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Research Article

Application of measures of noncompactness to the system of integral equations

ORCID Icon & | (Reviewing editor)
Article: 1702860 | Received 30 Aug 2019, Accepted 05 Dec 2019, Published online: 23 Dec 2019

Abstract

In this paper, by applying a measure of noncompactness in the space L(ℝn) and a new generalization of Darbo fixed point theorem, we study the existence of solutions for a class of the system of integral equations. Our main result is more general than the main result of [2]. Finally, an example is presented to show the usefulness of the outcome.

PUBLIC INTEREST STATEMENT

Metric fixed point theory is a powerful tool for solving many problems in various parts of mathematics and its applications. In particular, the technique of measure of noncompactness is a very useful tool for studying the existing solutions o integral equations .In this paper, by applying the technique of measure of noncompactness, we study the existence of solutions for a class of the system of integral equations.

1. Introduction

The technique of measure of noncompactness is the main tool to solvability of several types of integral equations, see, for example, (Aghajani, Mursaleen, & Shole Haghighi, Citation2015; Darwish, Citation2008; Das, Hazarika, & Mursaleen, Citation2017; Dhage & Bellale, Citation2008; Hazarika, Arab, & Mursaleen, Citation2019; Liu, Guo, Wu, & Wu, Citation2005; Mohiuddine, Srivastava, & Alotaibi, Citation2016; Mursaleen & Mohiuddine, Citation2012; Mursaleen & SYED, Citation2016; Olszowy, Citation1980; Srivastava, Das, Hazarika, & Mohiuddine, Citation2018; Srivastava, Das, Hazarika,S, & Mohiuddine, Citation2019). Besides, it has been frequently applied in several branches of nonlinear analysis. The first measure of noncompactness was introduced by Kuratowski (Kuratowski, Citation1934). The most important fixed point theorem of this measure was introduced by Darbo (Darbo, Citation1955). In the last years, authors have applied this result to establish the existence and uniqueness of solutions for integral equations in Banach spaces. The space L(Rn) is one of the most important spaces where several integral equations have been solved in this apace. The additional advantage of this space depends on the fact that the functions of the space L(Rn) are not necessary to be continuous. Allahyari (Allahyari, Citation2018) introduced the construction of the measure of noncompactness on the space L(Rn) and studied the existence of solutions for a class of nonlinear functional integral equations of Urysohn type. The aim of this paper is to study the existence of solutions for a class of the system of integral equations of the form

(1.1) μ(x)=Fx,h(x,u(x),v(x))ΩRng(x,y,u(ξ(y)),v(ξ(y)))dy,(Tu)(x)0V(t,s,u(x))ds,v(x)=Fx,h(x,v(x),u(x))ΩRng(x,y,v(ξ(y)),u(ξ(y)))dy,(Tv)(x)0V(t,s,v(x))ds.(1.1)

The above system of integral equations is more general than the integral equation studied by Allahyari (Citation2018).

2. Preliminaries

Here, we recall some facts which will be used in our main results. Let E be a real Banach space with norm . and zero element θ. Besides, we suppose X and Convc(X) denote the closure and convex hull of X, respectively. Moreover, let us denote by ME the family of all nonempty and bounded subsets of E and by NE its subfamily consisting of all relatively compact sets.

Definition 2.1 ((Bannas & Goebel, Citation1980)). A mapping μ:MER+ is said to be a measure of noncompactness in E if it satisfies the following conditions:

The family kerμ=XME:μ(X)=0 is nonempty and kerμNE.

XYμ(X)μ(Y).

μ(X)=μ(X).

μ(ConvX)=μ(X).

μ(λX+(1λ)Y)λμ(X)+(1λ)μ(Y), for λ[0,1].

If {Xn} is a sequence of closed sets from ME such that Xn+1Xn, for n=1,2, and if limnμ(Xn)=0 then X=n=1Xn.

The following theorem is basic for our main result.

Theorem 2.2 (Darbo (Darbo, Citation1955)). Let C be a nonempty, bounded, closed and convex subset of a Banach space E and T: C C be a continuous mapping. Assume that there exists a constant K[0,1) such that μ(TX)Kμ(X) for any nonempty subset X of C, where μ is a (M.N.C) defined in E. Then T has at least a fixed point in C.

