r)-harmonic function u in D has the form um(z)=cmF(χp,q,r,m+,χp,q,r,m,m+1;|z|2)zm,zD, for some cmC when mN is a non-negative integer. The parameters χp,q,r,m+ and χp,q,r,m of the hypergeometric function F in this expression are the zeros of the quadratic polynomial (6) Pp,q,r,m(λ)=λ2λ(mpq)+rpm,λC.(6) The discriminant of this polynomial can be written as (7) Δp,q,r,m=(m+pq)24(rpq).(7) Note that the zeros of the polynomial Pp,q,r,m in (Equation6) are p and mq in the case when r = pq.

A similar formula is given for the m-th homogeneous part um of a (p,q,r)-harmonic function when mZ=ZN is a negative integer. These two results rely on the conclusion (Theorem 2.4) that for each of the homogeneous parts um of a (p,q,r)-harmonic function, there exist complex numbers p,qC, perhaps depending on mZ, such that Lp,q,rum=Lp,q,pqum with equality in D. As a consequence, we will have that the m-th homogeneous part of a (p,q,r)-harmonic function is also harmonic in the former meaning of the word, or (p,q)-harmonic, for some p,qC. This will allow us to apply many of the results achieved in [Citation1], and leads to the conclusion (Theorem 5.1) that a function u in D is (p,q,r)-harmonic if and only if it has the form (8) u(z)=m=0cmF(χp,q,r,m+,χp,q,r,m,m+1;|z|2)zm+m=1cmF(χq,p,r,m+,χq,p,r,m,m+1;|z|2)z¯m,zD,(8) for some sequence {cm}m= of complex numbers such that lim sup|m||cm|1/|m|1. As for the particular case r = pq, the sums in (Equation8) are shown to converge absolutely in the space C(D). This series characterization depends on a result concerning the asymptotic behaviour of the m-th homogeneous parts um of a (p,q,r)-harmonic function. We show (see Theorem 4.6) that lim sup|m|umj,k;K1/|m|<1, for all j,kN and KD compact. This result allows us to apply the root test for absolute convergence of the function series m=um in C(D).

Further modelling on previous cases also shows (see Theorem 3.4) that limmF(χp,q,r,m+,χp,q,r,m,m+1;z)=(1z)p,zD. This result retrieves that obtained for the hypergeometric functions associated with the m-th homogeneous parts of (p,q)-harmonic functions (see [Citation1], Theorem 2.6).

In this paper we have pursued the course of Olofsson with particular reference to [Citation1,Citation2]. We also refer to [Citation3] by Olofsson and Wittsten. Other related sources include those of Wittsten [Citation4] or Wittsten and Carlsson [Citation5]. We also refer to Li with collaborators [Citation6,Citation7]. The case r = pq has also been treated by Ahern, Bruna and Cascante [Citation8], who traced the corresponding class of operators for this particular case to Geller [Citation9]. Related studies are also found in connection with conductivity problems, including Calderón [Citation10] or Astala and Päivärinta [Citation11]. Borichev and Hedenmalm also established a connection to polyharmonic theory [Citation12]. Early traces also leads to Garabedian [Citation13]. Connections to Bose-Einstein condensates and harmonic traps are found in Kling [Citation14], as briefly mentioned in the concluding remarks.

2. Preliminaries and basic constructions

A function u in D{0} is said to be homogeneous of order mZ with respect to rotations if it has the property u(ez)=eimθu(z),zD{0}, for eT. In particular, we will consider such functions of the form (9) u(z)=f(|z|2)zm,zD{0},(9) for some fC2(0,1) and mZ. Denote by (10) Ha,b,c=(1x)xd2dx2+(c[a+b+1]x)ddxab,(10) the ordinary hypergeometric differential operator, where a,b,cC are complex parameters. This operator is associated with the familiar ordinary hypergeometric differential equation (1x)xy′′(x)+(c[a+b+1]x)y(x)aby(x)=0, and takes the form Ha,b,cy=0 in terms of the operator Ha,b,c.

