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Abstract
The concept of nil-M-McCoy (nil-McCoy ring relative to monoid M), which are generalizations of McCoy ring and nil-M-Armendariz rings have been introduced, and we investigate their properties. It is shown that every NI ring is nil-M-McCoy for any unique product monoid M, it has also been shown that every semicommutative rings is nil-M-McCoy for any unique product monoid and any strictly totally ordered monoid M. Moreover, it is proved that for an ideal I of R, if I is semicommutative and R / I is nil-M-McCoy then R is nil-M-McCoy for any strictly totally ordered monoid. We extend and unify many known results related to McCoy rings and nil-Armendariz ring.
Public Interest Statement
The current paper attempts to generalize Nil-macCoy rings with Monoid to present a novel work with the title of Nil-M-MacCoy. The survey of literature demonstrates that studies on Nill-Armendariz and Nil-MacCoy and Nil-M-Armendariz and have already been researched. The theorems, lemmas and corollaries which have been already studied concerning this topic to be compared with the new work to generalize or complete it. It paves the way for the willing researchers to continue the trend with the novel areas that have been investigated.
1. Introduction
All rings considered here are associative with identity. For a ring R, nil(R) denotes the set of nilpotent elements. Rege and Chhawchharia (Citation1997) introduced the notion of an Armendariz ring Recall that a ring R is called reduced if implies that
, for all
; R is symmetric if
implies
, for
; R is reversible if
implies
, for all
; R is semicommutative if
implies
, for all
.
Recall that a monoid M is called an u.p.-monoid (unique product monoid) if for any two nonempty finite subsets there exists an element
that can be written uniquely in the form ab where
and
. The class of u.p.monoids is quite large and important (see Birkenmeier & Park, Citation2003).
According to Nielsen (Citation2006), a ring R is called right McCoy whenever polynomials satisfy
, there exists a nonzero
such that
. We define left McCoy ring similarly. If a ring is both left and right McCoy, we say that the ring is a McCoy ring. Liu (Citation2005), studied a generalization of Armendariz ring, which is called M-Armendariz ring if whenever
,
, with
satisfy
, then
for each
.
Zhao, Zhu, and Gu (Citation2012) introduced the notion of a nil-McCoy ring. A ring R is said to be right nil-McCoy if , where
,
, implies that there exists
such that
for
. Left nil-McCoy ring are defined similarly. A ring is nil-McCoy if it is both left and right nil-McCoy. According to Hashemi (Citation2010), a ring R is called right M-McCoy if whenever
,
, with
,
satisfy
, then
for some nonzero
. Left M-McCoy ring are defined similarly. Also, if R is both left and right M-McCoy, then we say R is M-McCoy.
Our results also generalized and unify the above-mentioned concepts by introducing the notion of nil-M-McCoy ring.
2. Nil-McCoy rings relative to a monoid
We begin this section by the following definition and also we study properties of nil-M-McCoy rings.
Definition 2.1
Let M be a monoid and R a ring. We say that R is right nil-M-McCoy (right nil-McCoy ring relative to M), if whenever ,
, with
,
satisfy
, then
for some nonzero
and for each
. Left nil-M-McCoy rings are defined similarly. If R is both left and right nil-M-McCoy, then we say R is nil-M-McCoy.
Let . Then a ring R is nil-M-McCoy (resp., nil-M-Armendariz) if and only if R is nil-McCoy (resp., nil-Armendariz). If
, then for any ring R, R is nil-M-McCoy and nil-M-Armendariz.
Example 2.1
Let be the ring of integers modulo 2 and R be a nil-Armendariz ring and
where I is the ideal generated by the relations: . Get S be subring generated by elements not involving e. Let
and
such that
and let
then
. It is straightforward to see that the element as is not nilpotent for any nonzero
. However, R is nil-M-McCoy as
for any elements
.
For any , we denote by
the set of all coefficients of
.
Proposition 2.1
For any "u.p."-monoid M, every NI ring is nil-M-McCoy.
Proof
Let M be an "u.p."-monoid and R be a NI ring. Suppose that satisfy
. Since nil(R) is an ideal of R, R / nil(R) is M-McCoy by Liu (Citation2005, Proposition 2.6). For any
, denote
. It is easy to see that the mapping
. Defined by
is a ring homomorphism. Since
,
. Hence, we have
. So
for i, j, since R / nil(R) is M-McCoy. Thus,
for i, j. Choosing
and
, we have
and
, for i, j. Therefore, R is nil-M-McCoy.
Example 2.2
Let M be "u.p."-monoid and K be field. Suppose . Then the ring
is nil-M-McCoy, since R is a NI ring.