Definition 2.3. (Bhaskar & Lakshmikantham, Citation2006) An element (x,y)X×X is called coupled fixed point of the mapping F:X×XX if F(x,y)=x and F(y,x)=y.

Theorem 2.4. (Aghajani & Allahyari, Citation2014) Suppose μ1,μ2,,μn are measures of noncompactness in Banach spaces E1,E2,,En respectively. Moreover assume that the function F:R+nR+ is convex and F(x1,,xn)=0 if and only if xi=0 for i=1,2,,n. Then

μ˜(X)=F(μ1(X1),μ2(X2),,μn(Xn)),

defines a measure of noncompactness in E1×E2××En where Xi denotes the natural projection of X into Ei, for i=1,2,,n.

Samadi (Samadi, Citation2018) obtained the following result.

Theorem 2.5. Let C be a nonempty bounded, closed and convex subset of a Banach space E. Assume T:C×CC be a continuous operator satisfying

(2.2) θ(μ(T(X1×X2)))+f(μ(T(X1×X2)))f(μ(X1)+μ(X2))(2.2)

for all nonempty subsets X1,X2C, where μ is an arbitrary measure of noncompactness defined in E and (θ,f)Δ. Then T has at least a coupled fixed point.

Let L(Rn) denote the space of all Lebesgue measurable functions on Rn with the standard norm

f=inf{C > 0:|f(t)|Ca.e.onRn}.

The function f:ΩR is said to belong to Lloc(Rn) if fχKL(Ω) for every compact set K contained in Ω, where Ω is an open subset of Rn. Allahyari (Allahyari, Citation2018) proved the following theorems to characterize the compact subsets of L(Rn).

Theorem 2.6. Let B be a bounded set in L(Rn). Then B is relatively compact if the following conditions are satisfied:

(i) limh0τ hffL(BˉT)=0 uniformly with respect to fB for any T > 0, where τhf(x)=f(x+h).

(ii) For ε > 0 there is some T > 0 so that for every f,gB

We recall the Euclidean norm on the space Rn to be

x∥=i=1n(xi2)12,

for x=(x1,x2,,xn).

Theorem 2.7 ((Allahyari, Citation2018)). Let B be a bounded set in L(BˉT). Then B is relatively compact if and only if

(2.3) limh0τhffL(BˉT)=0(2.3)

uniformly with respect to fB, where τ hf(x)=f(x+h).

Now we recall the definition of a measure of noncompactness in L(Rn) which has been presented in (Allahyari, Citation2018).

Suppose X be a bounded subset of the space L(Rn). For xX and ε > 0. Let us denote

ωT(f,ε)=sup{τ hffL(BˉT):∥h < ε},ωT(X,ε)=sup{ωT(f,ε):fX},ωT(X)=limε0ωT(X,ε),ω(X)=limTωT(X),

and

d(X)=limTsup{fgL(RnBˉT):f,gX},ω0(X)=ω(X)+d(X).

From (Allahyari, Citation2018) we know that ω0 is a measure of noncompactness in the space L(Rn).

The following definition will be used in the next section.

Definition 2.8. A function f:Ω×RnR is said to have the Caratheodory conditions if

(i) for all uRn the function xf(x,u) is measurable on Ω.

(ii) for almost all xRn the function uf(x,u) is continuous on Rn

3. Application

In this section, as an application of Theorem 2.5, we study the solvability ofEquation (1.1) on the space L(Ω). We need the following conditions:

(H1) ξ:ΩΩ is a measurable function (ΩRn).

(H2) F:Ω×R×RR satisfies the Caratheodory conditions and F(.,0,0)L(Rn). Besides, there exist positive real numbers τ > 0 such that

|F(x,u1,v1)F(x,u2,v2)|eτ(|u1u2|+|v1v2|)a.e.xΩ.

