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- Condition (1.17) implies ∥H(t)B∥ dt<∞, see also the Appendix
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- Ibid., Appendix, where a new proof appears of a result of Allan, Bochner and Phillips. See Ref. 29 for the references to the latter work
- Note the following:[(I-L+)f](x) = e-xT −1Q+h(x>0) for some hϵD(T), if and only if f(0)ϵRan X+xD(T) and Q+f(0) = Q+h. So Q+h = f(0)-Q−f(0) belongs to [X++Ran Q] xD(T). Further, if (l-L+)f=0, then f(x)ϵD(T), and thus both f(Ō)ϵX+n D(T) and Q+f(0) = 0. So f (0)EX+x Ran Q− ⊆ D(T)
- van der Mee , C. V. M. 1983 . Int. Eqs. Oper. Theor. , 6 : 405
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- A reduction of this kind appeared before in Refs. 3,4 and 33
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