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- The mol of 4a in the mixture of 4a and 4b was determined as follows: The area under the multiplet at 2.70 ppm (assigned to CH of 4a and 4b) was set to unity and the area under the triplet at 2.26 ppm (assigned to the CH2NH2, of 4a) was found to be z as determined by the 1H NMR integration of the distilled mixture of 4a and 4b. Hence the ratio mol 4a/mol 4b = 22/3z(1-z) can be calculated. Letting x and y equal the weight in g of 4a and the weight in g of 4b in the mixture, respectively, we have that the mole ratio 4a/4b is also 230y/272x where the molecular weights of 4a and 4b are 230 and 272 g/mol, respectively. Since the total weight of the mixture is known, the simultaneous equations provide the solution for x and y from which the total volume of hexanes in mL is {(mol of 4a/0.32 M) - (g of 4b)/ 0.92} where the density of 4b = ∼ 0.92 g/mL.