(H3) g:Ω×Ω×R×RR satisfies the Caratheodory conditions, gLloc(Ω×Ω×R×R) and there exists nondecreasing function b:R+R+ such that for all r > 0 and u,vL(Ω) with ur,vr we have

(3.4) esssupxΩ|h(x,u(x),v(x))||Ωg(x,y,u(ξ(y)),v(ξ(y)))dy|b(r).(3.4)

Besides, for all rR+

limTesssupx > TΩg(x,y,u(ξ(y)),v(ξ(y)))dyg(x,y,v(ξ(y)),u(ξ(y)))dy=0

uniformly with respect to u,vL(Ω) such that uvr. Moreover, we have

limTesssupxΩΩBT|g(x,y,u(ξ(y)),v(ξ(y)))|dy=0.

(H4) T:L(Rn)L(Rn) is a continuous operator such that

|(Tu)(x)||u(x)|,|(Tu)(x)(Tv)(x)||u(x)v(x)|,|(Tu)(x1)(Tu)(x2)||u(x1)u(x2)|,

for all u,vL(Rn) and x1,x2,xRn.

(H5) V:R+×R+×RR is a continuous function and there exists a continuous function k:R+×R+R+ such that the function sk(t,s) is integrable over R+ and the following conditions hold:

|V(t,s,x)|k(t,s)||x|,|V(t,s,x)|V(t,s,y)|k(t,s)|xy|,

for all t,sR+ and x,yR. Moreover, assume that

M=suptR+0k(t,s)ds.

(H6) h:Ω×R×RR satisfies the Caratheodory conditions and h(.,0,0)L(Rn). Besides, there exists positive real number τ > 0 such that

|h(x,x1,x2)h(x,y1,y2)|eτ(|x1y1|+|x2y2|),a.eonxΩ.

(H7) There exists a positive solution r0 of the inequality

eττbr+Meτr2+F.,0,0r

Theorem 3.1. Under the assumptions (H1)(H7), Equation (1.1) has at least one solution in the space L(Ω)×L(Ω).

Proof. Let us define the operator G on the space L(Ω)×L(Ω) by

G(u,v)(x)=Fx,h(x,u(x),v(x))ΩRng(x,y,u(ξ(y)),v(ξ(y)))dy,(Tu)(x)0V(t,s,u(x))ds.

The space L(Ω)×L(Ω) is equipped with the norm

(x,y)∥=∥x+y.

We prove that G(Br0×Br0)Br0. Since the function F satisfies the Caratheodory conditions, so G(u,v) is measurable for any u,vL(Ω). In view of our assumptions, we obtain the following inequality

|G(u,v)(x)||F(x,h(x,u(x),v(x))Ωg(x,y,u(ξ(y)),v(ξ(y)))dy,(Tu)(x)0V(t,s,u(x))ds)F(x,0,0)|+|F(x,0,0)|eτ|h(x,u(x),v(x))ΩRng(x,y,u(ξ(y)),v(ξ(y)))dy|+eτ|(Tu)(x)0V(t,s,u(x))ds|+|F(x,0,0)|eτb(u)+eτu2M+F(.,0,0).

Accordingly,

(3.5) G(u,v)eτb(u)+eτu2M+F(.,0,0).(3.5)

Consequently, from (3.5) and condition (H7) we infer that G(Br0×Br0)Br0. Now we prove that the operator G is contnuous on Br0×Br0. To do so, let us ε > 0 and take arbitrary (x,y),(u,v)Br0×Br0 such that (u1,v1)(u2,v2)Br0×Br0 < ε. Thus, we have

(3.6) |G(u1,v1)(x)G(u2,v2)(x)|eτ|h(x,u1(x),v1(x))||Ωg(x,y,u1(ξ(y)),v1(ξ(y)))g(x,y,u2(ξ(y)),v2(ξ(y)))dy|+eτ|h(x,u1(x),v1(x))h(x,u2(x),v2(x))||Ωg(x,y,u2(ξ(y)),v2(ξ(y)))dy|+eτ|(Tu1)(x)||0V(t,s,u1(x))V(t,s,u2(x))ds|+eτ|(Tu1)(x)(Tu2)(x)||0V(t,s,u2(x))ds|(e2τu1+e2τv1)BT|g(x,y,u1(ξ(y)),v1(ξ(y)))g(x,y,u2(ξ(y)),v2(ξ(y)))|dy+(e2τu1+e2τv1)ΩBT|g(x,y,u1(ξ(y)),v1(ξ(y)))g(x,y,u2(ξ(y)),v2(ξ(y)))|dy+e2τh(x,0,0)BT|g(x,y,u1(ξ(y)),v1(ξ(y)))g(x,y,u2(ξ(y)),v2(ξ(y)))|dy+e2τh(x,0,0)ΩBT|g(x,y,u1(ξ(y)),v1(ξ(y)))g(x,y,u2(ξ(y)),v2(ξ(y)))|dy+eτMu1u1u2+eτu1u2Mu2(e2τu1+e2τv1)m(BT)ω(ε)+(e2τu1+e2τv1)2esssupxΩΩBT|g(x,y,u1(ξ(y)),v1(ξ(y)))|dy+e2τh(x,0,0)m(BT)ω(ε)+e2τh(x,0,0)2esssupxΩΩBT||g(x,y,u1(ξ(y)),v1(ξ(y)))|dy+eτu1)Mu1u2+eτu1u2Mu2(3.6)

