Abstract
In the paper [A. Ben Amar, A. Jeribi, and B. Krichen, Fixed point theorems for block operator matrix and an application to a structured problem under boundary conditions of Rotenberg's model type, to appear in Math. Slovaca. (2014)], the existence of solutions of the two-dimensional boundary value problem (1) and (2) was discussed in the product Banach space Lp×Lp for p∈(1, ∞). Due to the lack of compactness on L1 spaces, the analysis did not cover the case p=1. The purpose of this work is to extend the results of Ben Amar et al. to the case p=1 by establishing new variants of fixed-point theorems for a 2×2 operator matrix, involving weakly compact operators.
1. Introduction
In this paper, we are concerned with the existence of solutions for the following two-dimensional boundary value problem introduced in [Citation4]:
where ,
, μ∈[0, Citation1],
with
. The functions
and
are nonlinear and λ is a complex number.
The boundary conditions are given by
Rotenberg [Citation17] proposed the singular partial differential equation:
Latrach and Jeribi [Citation14] examined the existence of Equation (3) supplemented with the boundary conditions
Recently, Ben Amar et al. [Citation4] proved an existence result for integrable solutions of the two-dimensional boundary problem (1) and (2) which were obtained in the Banach space for
. The analysis was carried out via topological arguments and uses the compactness results established in [Citation14] for a one-dimensional transport equation and the Schauder and Krasnoselskii fixed-point theorems [Citation13,Citation18]. The purpose of this work is to continue this analysis in the Banach space
, due to the lack of compactness in L1 spaces, by using the results concerning the weak compactness in [Citation3]. Our strategy consists in establishing fixed-point theorems for a 2×2 operator matrix on the general product Banach spaces which can be applied directly to solve our problem.
Note that the boundary value problem (1) and (2) may be transformed into the following fixed-point problem:
where
The outline of the paper is a follows. In Section 2, we recall some definitions and give basic results for future use. In Section 3, we establish some fixed-point results for the operator matrix (5). In Section 4, we use the results of Section 3 to derive the existence of solutions to problem (1) and (2) in the Banach space
. In Theorem 4.1, we consider the special case where each σi does not depend on the density of the population i, that is,
. The general boundary value problem (1) and (2) (i.e.
is a nonlinear function of
) is discussed in Theorem 4.2.
2. Preliminaries
Throughout this section, denotes a Banach space. For any r>0, Br denotes the closed ball in
centred at
with radius r. Here ⇀ denotes weak convergence and → denotes strong convergence in
, respectively.
is the collection of all nonempty bounded subsets of
and
is the subset of
consisting of all weakly compact subsets of
. Recall that the notion of the measure of weak noncompactness was introduced by De Blasi [Citation11]; it is the map
defined in the following way:
for all
. For convenience, we recall some basic properties of
needed below [Citation2,Citation11].
Lemma 2.1
Let
be two elements of
. Then, the following conditions are satisfied:
(1)
implies
.
(2)
if and only if
that is,
is the weak closure of
.
(3)
.
(4)
.
(5)
for all
.
(6)
that is,
is the convex hull of
.
(7)
.
(8) if
is a decreasing sequence of nonempty bounded and weakly closed subsets of
with
then
is nonempty and
that is,
is relatively weakly compact.
Definition 2.1
A map is said to be weakly compact, if
is relatively weakly compact for every bounded subset
.
Definition 2.2
A map is said to be ω-contractive (or ω-contraction) if it maps bounded sets into bounded sets, and there exists some α∈[0, 1) such that
for all bounded subsets
.
Definition 2.3
A map is said to be weakly–strongly sequentially continuous if for every sequence
implies
.
Let A be a nonlinear operator from into itself. Following Latrach et al. [Citation15], we introduce the following conditions:
Regarding these two conditions, Latrach et al. [Citation15, Remark 2.1] noted the following.
Remark 2.1
(a) Operators satisfying
or
are not necessarily weakly continuous.
(b) Every ω-contractive map satisfies
.