We will need the following result, and refer to [Citation1], Theorem 2.1, for details.

Theorem 2.1

Let Lp,q,r be as in (Equation1) for some p,q,rC. Let u be a function of the form (Equation9) for some fC2(0,1) and mZ. Then Lp,q,ru(z)=zmHa,b,cf(|z|2),zD{0}, where c = m + 1 and (11) {a+b=mpq,ab=rpm.(11)

Equation (Equation11) tells us that a and b are the zeros of the quadratic polynomial in (Equation6). We denote these two zeros by χp,q,r,m+ and χp,q,r,m, and get the following construction of (p,q,r)-harmonic functions.

Proposition 2.2

Let p,q,rC. Consider the function (12) um(z)=F(χp,q,r,m+,χp,q,r,m,m+1;|z|2)zm,zD,(12) where mN and F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6). Then um is a (p,q,r)-harmonic function.

Proof.

It is clear that umC(D). It is also known that the hypergeometric function y=F(a,b,c;) satisfies the hypergeometric equation Ha,b,cy=0. The result now follows by Theorem 2.1.

We compare the last result with Proposition 2.2 in [Citation1]. We also refer to [Citation15], Section 2.3, for more on the hypergeometric equation and its solutions.

Corollary 2.3

Let p,q,rC. Consider the function um(z)=F(χq,p,r,|m|+,χq,p,r,|m|,|m|+1;|z|2)z¯|m|,zD, where mZ and F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6). Then um is a (p,q,r)-harmonic function.

Proof.

Consider the conjugated expression um(z)¯=F(χq¯,p¯,r¯,|m|+,χq¯,p¯,r¯,|m|,|m|+1;|z|2)z|m|,zD. By Proposition 2.2 we have that u¯m is a (q¯,p¯,r¯)-harmonic function. It is then straightforward to check using the definition in (Equation1) that um is a (p,q,r)-harmonic function.

For coming purposes, we introduce the quadratic polynomial (13) Qp,q,r,m(λ)=λ2λ(m+pq)+rpq,λC.(13) Note that the polynomials Qp,q,r,m and Pp,q,r,m have the same discriminant (Equation7).

We also state that a function uC(D) is homogeneous of order m0 with respect to rotations if and only if it has the form (Equation9) for some fC[0,1), with care taken at the origin in the case that u is less smooth. We refer the reader to the fourth section of [Citation16] and Theorem 4.2 for a more elaborative discussion.

Theorem 2.4

Let p,q,rC and let mN. Let uC2(D) be homogeneous of order m with respect to rotations. Then there exist complex numbers p,qC such that (14) Lp,q,ru=Lp,q,pqu,inD.(14) Particularly, the complex numbers (15) {p=pμ,q=q+μ,(15) where μ is a zero of the polynomial Qp,q,r,m in (Equation13), are admissible for (Equation14).

Proof.

By the comments preceding this statement we can write uC2(D) on the form u(z)=zmf(|z|2),zD, for some fC2(0,1). By Theorem 2.1 we have that (16) Lp,q,ru(z)=zmHa,b,cf(|z|2),zD,(16) where a,bC satisfy the system of equations in (Equation11) and c = m + 1. This means that (17) Lp,q,ru=Lp,q,ru,inD,(17) for p,q,rC satisfying (18) {mpq=mpq,rpm=rpm.(18) In vector terms, we can express the general solution to this system of equations as (19) (pp,qq,rr)=μ(1,1,m),μC.(19) This can be seen by noticing that the complex vector on the left of this expression is in the orthogonal complement of the set {w1,w2} formed by the two vectors w1=(1,1,0) and w2=(m,0,1). We can then let r=pq in (Equation19) for a quadratic equation in μ that is satisfied by the zeros of the polynomial Qp,q,r,m in (Equation13). This gives the conclusion of the statement.