To prove Theorem 2.1, we state the following lemmas.
Lemma 2.1
Let M be cyclic group of order and R a ring with
. Then R is not nil-M-McCoy.
Proof
Suppose that . Let
and
then
, but
for each nonzero
. Therefore, R is not right nil-M-McCoy. Similarly R is not left nil-M-McCoy. Therefore, R is not nil-M-McCoy.
Lemma 2.2
Let M be a monoid and N a submonoid of M. If R is nil-M-McCoy, then R is nil-N-McCoy.
Proof
It is clear by Liu (Citation2005, lemma 1.12) and Hashemi (Citation2010, lemma 1.12).
Lemma 2.3
Liu (Citation2005, Lemma 1.13). Let M and N be "u.p."-monoid. Then so is the monoid .
Example 2.3
Let and let M, N be “u.p.”-monoids. Let
and. Since M is a "u.p."-monoid, there exist i, j with
and
such that
is uniquely presented by considering two subsets
Consider two subsets
Since N is a “u.p.”-monoid, there exist such that
is uniquely presented.
Now it is easy to see that is uniquely presented. Thus
is a “u.p.”-monoid.
Recall that a monoid M is called torsion-free if the following property holds: if and
are such that
, then
.
Let T(H) be the set of elements of finite order in an abelian group H. H is said to be torsien-free If T(H)={e}.
Theorem 2.1
Let H be finitely generated abelian group. Then the following conditions on H are equivalent:
(1) | H is torsion-free. | ||||
(2) | There exists a ring R with |
Proof
If H is finitely generated abelian group with
, then
, a finite direct product of the group
, by Lemma 2.3, H is “u.p.”-monoid. Let R be a NI ring. Then, by Proposition 2.1, R is nil-H-McCoy.
If
and
, then
is a cyclic group of finite order. If a ring
is nil-H-McCoy, then by Lemma 2.2, R is nil-N-McCoy, a contradiction with Lemma 2.1. Therefore, every ring
is not nil-H-McCoy.
A ring R is called right Ore if given with b regular, there exist
with
regular such that
. left Ore rings can be defined similarly.
Proposition 2.2
Let M be a monoid and R a right Ore ring with its classical right quotient ring Q. If R is right nil-M-McCoy, then Q is right nil-M-McCoy.
Proof
Let ,
be nonzero polynomials of Q[M] such that
. Since Q is a classical right quotient ring, we assume that
and
for
for all i, j and regular elements
. For each j, there exists
and a regular element
such that
. Denote
and
. We have
. So
. Since R is right nil-M-McCoy, there exists a nonzero element
such that
. So
, for each i, and uc is a nonzero element in Q. Hence, Q is a right nil-M-McCoy ring.
Theorem 2.2
Let M be a monoid with . Then the finite direct sum of nil-M-McCoy rings is nil-M-McCoy.
Proof
It suffices to show that if are nil-M-McCoy rings, then so is
. Let
and
be such that
. Therefore we show that there exists
such that
and
for each
,
and for all
. Now let
,
,
,
. Then
and
. Since by hyopothesis
and
are nil-M-McCoy
,
for each
. Thus for each
, and also
,
for each
. Thus for each
. Therefore,
is nil-M-McCoy.
Example 2.4
Let R be an M-McCoy reduced ring, and M a monoid with and let
Then is not M-McCoy for
by Ying et al. (Citation2008, Theorem 2.1). But
is nil-M-McCoy by Theorem 2.3 below. Hence, a nil-M-McCoy ring is not a trivial extension of an M-McCoy.
Theorem 2.3
Let M be a monoid with . Then the following conditions are equivalent:
(1) | R is nil-M-McCoy. | ||||
(2) |
|
Proof
In a similar way, proposition 2.12 (Nikmehr, Fatahi, & Amraei, Citation2011). It is easy to see that there exists an isomorphism of rings
defined
Suppose that and
are such that
, where
. We claim there exists
such that
for each i. Assume that
and let and
. Also by observing that
thus, we have for each
. Since R is a nil-M-McCoy ring, there exists some positive integer
such that
for any s and any i. Let
. Then
and so
. Therefore,
is nil-M-McCoy.
Suppose that
is nil-M-McCoy. Note that R is isomorphic to the subring
of . Thus, R is nil-M-McCoy since each sub ring of a nil-M-McCoy ring is also nil-M-McCoy.