By applying condition (H3), there exist T1,T2 > 0 such that for T=max{T1,T2} we have

(3.7) esssupx > TΩg(x,y,u1(ξ(y)),v1(ξ(y)))g(x,y,v1(ξ(y)),u1(ξ(y)))dy < ε,esssupxΩΩBT|g(x,y,u(ξ(y)),v(ξ(y)))|dy < ε.(3.7)

From (3.6), we have

(3.8) esssupx > T|G(u1,v1)(x)G(u2,v2)(x)|(e2τu1+e2τv1)ε+e2τh(x,0,0)ε+eτMu1)ε+eτu2Mε(3.8)

Now for almost all xBTΩ, we have

(3.9) |G(u1,v1)(x)G(u2,v2)(x)|(e2τu1+e2τv1)m(BT)ω(ε)+(e2τu1+e2τv1)2esssupxΩΩBTg(x,y,u1(ξ(y)),v1(ξ(y)))dy+e2τh(x,0,0)m(BT)ω(ε)+e2τh(x,0,0)2esssupxΩΩBTg(x,y,u1(ξ(y)),v1(ξ(y)))dy+eτu1Mε+eτu2Mε(3.9)

where

ω(ε)=inf{C0:|g(x,y,u1,v1)g(x,y,u2,v2)|Ca.eonxBTΩ,yBTΩ,u1,v1,u2,v2[r0,r0],|u1v1|<ε,|u2v2|<ε

Now by applying the Caratheodory conditions for g on the compact set BT×BT×[r0,r0]×[r0,r0] and Theorem 2.7, we infer that ω(ε)0 as ε0. Combining (7), (8) and (9) we conclude that G is continuous on Br0×Br0. Now we prove that for any X1,X2Br0 we have

θ(μ(G(X1×X2)))+f(μ(G(X1×X2)))f(μ(X1)×μ(X2)).

To do so, assume that T > 0 and ε > 0 are arbitrary constants. Hence, for almost all xΩ, h∥≤ε and (u,v)X1×X2, we have

(3.10) |G(u,v)(x)G(u,v)(x+h)||F(x,h(x,u(x),v(x))Ωg(x,y,u(ξ(y)),v(ξ(y)))dy,(Tu)(x)0V(t,s,u(x))ds)F(x+h,h(x,u(x),v(x))Ωg(x,y,u(ξ(y)),v(ξ(y)))dy,(Tu)(x)0V(t,s,u(x))ds)|+|F(x+h,h(x,u(x),v(x))Ωg(x,y,u(ξ(y)),v(ξ(y)))dy,(Tu)(x)0V(t,s,u(x))ds)F(x+h,h(x+h,u(x+h),v(x+h))Ωg(x+h,y,u(ξ(y)),v(ξ(y)))dy,(Tu)(x+h)0V(t,s,u(x+h))ds)|ωr0T(F,ε)+eτ|h(x,u(x),v(x))Ωg(x,y,u(ξ(y)),v(ξ(y)))dyh(x+h,u(x+h))Ωg(x+h,y,u(ξ(y)),v(ξ(y)))dy|+eτ|(Tu)(x)0V(t,s,u(x))ds(Tu)(x+h)0V(t,s,u(x+h))ds|ωr0T(F,ε)+eτωr0T(h,ε)|BTg(x,y,u(ξ(y)),v(ξ(y)))g(x+h,y,uξ(y)),vξ(y)))dy|+eτωr0T(h,ε)|ΩBTg(x,y,u(ξ(y)),v(ξ(y)))g(x+h,y,u(ξ(y)),v(ξ(y)))dy|+eτ|(Tu)(x)||0V(t,s,u(x))V(t,s,u(x+h))ds|+eτ|(Tu)(x)(Tu)(x+h)||0V(t,s,u(x+h))ds|ωr0T(F,ε)+eτωr0T(h,ε)m(BT)ωr0T(g,ε)+eτωr0T(h,ε)2esssup|ΩBTg(x,y,u(ξ(y)))dy|+eτωT(u,ε)uM+eτMωT(u,ε)u,(3.10)