The relations in (Equation18) can be retrieved from (Equation15) and the polynomial Qp,q,r,m in the form of r=pq by noticing that (20) Qp,q,r,m(λ)=rpm(pλ)(q+λm),λC.(20) We also note that every triple of complex numbers p,q,rC of the form (Equation19) is admissible for (Equation17). However, the statement of Theorem (2.4) as it stands will do for our purposes, and we will proceed accordingly.

We will need the following result and refer to [Citation1], Theorem 2.4, for details. We also remind the reader that the naming convention (p,q,r)-harmonic is an adaptation to our situation and stems from the terminology used in the particular case r = pq, in which case the (p,q,pq)-harmonic functions are simply called (p,q)-harmonic.

Theorem 2.5

Let p,qC and mN. Let uC2(D) be homogeneous of order m with respect to rotations. Then u is (p,q)-harmonic if and only if it has the form (21) u(z)=cF(p,mq,m+1;|z|2)zm,zD,(21) for some cC, where F is the hypergeometric function (Equation3).

The last Theorem adapted to the general situation reads as follows.

Theorem 2.6

Let p,q,rC and mN. Let uC2(D) be homogeneous of order m with respect to rotations. Then u is (p,q,r)-harmonic if and only if it has the form u(z)=cF(χp,q,r,m+,χp,q,r,m,m+1;|z|2)zm,zD, for some cC, where F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6).

Proof.

The ”if” part of this statement is a consequence of Proposition 2.2. For the converse, let uC2(D) be a (p,q,r)-harmonic function homogeneous of order m with respect to rotations. Let p,qC be of the form (Equation15) for some μC such that Qp,q,r,m(μ)=0, with the latter defined as in (Equation13). Then Theorem 2.4 tells us that Lp,q,ru=Lp,q,pqu,inD. From Theorem 2.5, we have that u(z)=cF(p,mq,m+1;|z|2)zm,zD, for some cC. Note that p and mq are the zeros of the quadratic polynomial Pp,q,pq,m(λ)=λ2λ(mpq)+pqpm,λC. Recall the expression for Qp,q,r,m in the form of (Equation20). From this expression, we get that pqpm=rpm, for p,qC as above. This shows that Pp,q,pq,m and Pp,q,r,m define the same polynomial, where Pp,q,r,m is the polynomial in (Equation6). We conclude with the statement of this theorem.

The next result gives an indication of how we will proceed in view of the comments made in the introduction and was given in [Citation1], Theorem 3.2.

Theorem 2.7

Let {fm}m=0 be a sequence in C[0,1) such that lim supm(max0xr|fm(n)(x)|)1/m1, for nN and 0<r<1. Set um(z)=fm(|z|2)zm,zD, for m=0,1,2,. Then lim supmumj,k;K1/m<1 for all j,kN and KD compact.

3. Asymptotics

The space H(D) of analytic functions in D is topologized in the usual manner using the semi-norms (22) fK=maxzK|f(z)|,(22) for KD compact. We refer to convergence in H(D) as normal convergence in D, and say that a subset F of H(D) is normal if every sequence of functions of F has a subsequence which converges in H(D). The limit function is not required to belong to F.

Within our context, the Binomial series is suitably expressed in terms of the hypergeometric function (Equation3) as (23) F(a,b,b;z)=n=0(a)nn!zn=1(1z)a,(23) for zD.

On a last note before we proceed, we also refer to Conway [Citation17], Theorem VII.2.9, for Montel's Theorem, characterizing normal families of analytic functions.

Lemma 3.1

Let p,q,rC. Consider the functions fm(z)=F(χp,q,r,m+,χp,q,r,m,m+1;z),zD, for mN, where F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6). Then F={fm:mN} is a normal family of analytic functions in D.

Proof.