Let R be a ring and let
and
and T(R, R) be the trivial extension of R by R. Using the same method in the proof of Theorem 2.3, we have the following results:
Corollary 2.1
Let M be a monoid with . Then the following conditions are equivalent:
(1) | R is nil-M-McCoy; | ||||
(2) |
| ||||
(3) | T(R, n) is nil-M-McCoy; | ||||
(4) | T(R, R) is nil-M-McCoy; | ||||
(5) |
|
Proof
Using the same method in the proof of Theorem 2.3 we have ,
and
. It is easy to see that T(R, n) is a sub ring of the triangular matrix rings, with matrix addition and multiplication. We can denote elements of T(R, n) by
, then T(R, n) is a ring with addition point-wise and multiplication given by
for each On the other hand, there is a ring isomorphism
, since by,
, with
,
. So
, where R[x] is the ring of polynomial in an indeterminate x and
is the ideal generated by
. Therefore
.Thus by similarly method we have
. Therefore all conditions are equivalent.
Let R be a ring and M a monoid. Let . The
is a subring of
full matrix ring
under usual addition and multiplication. In fact,
possesses the similar form of both the ring of all lower triangular matrices and the ring of all upper triangular matrices. A natural problem asks if the nil-M-McCoy property of such subring of
coincides with that of R. This inspires us to consider the nil-M-McCoy property of
.
Theorem 2.4
Let M be a monoid with . Then the following conditions are equivalent:
(1) | R is nil-M-McCoy; | ||||
(2) |
|
Proof
We first show that
Suppose that
, and m is a positive integer such that
. Then
. Hence,
Now assume that Then there exists some positive integer m such that
. Hence
, and so
Therefore, . Then by analogy with the proof of Theorem 2.4, we can show that
is nil-M-McCoy.
it is trivial (see Hashemi, Citation2013).
In the proof of the next proposition we will need the following lemma.
Lemma 2.4
Zhao et al. (Citation2012, Lemma 2.7) Let R be a semicommutative ring, and be in R[x]. If
, then
.
Proposition 2.3
Semicommutative rings are nil-M-McCoy rings.
Proof
Let ,
with
, then we have
. It follows that
by Lemma 2.4. Hence, there exists
for some
such that
with
. This implies that R is a right nil-M-McCoy. Similarly, we can show that R is left nil-M-McCoy. Therefore, R is a nil-M-McCoy.
We now have the following description of the rings which shows one way to give more nil-M-McCoy rings from old ones.
Proposition 2.4
Let be an index set and
a family of rings. If
, then R is right nil-M-McCoy if and only if every
is right nil-M-McCoy for each
.
Proof
It is straightforward to verify that if R is right nil-M-McCoy, then every is right nil-M-McCoy for each I. Conversely, if
for
,
}, where
,
. For each
, let
,
, then
. Since
there exists some index J with
. In particular, there exists some nonzero
with
for all
by the nil-M-McCoy property of
. Fix
, and take r to be the sequence with
in the
coordinate and zero elsewhere. Clearly
and
.
Corollary 2.2
A finite direct product of right nil-M-McCoy rings is right nil-M-McCoy.
Theorem 2.5
For any monoid M. Then we have the following statements:
(1) | nil-M-Armendariz rings are nil-M-McCoy; | ||||
(2) | M-McCoy rings are nil-M-McCoy; | ||||
(3) | M-Armendariz rings are nil-M-McCoy. |
Proof
(1) Let R be a nil-M-Armendariz rings and ,
satisfy
. Then
for each i, j. Since
and
, for
,
there exists
,
. Hence,
and
. Therefore, R is nil-M-McCoy.
(2) It follows easily form the definition.
(3) It is easy to see that each M-Armendariz rings is M-McCoy and therefore nil-M-McCoy by (2).
Let be a ring, for each
, and let
and
be the subring generated by
and
. Then we have the following result (see Alhevaz & Moussavi, Citation2010).
Proposition 2.5
Let be a ring,
and
. Then R is right nil-M-McCoy if and only if each
is right nil-M-McCoy if and only if S is right nil-M-McCoy.
Proof
Let each be a right nil-M-McCoy ring and
and
such that
, where
and
. If there exists
such that
, for each
, then we have
, where
. Now, suppose for each
, there exists
such that
. Since
, there exists
and
such that
. Consider
and
. We have
. Thus, there exists some nonzero
such that
, for each
. Therefore,
, for each
, where
, and so R is right nil-M-McCoy.
Conversely, suppose R is right nil-M-McCoy, ,
and
such that
. Let
and
. So there exists
and
clearly,
. Thus, we have
and so
is right nil-M-McCoy. It is easy to see that S is right nil-M-McCoy if and only if each
is right nil-M-McCoy.
Let be an ordered monoid. If for any
,
implies that
and
, then
is called a strictly totally ordered monoid.
Corollary 2.3
Let M be a strictly totally ordered monoid and R a reversible ring. Then R is nil-M-McCoy.