(c) A map A satisfies
if and only if it maps relatively weakly compact sets into relatively weakly compact ones (use the Eberlien–Šmulian theorem [12, p. 430]).
(d) A map A satisfies
if and only if it maps relatively weakly compact sets into relatively compact ones.
(e) The condition
holds true for every bounded linear operator.
Moreover, note that is weaker than the weakly–strongly sequentially continuity of the operator A [Citation1]. Now, we shall recall the following well-known results in [Citation15].
Theorem 2.1
Let be a nonempty closed convex subset of a Banach space
. Assume that
is a continuous map which verifies
. If
is relatively weakly compact, then there exists
such that Ax=x.
Theorem 2.2
Let be a nonempty bounded closed convex subset of a Banach space
. Assume that
is a continuous map satisfying
. If A is ω-contractive, then there exists
such that Ax=x.
Remark 2.2 Assume that a mapping is a contraction and satisfies
then A is ω-contractive.
Theorem 2.3
Let be a nonempty closed bounded convex subset of a Banach space
. Suppose that
and
such that
(i) A is continuous,
is relatively weakly compact and A satisfies
(ii) B is a contraction satisfying
(iii)
.
Then, there is such that Ax+Bx=x.
3. Fixed-point theory
Let and
be closed convex nonempty subsets of two Banach spaces
and
. We consider the 2×2 block operator matrix
(5) defined on the Banach space
, that is, the nonlinear operator A maps
into
, B from
into
, C from
into
and D from
into
.
Our aim is to develop a general matrix fixed-point theory which allows to treat the biological application described in the introduction. In the following, we discuss the existence of fixed points for the block operator matrix (5) by imposing some conditions on the entries, which are in general nonlinear operators. This discussion is based on the invertibility or not of the diagonal terms of
.
First case: I−A and I−D are invertible.
Assume that
the operator I−A is invertible and
;
(I−A)−1B is a operator continuous satisfying
and
is relatively weakly compact;
C is a operator continuous satisfying
;
the operator I−D is invertible and their inverse (I−D)−1 is continuous on
and satisfies
;
.
Theorem 3.1
Under assumptions –
the block matrix operator (5) has a fixed point in
.
Proof Let Γ be the operator defined by . In order to prove the theorem, we have to check that (1)
is relatively weakly compact. For this, let
be a sequence in
, there exists a sequence
such that
for all
, because
and
is relatively weakly compact then, by Eberlien–Šmulian theorem [Citation12],
has a weakly convergent subsequence. On the other hand, using the fact that C and (I−D)−1 verify
, the sequence
has also a weak converging subsequence, it follows that
is relatively weakly compact. (2) Γ satisfies the condition
. Let
be a weakly convergent sequence of
, since (I−A)−1B satisfies
and
has a strongly convergent subsequence. By the continuity of the operator C and (I−D)−1,
has also a strongly convergent subsequence, that is, Γ satisfies
. Clearly, Γ is continuous; consequentially, Γ satisfies the hypotheses of Theorem 2.1 as we claimed, and there exists
such that
Let
, hence
. ▪
In the other cases, we will assume furthermore that and
are bounded.
Second case: I−A or I−D is invertible.
We shall treat only the case of invertibility of I−A, the other case is similar just simply exchanging the roles of A and D and B and C.
Assume that
the operator I−A is invertible and
;
is a contraction satisfying
with constant k;
D is a continuous operator satisfying
and ω-α-contractive for some
;
.
Theorem 3.2
Under assumptions –
the block matrix operator (5) has a fixed point in
.
Proof Since S is a contraction with a constant k∈(0, 1), the mapping I−S is a homeomorphism from into
[Citation18]. Let y′ be fixed in
, the map which assigns to each
the value Sy+Dy′ defines a contraction from
into
. Therefore, by the Banach fixed-point theorem, the equation y=Sy+Dy′ has a unique solution
in
. Therefore,
Next, we will prove that
satisfies the conditions of Theorem 2.2. It is clear that T is continuous and satisfies
. Now, we check that T is ω-β-contractive for some β∈[0, 1). To do so, let
be a subset of
. Using the following equality:
we infer that
The properties of
in Lemma 2.1 and the assumptions on S and D imply that
and therefore,
This inequality means that T is ω-β-contractive with
. Consequently, T satisfies the hypotheses of Theorem 2.2 as we claimed, and hence, such operator has a fixed point in
, so the operator matrix (5) has at least a fixed point in
. ▪
Third case: Neither I−A nor I−D is invertible.