We will show that the functions in F are uniformly bounded on compact subsets of D. An application of Montel's Theorem then gives the conclusion of the lemma. Let KD be compact and let 0<ρ<1 be such that maxzK|z|<ρ. It is straightforward to check that (24) (χp,q,r,m++k)(χp,q,r,m+k)=mp+r+k(m+1+k(1+p+q)),(24) where k,mN. This gives us (χp,q,r,m++k)(χp,q,r,m+k)m+1+k=mp1m+1+k+r1m+1+k+k(11+p+qm+1+k), for k,mN. Applying the triangle inequality to this expression grants |(χp,q,r,m++k)(χp,q,r,m+k)m+1+k||p|mm+1+k+|r|1m+1+k+k|11+p+qm+1+k|, for k,mN. Choose N>0 such that |11+p+qm+1|1ρ, for m>N. Then |(χp,q,r,m++k)(χp,q,r,m+k)m+1+k||p|+|r|+kρ, for m>N and kN. Note that (χp,q,r,m+)n(χp,q,r,m)n(m+1)n=k=0n1pmm+1+k+rm+1+k+k(11+p+qm+1+k), where m,nN. By the last inequality we get that (25) |(χp,q,r,m+)n(χp,q,r,m)n(m+1)n|(|p|+|r|)nρn,(25) for nN when m>N. This shows that the family F is uniformly bounded on compact subsets KD. Indeed, by another application of the triangle inequality, we get from Equation (Equation25) that |fm(z)|n=0(|p|+|r|)nn!|z|nρn=1(1|z|/ρ)|p|+|r|, for |z|<ρ and m>N, where the last equality follows by the binomial series in (Equation23).

In the particular case when p,qC are such that Re(p)+Re(q)>1 and r = 0, we obtain the following asymptotic bound for the sequence F in Lemma 3.1.

Proposition 3.2

Let p,qC be such that Re(p)+Re(q)>1 and let r = 0. Let F be the normal family in Lemma 3.1. Then there is N>0 such that |fm(z)|1(1|z|)|p|,zD, for m>N.

Proof.

From (Equation24) we see that (χp,q,r,m++k)(χp,q,r,m+k)m+1+k=pmm+1+k+km(1+p+q)+1+km+1+k, for k,mN. We can choose N>0 such that |11+p+qm|1, for m>N. Following a similar line of argument to that in Lemma 3.1, we obtain |(χp,q,r,m+)n(χp,q,r,m)n(m+1)n|(|p|)n, for nN when m>N. Use of the triangle inequality then shows that |fm(z)|n=0(|p|)nn!|z|n=1(1|z|)|p|, for zD and m>N.

The last two results are modelled on Lemma 2.5 in [Citation1].

We mention here briefly that the restriction Re(p)+Re(q)>1 on the parameters p,qC appears naturally in the (p,q)-harmonic Dirichlet boundary value problem: (26) {Lp,qu=0inD,u=φonT,(26) where φ is a given function continuous on the unit circle T and with Lp,q:=Lp,q,pq as in (Equation1). It can be shown that this problem admits a solution in terms of a Poisson type integral that includes the classical case corresponding to p = q = 0, in which case the operator Lp,q reduces to that of Laplace. For the statement of this result, we define the (p,q)-harmonic Poisson kernel by (27) Kp,q(z)=(1|z|2)p+q+1(1z)p+1(1z¯)q+1,zD.(27) Let p,qC be such that Re(p)+Re(q)>1. Associated with this kernel is the (p,q)-harmonic Poisson integral (28) Kp,q[f](z)=cp,q2πTKp,q(ze)f(e)dθ,zD,(28) defined for integrable functions fL1(T) on T, where cp,q=Γ(p+1)Γ(q+1)Γ(p+q+1).

Theorem 3.3

Let p,qCZ be such that Re(p)+Re(q)>1. Let φC(T). Then a function u in D satisfies (Equation26) if and only if it has the form u(z)=Kp,q[φ](z),zD.