It was shown in Liu (Citation2005, Proposition 1.4), that if M is strictly totally ordered monoid and I is a reduced ideal of R such that R / I is an M-Armendariz ring, then R is M-Armendariz. The following result generalizes this.
Theorem 2.6
Let M be a strictly totally ordered monoid and I an ideal of R. If I is semicommutative (as a ring without identity) and R / I is nil-M-McCoy, then R is nil-M-McCoy.
Proof
Let ,
be such that
and
,
. We will use transfinite induction on the strictly totally ordered set
to show that
for some nonzero
and for each i. Note that in (R / I)[M],
. The fact that R / I is nil-M-McCoy means that there exists r in R such that
thus, there exists
such that
for each i. If there exists
and
such that
, then
and
. If
, then
, a contradiction. Thus,
. Similarly,
. Therefore
for some nonzero
and for each i.
Now suppose that is such that
for each
and
with
. Set
. Then X is a finite set. We write X as
such that
. Since M is cancellative,
and
imply
. Since
and
, we have
. Thus
.
Now . For any
,
, and thus by induction hypothesis, we have
. For
, let
. Then
. Thus
Since
and I is semicommutative, it follows that
that procedure yields that . Thus
.
Since and
, we have
. Similarly one can show that
and
, for
.
Since and
and I is semicommutative, we have
Multiplying (1) on the right side by and on the left side by
, then
Similarly one can show that
for each and
. Since
, there exists
such that
. Clearly,
equal to sums of such elements
, where
for each t. Then
where and
. Multiplying Equation (2) on the right side by
, we have
where and
, since nil(I) is an ideal of I by Lunqun and Jinwang (Citation2013, Lemma 3.1). Hence
.
Since , by analogy with the above proof we have that
for each
. Since
and
are nilpotent, there exists
such that
. Then
. Since
and I is semicommutative, we have
. Thus
. Hence
for each
. By analogy with the above proof we have
, where
and
. Since
, we have
where ,
and
. Multiplying Equation (3) on the right side by
, then
where
,
and
. Therefore
. Similarly one can show that
are nilpotent. Then
for some nonzero
and for each i. This implies that R is a right nil-M-McCoy. Similarly, we can show that R is left nil-M-McCoy. Therefore, R is a nil-M-McCoy.
The following example shows that the condition R / I is a nil-M-McCoy ring in Theorem 2.6 is not superfluous.
Example 2.5
Let , and let F be any field and
. Then
is a semicommutative ideal of R, but
is not nil-M-McCoy ring. Let
and
. Then
, but if
and
, for each i,j then clearly
. Therefore, R is not right nil-M-McCoy, and hence it is not nil-M-McCoy.
The following lemma shows that the condition M is an "u.p."-monoid in Theorem 2.7 is not superfluous.
Lemma 2.5
Let M be a cyclic group of order and R any NI ring. Then R is not nil-M-McCoy.
Proof
Suppose that . Let
and
. Then
. Therefore, R is not nil-M-McCoy, whereas R is NI ring.
A ring R is a subdirect sum of a family of rings if there is a surjective homomorphism, where
is the
projection.
Now we consider the case of subdirect sum of nil-M-McCoy.
Proposition 2.6
If R is a subdirect sum of nil-M-McCoy then R is nil-M-McCoy.
Proof
Let for each
be ideals of R and for them ring
, is nil-M-McCoy and let
. Let
and
such that
. Since
, for each k, is nil-M-McCoy then we have
. Now let
, therefore
. Since
, for each i. Hence, R is nil-M-McCoy.
The ring of Laurent polynomials in x with coefficients in a ring R, consists of all formal sums with obvious addition and multiplication, where
and k, n are (possibly negative) integers, denoted by
. We finish this paper with the following corollary.
Corollary 2.4
Let R be a semicommutative ring. Then R is nil--McCoy, for any
,
, if
, then there exist
such that
and
for each
and
.
Proof
Note that (see Alhevaz, Moussavi, & Habibi, Citation2012).
Additional information
Funding
Notes on contributors
Vahid Aghapouramin
Vahid Aghapouramin is currently a PhD student at the department of mathematics, Karaj Branch, Islamic Azad university, Karaj, Iran. His research interests are pure mathematics, Commutative Algebra, Noncommutative Algebra.
Mohammad Javad Nikmehr
Mohammad Javad Nikmehr is a associate professor, Faculty of Mathematics, K.N. Toosi, University of Technology, P.O. Box 16315-1618, Tehran, Iran. His research interest are Commutative Algebra, Graph Theory, Non-commutative Algebra, Algebraic Combinatorics.
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