Here, we discuss the existence of fixed points for the following perturbed block operator matrix by imposing some conditions on the entries:
The operator I−A1 (resp. I−D1) is invertible from
into
(resp. from
into
).
(I−A1)−1B and (I−D1)−1C are continuous, weakly compact maps and verify
.
and
are contraction maps and verify
.
and
.
Theorem 3.3
Under assumptions –
the block matrix operator (6) has a fixed point in
.
Proof Using assumption the following equation
may be transformed into
where
and
Obviously, the operator matrix
is continuous. Now, we check that
is a weakly compact operator and satisfies
. To see this, let
be a sequence in
; since (I−A1)−1B is weakly compact, the sequence
has a weakly convergent subsequence, say
. On the other hand, the sequence
has a weak converging subsequence say
, then
is a weakly convergent subsequence of
; hence,
is a weakly compact operator. Also, we show that the operator matrix
verifies
and from
the operator matrix
is a contraction that satisfies
. It follows with
and Theorem 2.3 that the operator matrix (6) has at least a fixed point in
. ▪
4. Application to transport equations
The aim of this section is to apply Theorems 3.1 and 3.3 to discuss existence results for the two-dimensional boundary value problem (1) and (2) in the Banach space . To do so, let us first make precise the functional setting of the problem. Let
where
. We denote by
and
the following boundary spaces
endowed with their natural norms. Let
be the space defined by
It is well known [Citation7,Citation8,Citation10] that any ψ in
has traces on the spatial boundary {0} and {1} which belong, respectively, to the spaces
and
.
We define the free streaming operator , i=1, 2, by
where
,
,
and Ki, i=1, 2, are the following nonlinear boundary operators
satisfying the following conditions:
There exists αi>0 such that
K2 is a weakly compact operator on
.
As an immediate consequences of we have the continuity of the operator Ki from
into
and
Let us consider the equation
Our objective is to determine a solution
where g is given in
and
. Let
be real defined by
For
, the solution is formally given by
Accordingly, for μ=1, we get
Let ; from
and estimate (8), we have
Lemma 4.1
Assume that holds. Then,
(1) for every λ satisfying i=1, 2, the operator Wi, λ is continuous and maps bounded sets into bounded ones and satisfies the following estimate
(2) If then the operator
is invertible and
is given by
Moreover, is continuous on
and maps bounded sets into bounded ones.
In what follows and for our subsequent analysis, we need the following hypothesis:
(
,
where f is a measurable function defined by
with
,
, is a measurable function from
to ℂ which defines a bounded linear operator Bij by
Definition 4.1 [Citation16]
Let Bij, be the operator defined by Equation (16). Then, Bij is said to be a regular operator if
is a relatively weakly compact subset of
.
Lemma 4.2 [Citation3]
If Bij, is a regular operator then
is weakly compact on
for
.
Let D be a subset of ℝn. Recall that a function is said to satisfy the Carathéodory conditions on
if
Observe that if f is a Carathéodory function, then we can define the operator on the set of functions
by
for every
. The operator
is called the Nemytskii operator generated by g.
In Lp spaces, , the Nemytskii operator has been extensively investigated [Citation9,Citation10]. However, we recall the following result which states a basic fact for the theory of these operators on L1 spaces.
Lemma 4.3 [Citation9]
Assume that g satisfies the Carathéodory conditions. If the operator acts from L1 into L1, then
is continuous and takes bounded sets into bounded sets.
We shall also assume that
f satisfies the Carathéodory conditions and
acts from
into
.
We recall the following lemma established in [Citation15] which will play a crucial role below.