We refer to [Citation1–3] for proofs and more on the Dirichlet problem. We should also mention that our definition of the kernel in (Equation27) differs slightly from that given in [Citation1], where this function is instead denoted up,q and Kp,q=cp,qup,q. We have chosen to do so for the underscoring of certain relations between the more familiar elements associated with (p,q)-harmonics that we will give later on (Theorem 5.3).

To proceed, we give the following limit theorem for the family in Lemma 3.1, the proof details of which agrees in form to the proof of Theorem 2.6 in [Citation1].

Theorem 3.4

Let p,q,rC. Then (29) limmF(χp,q,r,m+,χp,q,r,m,m+1;z)=(1z)p,zD,(29) with normal convergence, where F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6).

Proof.

Let the sequence of functions fm be as in Lemma 3.1. From Lemma 3.1 we have that the set F={fm:mN} is a normal family. From (Equation3) we see that (30) fm(n)(0)=(χp,q,r,m+)n(χp,q,r,m)n(m+1)n,(30) for m,nN. Recall that the Pochhammer symbol ()n is a monic polynomial of degree n. In passing to the limit we obtain (31) limmfm(n)(0)=(p)n,(31) for nN. From (Equation23) we have that f(n)(0)=(p)n for nN, where f(z)=(1z)p,zD. A standard argument invoking Lemma 3.1 now gives that fmf in H(D) as m. We refer the reader to [Citation1], Theorem 2.6, for details.

We end this section with the following result, related to the asymptotic behaviour of the m-th homogeneous parts um of a (p,q,r)-harmonic function, as further described in Theorem 4.6.

Proposition 3.5

Let p,q,rC. Then lim supm(max0xr|F(n)(χp,q,r,m+,χp,q,r,m,m+1;x)|)1/m1, for nN and 0<r<1, where F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6).

Proof.

We note that the complex derivative ff is continuous in the topology of normal convergence of analytic functions. In view of this and Montel's Theorem, the proposition now follows from Theorem 3.4.

This last result should be compared with Proposition 3.3 in [Citation1].

4. Homogeneous parts of the generalized harmonic function

We will need the following result and refer to [Citation1], Proposition 4.1, for details.

Proposition 4.1

Let um be the m-th homogeneous part of uCn(D) for some mZ, where nN{}. Then umCn(D) and um is homogeneous of order m with respect to rotations.

The next result shows that each of the homogeneous parts of a (p,q,r)-harmonic function is also (p,q,r)-harmonic.

Proposition 4.2

Let p,q,rC. Let u be a (p,q,r)-harmonic function and denote by um its m-th homogeneous part for some mZ. Then um is (p,q,r)-harmonic.

Proof.

The proof is identical in form to Proposition 4.2, [Citation1]. We leave out the details.

The reader is asked to compare the following discussion to that of the fourth section in [Citation1].

Theorem 4.3

Let p,q,rC. Let u be a (p,q,r)-harmonic function and denote by um its m-th homogeneous part for some mN. Then (32) um(z)=cmF(χp,q,r,m+,χp,q,r,m,m+1;|z|2)zm,zD,(32) for some cmC, where F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6).

Proof.

By Proposition 4.1, the function um is homogeneous of order m with respect to rotations. By Proposition 4.2 the function um is (p,q,r)-harmonic. An application of Theorem 2.6 now gives the conclusion of this statement.

Corollary 4.4

Let p,q,rC. Let u be a (p,q,r)-harmonic function and denote by um its m-th homogeneous part for some mZZ+. Then (33) um(z)=cmF(χq,p,r,|m|+,χq,p,r,|m|,|m|+1;|z|2)z¯|m|,zD,(33) for some cmC, where F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6).

Proof.

The complex conjugate u¯m is the m=|m|-th homogeneous part of the function u¯. It is straightforward to check that u¯ is a (q¯,p¯,r¯)-harmonic function from the definition in (Equation1). From Theorem 4.3 we have that um(z)¯=kmF(χq¯,p¯,r¯,|m|+,χq¯,p¯,r¯,|m|,|m|+1;|z|2)z|m|,zD, for some kmC. A complex conjugation now yields (Equation33) with cm=k¯m.