where

ωr0T(h,ε)=inf{C0:|h(x,u,v)h(x+h,v,v)|Ca.eonxBT,h∥≤ε,u∥≤r0,v∥≤r0},
ωr0T(F,ε)=inf{C0:|F(x,u,v)F(x+h,u,v)|Ca.eonxBT,h∥≤ε,|u|b(r0),|v| < Mr02},
ωr0T(g,ε)=inf{C0:|g(x,y,u,v)g(x+h,y,u,v)|Ca.eonxBTΩ,yBTΩ,h∥≤ε,|v| < r0,|u|r0}.

Thus, we have

(3.11) ωT(G(X1×X2),ε)ωr0T(F,ε)+eτωr0T(h,ε)m(BT)ωr0T(g,ε)+eτωr0T(h,ε)2esssupΩBTg(x,y,u(ξ(y))),v(ξ(y)))dy|+eτωT(X1,ε)uM+e\tauMωT(X1,ε)u,(3.11)

The functions F, g and h satisfy the Caratheodory conditions on the compact set BT×[b(r0),b(r0)]×[Mr02,Mr02], BT×BT×[r0,r0]×[r0,r0] and BT×[r0,r0]×[r0,r0], respectively. So, ωr0T(F,ε)0, ωr0T(g,ε)0 and ωr0T(h,ε)0 as ε0. Accordingly, thanks to our assumptions, we have

(3.12) ωT(G(X1×X2))eτr0MωT(X1,ε)+eτMr0ωT(X1,ε).(3.12)

Taking T we get

(3.13) ω(G(X1×X2)2eτMr0(ω0(X1)+ω0(X2))(3.13)

Moreover, for all (u1,v1),(u2,v2)X1×X2, we have

(3.14) esssupx > T|G(u1,v1)(x)G(u2,v2)(x)|eτ|h(x,u1(x),v1(x))Ωg(x,y,u1(ξ(y)),v1(ξ(y)))dyh(x,u2(x),v2(x))Ωg(x,y,u2(ξ(y)),v2(ξ(y)))dy|+eτ|(Tu1)(x)0V(t,s,u1(x))ds(Tu2)(x)0V(t,s,u2(x))ds|(3.14)

Consequently,

(3.15) G(u1,v1)G(u2,v2)L(ΩBT)|h(x,u1(x),v1(x))|esssupx > TΩ|g(x,y,u1(ξ(y)),v1(ξ(y)))g(x,y,u2(ξ(y)),v2(ξ(y)))|dy+|h(x,u1(x),v1(x))h(x,u2(x),v2(x))|esssupx > TΩ|g(x,y,u2(ξ(y)),v2(ξ(y)))|dy+eτMr0|u1(x)u2(x)|+eτMr0|u1(x)u2(x)|(3.15)

Hence,

G(u1,v1)G(u2,v2)L(ΩBT¯)|h(x,u1(x),v1(x))|esssupxTΩg(x,y,u1(ξ(y)),v1(ξ(y)))
g(x,y,u2(ξ(y)),v2(ξ(y)))dy+|h(x,u1(x),v1(x))h(x,u2(x),v2(x))|esssupx > TΩ|g(x,y,u2(ξ(y)),v2(ξ(y)))|dy
(3.16) +eτMr0(eτMr0u1u2L(ΩBT¯)+eτMr0|u1(x)u2(x)|L(ΩBT¯)(3.16)

By applying assumption (H3) and taking T, we have

(3.17) d(G(X1×X2))2Mr0eτ(d(X1)+d(X2)).(3.17)

Since 2Mr0 < 1, by combining (3.13) and (3.17), we get

ω(G(X1×X2))+d(G(X1×X2))
eτ(ω(X1)+ω(X2)+d(X1)+d(X2))).