Lemma 4.4
If condition holds true, then
satisfies
.
We are now ready to state our first existence result.
Theorem 4.1
Assume that –
hold. If B12 is a regular collision operator on
then for each r>0 there is λr>0 such that for each λ satisfying
the problem
Proof Let λ be a complex number such that with
. Then, according to Lemma 4.1,
is invertible and therefore the problem (17) and (18) may be transformed into
where
Claim 1 Let r>0. We first check that, for suitable λ,
leaves Br invariant. Let ψ∈Br; therefore, from Lemma 4.1 and the estimates (8)–(11), we have
where M(r) is the upper-bound of
on Br. Let
. For
we have
Therefore,
Using Equation (15), we have
Let
, and from the estimate (8) there exists λ1 such that for any λ satisfying
, we have
; then using
we obtain
It follows that
Therefore,
where
Clearly, Q(·) is continuous strictly decreasing in t>0 and satisfies
. Hence, there exists λ2 such that
. Obviously, if
, then
maps Br into itself.
Claim 2 It is immediate that the operator Sλ is continuous and weakly compact on . Now, we check that Sλ satisfies the condition
. For this, let
be a weakly convergent sequence of
. Using the fact
satisfies
,
has a weakly convergent subsequence, say
. Moreover, using Proposition 2.12 and Lemma 4.7 in [Citation3], we have
weakly–strongly sequentially continuous, so
converges strongly in
. Then, Sλ satisfies
.
Claim 3 Clearly is continuous on
. Now, we check that
satisfies the condition
. To do so, let
be a weakly convergent sequence of
. Using the fact
satisfies the condition
,
has a weakly convergent subsequence, say
. Moreover, the continuity of the linear operator B21 implies that it is weakly continuous on
[Citation6], so
converge weakly in
. Then,
satisfies
.
Claim 4 Clearly from Lemma 4.1, we have that exists and is continuous on
. Now, we check that
satisfies the condition
. For this, let
be a weakly convergent sequence of
. Using the fact
is a bounded sequence and K2 is a weakly compact operator on
,
has a weakly convergent subsequence say
; moreover, using the continuity of the linear operators Q2, λ and R2, λ, we have that
converge weakly in
. Then, the operator
satisfies
. Arguing as the claim 1 for
, there exists λr such that for
, we have
. Finally, Γ has a fixed point in Br; equivalently the problem (17) and (18) has a solution in
. ▪
Now, we discuss the existence of solutions for the more general nonlinear boundary problem (1) and (2). When dealing with this problem, some technical difficulties arise. Therefore, we need the following assumption:
and for each r>0, the function
, i=1, 2, satisfies
where
denotes the set of all bounded linear operators from
into
and
and
acts from
into
.
Define the free streaming operator , i=1, 2, by
Theorem 4.2
Assume that –
hold. If Bij,
are regular collision operators on
then for each r>0, there is λr>0 such that for each λ satisfying
the problem (1) and (2) has at least one solution in
.
Proof Since Ki, i=1, 2, is linear, the operator is linear too. Using Lemma 4.1,
where
denotes the resolvent set of
. Let
such that
. Then, by linearity of the operator
, the problem (1) and (2) written in the form
where
may be transformed into the form
where
and
Claim 1 Check that, for suitable λ, the operator
is a contraction mapping. Indeed, let
,
A simple calculation using the estimates (8)–(11) leads to
Claim 2 Using Lemma 4.2 and arguing as in the proof of Theorem 4.1, we show that satisfies
and
is continuous, weakly compact on
and satisfies
.
Claim 3 Let r>0 and . According to estimation (19), we obtain
where T(·) has the same properties as E(·), and M(r) and M′(r) are the upper-bounds of
and
on Br. Arguing as above, we show that there exists λ2 such that, for all λ such that
, we have
.
By similar reasoning, we prove that there exists λ3, such that , and we have
.
Finally, if , then for all λ satisfying
, the operators
and
satisfy the conditions of Theorem 3.3. Consequently, the problem (1) and (2) has a solution in
for all λ such that
. ▪
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