It is also clear from Theorem 4.3 and Corollary 4.4 that umC(D) for mZ if u is (p,q,r)-harmonic. We will now proceed with summation of the homogeneous parts um of a (p,q,r)-harmonic function. From the triangle inequality we have that (34) sup|z|=r|um(z)|sup|z|=r|u(z)|,(34) for 0<r<1 and mZ.

Lemma 4.5

Let p,q,rC. Let u be a (p,q,r)-harmonic function and consider its m-th homogeneous part um for mZ. Let cm be as in (Equation32) or (Equation33) depending on whether mN or mZ. Then lim sup|m||cm|1/|m|1.

Proof.

Let mN and let 0<r<1. From Theorem 4.3 and (Equation34) we have that (35) |cm||F(χp,q,r,m+,χp,q,r,m,m+1;r2)|rmmax|z|=r|u(z)|,(35) for mN. From Theorem 3.4 we have that limmF(χp,q,r,m+,χp,q,r,m,m+1;r2)=(1r2)p0. Therefore, a passage to the limit in (Equation35) gives that lim supm|cm|1/m1/r. Since 0<r<1 was arbitrarily chosen we conclude that lim supm|cm|1/m1. The case mZ follows by a similar argument to that above. We conclude with the statement of this lemma.

Theorem 4.6

Let p,q,rC. Let u be a (p,q,r)-harmonic function and denote by um its m-th homogeneous part for mZ. Then umC(D) for mZ and lim sup|m|umj,k;K1/|m|<1, for all j,kN and KD compact.

Proof.

Recall Theorem 4.3 and Corollary 4.4. In the case of mN, Proposition 3.5 and Lemma 4.5 applies for the fulfilment of the assumptions in Theorem 2.7. An application of Theorem 2.7 shows that lim supmumj,k;K1/m<1 for j,kN and KD compact.

This last argument can also be applied to the case of negative integer values mZ by noting that um is the (m)-th homogeneous part of the (q¯,p¯,r¯)-harmonic function u¯.

Corollary 4.7

Let p,q,rC. Let u be a (p,q,r)-harmonic function with m-th homogeneous part um for mZ. Then the function series m=um is absolutely convergent in C(D).

Proof.

Theorem 4.6 allows us to apply the root test to conclude that m=umj,k;K<+, for j,kN and KD compact.

We will need the following lemma due to Fejér and refer the reader to [Citation1], Lemma 4.8, and Katznelson [Citation18], Section I.2, for proofs and a more elaborative description.

Lemma 4.8

Let uCn(D) for some nN and denote by um its m-th homogeneous part for mZ. Then u=limN+m=NN(1|m|N+1)um, in Cn(D).

We now show that (p,q,r)-harmonic functions are in fact smooth.

Corollary 4.9

Let p,q,rC. Let u be a (p,q,r)-harmonic function. Then uC(D) and u=m=um in C(D), where um is the m-th homogeneous part of u for mZ.

Proof.

From Lemma 4.8 we have that (36) u=limN+m=NN(1|m|N+1)um,(36) in C2(D). From Corollary 4.7 we know that the function series m=um is absolutely convergent in C(D). Following a standard argument we can do away with the convergence factors in (Equation36) and deduce that u=m=um in C(D).

5. Series representations for generalized harmonic functions

We are now in a position to give the following function series representation for (p,q,r)-harmonic functions.

Theorem 5.1

Let p,q,rC. Then u is a (p,q,r)-harmonic function if and only if it has the form (37) u(z)=m=0cmF(χp,q,r,m+,χp,q,r,m,m+1;|z|2)zm+m=1cmF(χq,p,r,m+,χq,p,r,m,m+1;|z|2)z¯m,zD,(37) for some sequence {cm}m= of complex numbers such that (38) lim sup|m||cm|1/|m|1,(38) where F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6). Moreover, the sums in (Equation37) are absolutely convergent in C(D) when (Equation38) holds.