By passing to logarithms, we get

(3.18) τ+ln(ω0(G(X1×X2)))ln(ω0(X1×X2)))(3.18)

Now applying Theorem 2.5 with f(t)=ln(t) and θ(t)=τ, we obtain that there exists u,vL(Ω) such that

(3.19) u(x)=F(x,h(x,u(x),v(x))ΩRng(x,y,u(ξ(y)),v(ξ(y)))dy,(Tu)(x)0V(t,s,u(x))ds),v(x)=F(x,h(x,v(x),u(x))ΩRng(x,y,v(ξ(y)),u(ξ(y)))dy,(Tv)(x)0V(t,s,v(x))ds).(3.19)

Example 3.2. Now, we study the following system of integral equations:

(3.20) u(x)=ex1x2x3τsineτx1x2x3sin|u(x)|+|v(x)|×R2arctane3(|x2|+|y2|)|u(y)||v(y)|8+|y1|+|x1|+cos|u(x)|1+|u(x)|0es1+t8sin|u(x)|8ds,v(x)=ex1x2x3τsineτx1x2x3sin|u(x)|+|v(x)|×R2arctane3(|x2|+|y2|)|u(y)||v(y)|8+|y1|+|x1|+cos|v(x)|1+|v(x)|0es1+t8sin|v(x)|8ds(3.20)

Equation (3.20) is a special case of the functional integral Equation (1.1), where

(3.22) F(x,u,v) =ex1x2x3τsinu+v,g(x1,x2,x3,y1,y2,u)=arctane3(|x2|+|y2|)|u||v|8+|y1|+|x1|,h(x1,x2,x3,u,v)=ex1x2x3τsin|u|+|v|,(Tu)(x)  =cos|u(x)|1+|u(x)|,ξ(y1,y2) =(y1,y2,0),(3.22)
V(t,s,x)=es8(1+t8)sin(|x|8),(Ω=3,Ω=2)

It easily seen that the functions ξ and F satisfy the assumptions (H1) and (H2) respectively. On the other hand gLloc(R3×R2×R×R) such that for all uL(R3) we have

(3.23) esssupxR3R2g(x,y,u(ξ(y)))dy=esssupxR3R2arctane3(|x2|+|y2|)|u(y)||v(y)|8+|y1|+|x1|dyesssupxR3e|x2|8+|x1|18=b(r)(3.23)

Moreover, for all rR+ we have

limTesssupx > TR2arctane3(|x2|+|y2|)|u(y)|8+|y1|+|x1|arctane3(|x2|+|y2|)|v(y)|8+|y1|+|x1|dy=0

uniformly with respect to x,yL(R3) such that xyr. Moreover,

limTesssupx3 |2BT¯arctan(e3(|x2|+|y2|)|u(y)||v(y)|8+|y1|+|x1|)dy=0.

Hence condition (H3) is satisfied. In this example (Tx)(t)=cos|x(t)|1+|x(t)| verifies assumption (H4). Now notice that the function V is continuous and satisfies the assumption (H5) with k(t,s)=es8(1+t8) and M=18. On the hand obviously the assumption (H6) holds. Finally, the existing inequalities in the assumption (H7) have the form

eτ8+eτ8r2r

It is easily seen that the last inequality has a positive solution. For example r0=1. So, 2Mr02 < 1 We see that all assumptions of Theorem 3.1 are satisfied. Consequently, from Theorem 3.1 the integral equation (11) has a solution in the space L(R3).

Additional information

Funding

This work was supported by the Islamic Azad University [1534189084]

Notes on contributors

Ayub Samadi

The research field of authors is fixed point theory with its applications. They are assistant professors and faculty members in Islamic Azad University. The authors have studied the existence of solutions for a class of the systems of integral equations. Also, they give an application of the obtained results. They applied the technique of measure of noncompactness in the main results.

References

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