Proof.

Let {cm}m= be a sequence of complex numbers satisfying (Equation38). Set (39) um(z)=cmF(χp,q,r,m+,χp,q,r,m,m+1;|z|2)zm,zD,(39) for mN and (40) um(z)=cmF(χq,p,r,|m|+,χq,p,r,|m|,|m|+1;|z|2)z¯|m|,zD,(40) for mZ. Consider the formal (p,q,r)-harmonic series expression on D of the form (41) um=um.(41) From Theorem 2.7 and Proposition 3.5 we have that lim sup|m|umj,k;K1/|m|<1, for j,kN and KD compact. The root test now applies to show that the series in (Equation41) is absolutely convergent in C(D), and we can write (Equation41) with equality. Since our series converges in C(D), we have that uC(D). From Proposition 2.2 and Corollary 2.3 we have that each term um is (p,q,r)-harmonic. An evaluation of u in (Equation41) with respect to the operator Lp,q,r shows that u is a (p,q,r)-harmonic function. This gives the first part of the statement.

For the converse, let u be a (p,q,r)-harmonic function and denote by um its m-th homogeneous part. From Theorem 4.3 and Corollary 4.4 we know the form of each of the functions um for mN and Z as given in (Equation39) and (Equation40), respectively. From Corollary 4.9 we have (Equation37) in the form u=m=um in C(D). By Corollary 4.7, this sum converges absolutely in C(D). From Lemma 4.5 we have that (Equation38) holds.

We note that Theorem 5.1 generalizes Theorem 5.1 in [Citation1], which in turn is an improvement of Ahern, Bruna and Cascante's Theorem 2.1 in [Citation8] when specialized to the current setting. Theorem 5.1 also includes Theorem 1.2 in Olofsson and Wittsten [Citation3], and Theorem 2.2 in Olofsson [Citation2].

We claim that it is possible to retrieve a formula for the expansion coefficients cm appearing in (Equation37). We will not delve into the details of this topic however, and instead refer to the fifth section of [Citation1]. The form in which the series expansion appears below can be deduced from the results of this section following a slight change of wording. We will content ourselves with stating the result.

Theorem 5.2

Let p,q,rC. Let u be a (p,q,r)-harmonic function. Then (42) u(z)=m=0mu(0)m!F(χp,q,r,m+,χp,q,r,m,m+1;|z|2)zm+m=1¯mu(0)m!F(χq,p,r,m+,χq,p,r,m,m+1;|z|2)z¯m,zD,(42) where F is the hypergeometric function (Equation3) with parameters χp,q,r,m± being the zeros of the polynomial Pp,q,r,m in (Equation6).

Note that the last result also settles the question on uniqueness of the series representation.

On a side note and before we conclude, we also wish to include an alternative form of the series representation in (Equation42), valid in the restriction to (p,q)-harmonic functions. In particular, we show that the hypergeometric function in (Equation21) can be retrieved from the (p,q)-harmonic Poisson kernel in (Equation27) and the basic elements of (p,0)-harmonic functions via integration of their product over T. This peculiar integral representation is given by (43) F(p,mq,m+1;r2)=12πTKp,q(re)F(p,m,m+1;re)dθ,(43) for 0r<1 and mN. Although we have found no natural fit for this formula, it can be applied to retrieve some of the earlier results, such as Theorem 6.6 in [Citation1]. We also note here that the hypergeometric function appearing under the integral sign in (Equation43) regularly occurs in α-harmonic theory, for which we refer to [Citation3], where instances of this formula also appears. We have chosen the following form for this representation, where we consider fr(e)=f(re) as functions on T.

Theorem 5.3

Let p,qC. Let u be a (p,q)-harmonic function. Then ur(e)=m=0mu(0)rmm!(12πTKp,q,r(e)Fr(p,m,m+1;e)dτ)eimθ+m=1¯mu(0)rmm!(12πTKq,p,r(e)Fr(q,m,m+1;e)dτ)eimθ, for 0r<1, where Kp,q is the (p,q)-harmonic Poisson kernel in (Equation27) and F is the hypergeometric function in (Equation3).

Proof.

We will give the formula in (Equation43). The statement then follows from Theorem 5.4 in [Citation1]. By Euler's transformation formula for hypergeometric functions (see [Citation15], Theorem 2.2.5), we can write F(p,mq,m+1;r2)=(1r2)p+q+1F(m+1+p,1+q,m+1;r2), for 0r<1 and mN. The hypergeometric function on the right of this expression is given by F(m+1+p,1+q,m+1;r2)=n=0(m+1+p)n(m+1)n(1+q)nn!r2n, for 0r<1 and mN. Note that F(m+1+p,1,m+1;z)=n=0(m+1+p)n(m+1)nzn,zD, for mN. We also recall that F(1,1+q¯,1;z)=n=0(1+q¯)nn!zn=1(1z)q¯+1,zD. Following an application of Parseval's formula, we obtain F(p,mq,m+1;r2)=(1r2)p+q+112πTF(m+1+p,1,m+1;re)(1re)q+1dθ, for 0r<1 and mN. Another use of Euler's transformation formula gives that F(m+1+p,1,m+1;z)=(1z)(1+p)F(p,m,m+1;z),zD, for mN. This gives the formula in (Equation43).

6. Final remarks

Questions concerning the class of second order differential operators in (Equation1) and the mapping (p,q,r)(a,b,c) of this class onto the subclass of hypergeometric operators as determined through zmHa,b,cf(|z|2)=Lp,q,rzmf(|z|2),zD, in accordance with Theorem 2.1, has led us to Theorem 2.4. It was this identification of elements (p,q,r) in the underlying parameter space of the operator class in (Equation1), with elements (p,q,pq) in the underlying parameter realm of the subclass Lp,q,pq, that allowed us to recycle the developments in [Citation1] concerned with the latter. This made possible the short cut in the upgrade from two degrees of freedom to three, and the generalization of Theorem 5.1 in [Citation1] as presented in Theorem 5.1. We will maintain our interest for the operator class in (Equation1) and its corresponding class of hypergeometric operators.

We also briefly discussed the associated Dirichlet boundary value problem for the case r = pq, and mentioned in section two that a solution to this problem has been obtained in terms of a Poisson type integral [Citation1–3,Citation8]. The case considered here in the addition of a third parameter is left open and we are unmindful of any such formulas.

As mentioned in the concluding remarks of [Citation1], earlier work also concerns pointwise boundary limits, Green functions and Lipschitz continuity of generalized harmonic functions [Citation16,Citation19,Citation20].

Before we finish, we also give a (formal) version of the operator class (Equation1) in polar terms, and consider the expression 14(1ρ2)2+p2(ρρiθ)+q2(ρρ+iθ)r. The homogeneous equation associated with this class of operators for the particular choice of p=q=1/2 and r=γ2/2 corresponds to ρρu12(1ρ2)2u=γ2u. We compare the form of this equation to that associated with harmonic traps in connection with Bose-Einstein condensates, as laid out in the third chapter of Kling [Citation14].Footnote4

Disclosure statement

No potential conflict of interest was reported by the author(s).

Notes

1 It is the author's opinion that the results of this paper should be viewed as an application of the methods presented in [Citation1], and be attributed as such. For this very reason, the author has chosen to preserve the earlier format to any suitable extent, and the reader is advised to consult the former text for reference. The author has also tried to highlight the connection between the two whenever applicable, and where a comparison can be made between the special and the more general.

2 The author wishes to thank Anders Olofsson for his constructive criticism of the manuscript.

3 The author would like to thank the referee for a thorough reading of the text.

4 The author thanks Felix Tellander for drawing his attention to this source.

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